11.11校园赛2-做题代码

# 输入n
n=int(input())

# 对折次数
ans=0
while(True):
    n=n/2
    if n >=1:
        ans+=1
    else:
        # 多少次后
        ans+=1
        break
print(ans)

# 输入行n,列，m
n,m=map(int,input().split())
# 操作次数
ans=int(input())
# 建立二维表
dp=[[1]*(m+1) for i in range (n+1)]
# print(dp[0][1])
# dp[0][1]=3
# print(dp)

# 开始每次操作
for i in range (ans):
    op=list(map(int,input().split()))
    for i in range (op[0],op[2]+1):
        for j in range (op[1],op[3]+1):
            dp[i][j]=0

# print(dp)
# 统计
print(dp)
ans=0
for i in range (1,n+1):
    for j in range (1,m+1):
        if dp[i][j]==1:
            ans+=1
print(ans)

aim='lanqiao'
aim=list(aim)
# print(aim)

a=str(input())
# print(a)
a=a.lower()
a=list(a)
# print(a)
# print(aim)
c=1
for i in range (len(aim)):
    if aim[i]!=a[i]:
        print('no')
        c=0
        break
if c==1:
    print('yes')

 

# 输入
a=int(input())
b=int(input())
a-=1
# 结果
c=(a+b)%7

print(c+1)

number='''
99, 22, 51, 63, 72, 61, 20, 88, 40, 21, 63, 30, 11, 18, 99, 12, 93, 16, 7, 53, 64, 9, 28, 84, 34, 96, 52, 82, 51, 77
'''
# 转化number成list
number=number.replace('\n','')
number=number.split(',')
print(number)
number=list(number)
# 计数
ans=0
# for 1--29
#     for i--29
# 暴力搜索
for i in range (30):
    for j in range (i+1,30):
        # if i==j:break
        if int(number[i])*int(number[j])>=2022:
            ans+=1
        # ans+=1
print(ans)

import datetime
# 开始时间：
start=datetime.date(1900,1,1)
# 结束时间
end=datetime.date(9999,12,31)
# 增加一天

# 相同的天数
ans=0
for i in range (999999999):


    # 开始增加
    start=start+datetime.timedelta(days=1)
    # 判断是否结束
    if start==end:
        break
    # 将日期转化成字符串
    start_=str(start).replace('-','')

    # 测试
    # print(start_)
    # break
    # 19000102
    #
    #
    # 转化成int计算

    # 年各个数字之和：
    year= int(start_[0])+int(start_[1])+int(start_[2])+int(start_[3])
    # 测试
    # print(year)
    # break
    # 10
    data_=int(start_[4])+int(start_[5])+int(start_[6])+int(start_[7])
    # 判断是否等于
    if data_==year:
        ans+=1
# 输出
print(ans)

b=['0','1','2','3','4','5','6','7','8','9']
for i in range (2022 ,3000):
    a=hex(i)
    z=a[2:]
    # print(a)
    z=list(z)
    c=0
    for j in z:
        if  (j  in  b):
            break
        else:
            c+=1
    if c==3:
        print(int(a,16))
        break