LeetCode刷题日记 344. 反转字符串

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一、题目描述

编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

题目链接

二、提示

1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符

三、示例

示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]

示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

四、代码

package q344反转字符串;

public class Main {
    public static void main(String[] args) {
        char[] s={'1','2','3','4','5','6'};
        reverseString(s);
        for (char ss:s){
            System.out.print(" "+ss);
        }

    }
    public static void reverseString(char[] s) {
        char t;
        for (int i=0;i<s.length/2;i++){
            t=s[i];
            s[i]=s[s.length-1-i];
            s[s.length-1-i]=t;
        }
    }
}

总结