1841. 联赛信息统计 1811. 寻找面试候选人 1809. 没有广告的剧集 1821. 寻找今年具有正收入的客户 1831. 每天的最大交易

1841. 联赛信息统计[足球比赛积分问题]

---

# Write your MySQL query statement below
select team_name, count(*) matches_played ,sum(yingle*3+pingle) points,
       sum(goal) goal_for ,sum(dis_goal) goal_against,
       sum(goal-dis_goal) goal_diff
from(
select home_team_id id,
#算积分
sum(if(home_team_goals > away_team_goals,1,0)) yingle,
sum(if(home_team_goals < away_team_goals,1,0)) shule,
sum(if(home_team_goals = away_team_goals,1,0)) pingle,
#算进球失球数
sum(home_team_goals) goal,
sum(away_team_goals) dis_goal
from matches group by home_team_id ,away_team_id
union all
select away_team_id id,
       sum(if(home_team_goals < away_team_goals,1,0)) yingle,
       sum(if(home_team_goals > away_team_goals,1,0)) shule,
       sum(if(home_team_goals = away_team_goals,1,0)) pingle,
       sum(away_team_goals) goal,
       sum(home_team_goals) dis_goal
from matches group by away_team_id , home_team_id)new_table,teams T
where T.team_id = new_table.id
group by id
order by points desc, goal_diff desc ,team_name 

1811. 寻找面试候选人(求连续＋行转列)

---

# Write your MySQL query statement below
with new_table as(
    select contest_id ,gold_medal id from Contests
    union all
    select contest_id ,silver_medal from Contests
    union all
    select contest_id ,bronze_medal from Contests

)
select name,mail
from Users
where user_id in(
select id
from(
select *,
       contest_id - rank()over(partition by id order by contest_id) paiming
from new_table)new_new_table
group by id ,paiming
having count(*) > 2

union

select gold_medal
from Contests
group by gold_medal
having count(*)> 2
)

---

1809. 没有广告的剧集

---

# Write your MySQL query statement below
select
    distinct session_id
from
    Playback p left join Ads a
on
    p.customer_id = a.customer_id and a.timestamp between p.start_time and p.end_time
where
    ad_id is null;

---

1821. 寻找今年具有正收入的客户

---

select customer_id
from Customers
where year = '2021' and revenue >0

---

1831. 每天的最大交易

---

# Write your MySQL query statement below
select transaction_id
from (
select transaction_id,
       rank()over(partition by date_format(day,'%Y-%m-%d') order by amount desc) paiming
from   Transactions)new_table
where paiming = 1
order by transaction_id asc