el-table相同的值合并单元格+多级表头

    <el-table border :data="costList" :span-method="objectSpanMethod" >
      <el-table-column label="类别" prop="类别" width="120"> </el-table-column>
      <el-table-column label="费用科目" prop="费用科目" width="120"> </el-table-column>
      <el-table-column v-for="(item, index) in costTitle" :key="index" :label="item.name" width="120" :prop="item">
        <el-table-column :label="item.amount" width="120">
          <el-table-column v-for="(val, ind) in item.data" :key="ind" :label="val.substr(val.length - 2)" :prop="val"
            width="120">
          </el-table-column>

        </el-table-column>
      </el-table-column>
    </el-table>



export default {
  name: "OaZyfy",
  data() {
    return {
      costList: [],//内容
      costTitle: [],//表头
        mergeObj:{},
      mergeArr:['类别'，]//需要合并的表头 我这key值为中文 
    }
     methods: {
      getList() {
this.costList=[{"类别":"办公费","费用科目":"行政办公_快件费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":111,"船代（曹妃甸）总计":888,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":222},{"类别":"办公费","费用科目":"行政办公_通讯费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":500,"船代（曹妃甸）总计":888,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":222,"船代（京唐港）总计":222},{"类别":"办公费","费用科目":"行政办公_网络服务费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":888,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":222},{"类别":"办公费","费用科目":"行政办公_消耗品费用_办公用品","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":888,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":222},{"类别":"办公费","费用科目":"行政办公费-市内交通费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":888,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":222},{"类别":"办公费","费用科目":"workSum","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":888,"船代（曹妃甸）总计":888,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":222,"船代（京唐港）总计":222},{"类别":"招待费","费用科目":"招待费_饭费","最小组织":"睿智","睿智总计":33,"睿智明细":0,"船代（曹妃甸）明细":3,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_酒水","最小组织":"睿智","睿智总计":33,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_购卡","最小组织":"睿智","睿智总计":33,"睿智明细":4000,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_礼金","最小组织":"睿智","睿智总计":33,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_礼品","最小组织":"睿智","睿智总计":33,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_烟","最小组织":"睿智","睿智总计":33,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_住宿","最小组织":"睿智","睿智总计":33,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"招待费_其他","最小组织":"睿智","睿智总计":33,"睿智明细":2,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"招待费","费用科目":"serveSum","最小组织":"睿智","睿智总计":33,"睿智明细":33,"船代（曹妃甸）明细":3,"船代（曹妃甸）总计":3,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"差旅费","费用科目":"交通费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":0,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"差旅费","费用科目":"过桥费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":0,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"差旅费","费用科目":"餐饮费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":0,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"差旅费","费用科目":"住宿费","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":0,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},{"类别":"差旅费","费用科目":"tripSum","最小组织":"睿智","睿智总计":0,"睿智明细":0,"船代（曹妃甸）明细":0,"船代（曹妃甸）总计":0,"船代（沧州）明细":0,"船代（沧州）总计":0,"船代（京唐港）明细":0,"船代（京唐港）总计":0},]
 this.costTitle=  [{"name":"睿智","amount":"123.0","data":["睿智总计","睿智明细"]},{"name":"船代（曹妃甸）","amount":"456.21","data":["船代（曹妃甸）总计","船代（曹妃甸）明细"]},{"name":"船代（沧州）","amount":"450.0","data":["船代（沧州）总计","船代（沧州）明细"]},{"name":"船代（京唐港）","amount":"789.96","data":["船代（京唐港）总计","船代（京唐港）明细"]}]
      this.getSpanArr(this.costList)
     // listCost(this.queryParams).then(response => {
      //  this.costList = response.data.data1;
       // this.costTitle = response.data.title1;
    
        //this.loading = false;
        // 需要合并的表头
       // this.costTitle.forEach(item=>{
          // this.mergeArr.push(...item.data)
         // this.mergeArr.push(item.data[0])
        //})
       // console.log(this.mergeArr)

   
      //});
    },
getSpanArr(data) {
    this.mergeArr.forEach((key, index1) => {
        let count = 0; // 用来记录需要合并行的起始位置
        this.mergeObj[key] = []; // 记录每一列的合并信息
        data.forEach((item, index) => {
            // index == 0表示数据为第一行，直接 push 一个 1
            if(index === 0) {
                this.mergeObj[key].push(1); 
            } else {
                // 判断当前行是否与上一行其值相等 如果相等 在 count 记录的位置其值 +1 表示当前行需要合并 并push 一个 0 作为占位
                if(item[key] === data[index - 1][key]) { 
                    this.mergeObj[key][count] += 1;
                    this.mergeObj[key].push(0);
                } else {
                    // 如果当前行和上一行其值不相等 
                    count = index; // 记录当前位置 
                    this.mergeObj[key].push(1); // 重新push 一个 1
                }
            }
        })
    })
    console.log(this.mergeObj)
    // 相同的值合并完成
},

// 默认接受四个值 { 当前行的值, 当前列的值, 行的下标, 列的下标 }
objectSpanMethod({ row, column, rowIndex, columnIndex }) {
    // 判断列的属性
    if(this.mergeArr.indexOf(column.property) !== -1) { 
        // 判断其值是不是为0 
        if(this.mergeObj[column.property][rowIndex]) { 
            return [this.mergeObj[column.property][rowIndex], 1]
        } else {
            // 如果为0则为需要合并的行
            return [0, 0]; 
        }
    }
},
}
    }
   }

效果图

解决右下角合并贯穿问题

getSpanArr(data) {
    this.mergeArr.forEach((key, index1) => {
        let count = 0; // 用来记录需要合并行的起始位置
        this.mergeObj[key] = []; // 记录每一列的合并信息
        data.forEach((item, index) => {
            // index == 0表示数据为第一行，直接 push 一个 1
            if(index === 0) {
                this.mergeObj[key].push(1); 
            } else {
                // 判断当前行是否与上一行其值相等 如果相等 在 count 记录的位置其值 +1 表示当前行需要合并 并push 一个 0 作为占位
                if(item[key] === data[index - 1][key]) { 
                    this.mergeObj[key][count] += 1;
                    this.mergeObj[key].push(0);
                } else {
                    // 如果当前行和上一行其值不相等 
                    count = index; // 记录当前位置 
                    this.mergeObj[key].push(1); // 重新push 一个 1
                }
            }
        })
    })
    console.log(this.mergeObj)
    // 相同的值合并完成
    // 循环对象让后面合并的列与第一列齐平
     Object.keys(this.mergeObj).forEach(key => {
      this.mergeObj[key]=this.mergeObj['类别']
          })
    console.log(this.mergeObj)

},