在链式存储结构建立二叉树排序树

#include 
#include 
 //定义树
typedef struct node{ //树的结点
    int data;
    struct node* left;
    struct node* right;
} Node;
 
typedef struct { //树根
    Node* root;
} Tree;
 
void insert(Tree* tree, int value)//创建树
{
    Node* node=(Node*)malloc(sizeof(Node));//创建一个节点
    node->data = value;
    node->left = NULL;
    node->right = NULL;
    if (tree->root == NULL)//判断树是不是空树
        tree->root = node;
    else {//不是空树
        Node* temp = tree->root;//从树根开始
        while (temp != NULL)
        {
            if (value < temp->data)//小于就进左儿子
            {
                if (temp->left == NULL)
                {
                     temp->left = node;
                    return;
                }
                else
                    temp = temp->left;
            }
            else {//否则进右儿子
                if (temp->right == NULL){
                    temp->right = node;
                    return;
                }   
                else 
                    temp = temp->right;
            }
        }
    }
    return;
}
 

void preorder(Node* node)//树的先序遍历
{
    if (node != NULL)
    {
        printf("%d ",node->data);
        preorder(node->left);
        preorder(node->right);
    }
}
 void midorder(Node* node)//树的中序遍历
{
    if (node != NULL)
    {
        midorder(node->left);
        printf("%d ",node->data);
        midorder(node->right);
    }
}
 void postorder(Node* node)//树的后序遍历
{
    if (node != NULL)
    {
        postorder(node->left);
        postorder(node->right);
        printf("%d ",node->data);
    }
}

// 求叶子个数
int count(Node* node){
    if(node==NULL){
        return 0;
    }else if(node->left==NULL&&node->right==NULL){
            return 1;
    }else{
        return count(node->left)+count(node->right);
    }
}

//计算二叉树的叶子节点和
int sum=0;
int sumnode(Node* t){
    if(t!=NULL){
        sum+=t->data;
        sumnode(t->left);
        sumnode(t->right);
    }
    return sum;
}

//计算该节点在二叉排序树中的层次
int height=0;
int level(Node* t,int x){
    if(t!=NULL){
        height++;
        if(t->data==x) return height;
        else if(t->data<x)
            level(t->right,x);
        else
            level(t->left,x);
    }
    return height;
}

//计算二叉排序树有多少层
int sumcount(Node* t){
    if(t==NULL) return 0;
    else{
        int lheight=sumcount(t->left);
        int rheight=sumcount(t->right);
        if(lheight>rheight)
            return lheight+1;
        else
            return rheight+1; 
    }
}

int main()
{
    Tree tree;
    tree.root = NULL;//创建一个空树
    int n;
    printf("输入n个数并创建这个树");//默认6层
    scanf("%d",&n);
    for (int i = 0; i < n; i++)//输入n个数并创建这个树3,8,9,4,7,2
    {
        int temp;
        printf("开始输入节点%d\t",i+1);
        scanf("%d",&temp);
        insert(&tree, temp);
    }
    printf("先序遍历结果\t");
    preorder(tree.root);//先序遍历
    printf("\n");
    
    printf("中序遍历结果\t");
    midorder(tree.root);//中序遍历
    printf("\n");
    
    printf("二叉树结点之和%d\n",sumnode(tree.root));
    printf("二叉树叶子结点的数目%d\n",count(tree.root));
    printf("7这个数在二叉树的第%d层\n",level(tree.root,7));
    printf("二叉树的高度为:%d",sumcount(tree.root));
    return 0;
}

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