求计算器的c语言程序代码,大神,求51单片机做简易计算器的那个c语言程序

大神,求51单片机做简易计算器的那个c语言程序

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解决时间 2021-02-07 09:17

提问者心魅

2021-02-06 12:27

大神,求51单片机做简易计算器的那个c语言程序

最佳答案

二级知识专家相忘于江湖

2021-02-06 13:02

以下是我编的简易计算器程序,基本成功

//4*4键盘检测程序,按下键后相应的代码显示在液晶屏上

//显示5位后,第6次显示操作符号

//再显示下一个数

// 键值与功能对应表

//键值 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

//功能 0 1 2 3 4 5 6 7 8 9 + - × ÷ = 清零

#include

sbit beep=P2^3;

sbit lcden=P3^4;

sbit rs=P3^5;

sbit rw=P3^6;

#define uint unsigned int

#define ulint unsigned long int

#define uchar unsigned char

#define lcddata P0

ulint bb,dd,ee,ff;

uchar d,flag1;

uchar fd1,fd2;

uchar b1=16,b2=16,b3=16,b4=16,b5=16;

uchar d1=16,d2=16,d3=16,d4=16,d5=16;

uchar f1=16,f2=16,f3=16,f4=16,f5=16,f6=16,f7=16,f8=16,f9=16,f10=16;

uchar key,keyval,c,temp;

void Delay1ms(uint i) //1ms延时程序

{

uint j;

for(;i>0;i--)

{

for(j=0;j<125;j++)

{;}

}

}

void write_com(uchar com)

{

lcddata=com;

rs=0;

rw = 0;

lcden=0;

Delay1ms(10);

lcden=1;

Delay1ms(10);

lcden=0;

}

void write_date(uchar date)

{

lcddata=date;

rs=1;

rw=0;

lcden=0;

Delay1ms(10);

lcden=1;

Delay1ms(10);

lcden=0;

}

void init2()

{

rw=0;

write_com(0x38);

Delay1ms(10);

write_com(0x0f);

Delay1ms(10);

write_com(0x06);

Delay1ms(10);

write_com(0x01);

Delay1ms(10);

}

void display1(uchar A1,uchar A2,uchar A3,uchar A4,uchar A5) //第1个数显示程序

{

init2();

write_com(0x80);//第1行,第1字

Delay1ms(10);

write_date(0x30+A1);

Delay1ms(10);

write_date(0x30+A2);

Delay1ms(10);

write_date(0x30+A3);

Delay1ms(10);

write_date(0x30+A4);

Delay1ms(10);

write_date(0x30+A5);

Delay1ms(10);

}

void display2(uchar A1,uchar A2,uchar A3,uchar A4,uchar A5) //第2个数显示程序

{

write_com(0x88);//第1行,第1字

Delay1ms(10);

write_date(0x30+A1);

Delay1ms(10);

write_date(0x30+A2);

Delay1ms(10);

write_date(0x30+A3);

Delay1ms(10);

write_date(0x30+A4);

Delay1ms(10);

write_date(0x30+A5);

Delay1ms(10);

}

void display3(uchar a) //操作符号显示程序

{

write_com(0x86);//第1行,第1字

Delay1ms(10);

switch(a)

{

case 10:

write_date('+');

Delay1ms(10);

case 11:

write_date('-');

Delay1ms(10);

case 12:

write_date('x');

Delay1ms(10);

case 13:

write_date('/');

Delay1ms(10);

}

}

void display4(uchar A1,uchar A2,uchar A3,uchar A4,uchar A5,uchar A6,uchar A7,uchar A8,uchar A9,uchar A10,uchar A11,uchar A12) //结果显示程序

{

write_com(0x80+0x40);//第2行,第1字

Delay1ms(10);

if (flag1==0)

{

write_date('-');

}

else write_date('+');

Delay1ms(10);

write_date(0x30+A1);

Delay1ms(10);

write_date(0x30+A2);

Delay1ms(10);

write_date(0x30+A3);

Delay1ms(10);

write_date(0x30+A4);

Delay1ms(10);

write_date(0x30+A5);

Delay1ms(10);

write_date(0x30+A6);

Delay1ms(10);

write_date(0x30+A7);

Delay1ms(10);

write_date(0x30+A8);

Delay1ms(10);

write_date(0x30+A9);

Delay1ms(10);

write_date(0x30+A10);

Delay1ms(10);

write_date('.');

Delay1ms(10);

write_date(0x30+A11);

Delay1ms(10);

write_date(0x30+A12);

