【Leetcode】【实现循环队列】【数据结构】

【Leetcode】【实现循环队列】【数据结构】_第1张图片
【Leetcode】【实现循环队列】【数据结构】_第2张图片
代码实现:

typedef struct {
    int front;
    int back;
    int k;
    int* a;
    
} MyCircularQueue;

bool myCircularQueueIsEmpty(MyCircularQueue* obj) {
    return obj->front==obj->back;
}

bool myCircularQueueIsFull(MyCircularQueue* obj) {
    return (obj->back+1)%(obj->k+1)==obj->front;
}

MyCircularQueue* myCircularQueueCreate(int k) {
    MyCircularQueue* obj=(MyCircularQueue*)malloc(sizeof(MyCircularQueue));
    obj->a=(int*)malloc(sizeof(int)*(k+1));
    obj->front=0;
    obj->back=0;
    obj->k=k;
    return obj;
}

bool myCircularQueueEnQueue(MyCircularQueue* obj, int value) {
   if(!myCircularQueueIsFull(obj))
   {
    obj->a[obj->back]=value;
    obj->back++;
    (obj->back)%=(obj->k+1);
    return true;
   }
    return false;
}

bool myCircularQueueDeQueue(MyCircularQueue* obj) {
    if(myCircularQueueIsEmpty(obj))
    {
    
        return false;
    }
    else 
        ++obj->front;
        (obj->front)%=(obj->k+1);
        return true;
}

int myCircularQueueFront(MyCircularQueue* obj) {
    if(myCircularQueueIsEmpty(obj))
    {
        return -1;
    }
    else
    return obj->a[obj->front];
}

int myCircularQueueRear(MyCircularQueue* obj) {
    if(myCircularQueueIsEmpty(obj))
    return -1;
    else
    return obj->a[(obj->back-1+obj->k+1)%(obj->k+1)];
}

void myCircularQueueFree(MyCircularQueue* obj) {
    free(obj->a);
    obj->a=NULL;
    free(obj);
    obj=NULL;
}

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