Delay1ms(10);

}

uchar keyscan()

{

key=16;

P3=0xef;//P3.7输出1个低电平

temp=P3; //读取

temp=temp&0x0f;//屏蔽高4位

if(temp!=0x0f)

{

Delay1ms(10);

if(temp!=0x0f)

{

temp=P3;

switch(temp)

{

case 0xee:

key=0;

break;

case 0xed:

key=4;

break;

case 0xeb:

key=8;

break;

case 0xe7:

key=12;

break;

}

while(temp!=0x0f)

{

temp=P3;

temp=temp&0x0f;

beep=0;

}

beep=1;

}

}

P3=0xdf;

temp=P3;

temp=temp&0x0f;

if(temp!=0x0f)

{

Delay1ms(10);

if(temp!=0x0f)

{

temp=P3;

switch(temp)

{

case 0xde:

key=1;

break;

case 0xdd:

key=5;

break;

case 0xdb:

key=9;

break;

case 0xd7:

key=13;

break;

}

while(temp!=0x0f)

{

temp=P3;

temp=temp&0x0f;

beep=0;

}

beep=1;

}

}

P3=0xbf;

temp=P3;

temp=temp&0x0f;

if(temp!=0x0f)

{

Delay1ms(10);

if(temp!=0x0f)

{

temp=P3;

switch(temp)

{

case 0xbe:

key=2;

break;

case 0xbd:

key=6;

break;

case 0xbb:

key=10;

break;

case 0xb7:

key=14;

break;

}

while(temp!=0x0f)

{

temp=P3;

temp=temp&0x0f;

beep=0;

}

beep=1;

}

}

P3=0x7f;

temp=P3;

temp=temp&0x0f;

if(temp!=0x0f)

{

Delay1ms(10);

if(temp!=0x0f)

{

temp=P3;

switch(temp)

{

case 0x7e:

key=3;

break;

case 0x7d:

key=7;

break;

case 0x7b:

key=11;

break;

case 0x77:

key=15;

break;

}

while(temp!=0x0f)

{

temp=P3;

temp=temp&0x0f;

beep=0;

}

beep=1;

}

}

return(key);

}

void main()

{ while(1)

{

c=1;

while(c<6)//输入第1个5 位数

{

keyval=keyscan();

if(keyval<10)

{

switch(c)

{

case 1:b1=keyval; break;

case 2:b2=keyval; break;

case 3:b3=keyval; break;

case 4:b4=keyval; break;

case 5:b5=keyval; break;

}

c++;

}

display1(b1,b2,b3,b4,b5);

}

while(c==6) //输入计算符号

{

keyval=keyscan();

if((keyval>=10)&&(keyval<14)) //可去一层括号,因逻辑运算优先级较低

{

d=keyval;

}

c=1;

display3(d);

}

while(c<6) //输入第2个5 位数

{

keyval=keyscan();

if(keyval<10)

{

switch(c)

{

case 1:d1=keyval; break;

case 2:d2=keyval; break;

case 3:d3=keyval; break;

case 4:d4=keyval; break;// 除

case 5:d5=keyval; break;

}

c++;

}

display2(d1,d2,d3,d4,d5);

}

bb=b1*10000+b2*1000+b3*100+b4*10+b5;

dd=d1*10000+d1*1000+d3*100+d4*10+d5;

while(keyval!=14) //等待按下"="

{

keyval=keyscan();

}

Delay1ms(10);

switch(d)

{

case 10:ee=bb+dd; break;//+

case 11:

flag1=1;

if(bb>=dd)

{

ee=bb-dd; //-

flag1=0;

}

else ee=dd-bb;

break;

case 12:ee=bb*dd; break;//*可能会溢出

case 13:ee=bb/dd; //除法小数部分会丢失,保留2位

ff=bb%dd;

fd1=ff*10/dd;

fd2=ff*100/dd%10;

break;

}

f10=ee/1000000000%10;

f9=ee/100000000%10;

f8=ee/10000000%10;

f7=ee/1000000%10;

f6=ee/100000%10;

f5=ee/10000%10;

f4=ee/1000%10;

f3=ee/100%10;

f2=ee/10%10;

f1=ee%10;

display4(f10,f9,f8,f7,f6,f4,f4,f3,f2,f1,fd1,fd2);

while(keyval!=15)

{

keyval=keyscan();

}

b1=0;b2=0;b3=0;b4=0;b5=0;

d1=0;d2=0;d3=0;d4=0;d5=0;

bb=0;dd=0;ee=0;

init2();

}

}

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