leetcode做题记录——搜索插入位置

请必须使用时间复杂度为 O(log n) 的算法。

示例 1:

输入: nums = [1,3,5,6], target = 5
输出: 2
示例 2:

输入: nums = [1,3,5,6], target = 2
输出: 1
示例 3:

输入: nums = [1,3,5,6], target = 7
输出: 4
示例 4:

输入: nums = [1,3,5,6], target = 0
输出: 0
示例 5:

输入: nums = [1], target = 0
输出: 0

提示:

1 <= nums.length <= 104
-104 <= nums[i] <= 104
nums 为无重复元素的升序排列数组
-104 <= target <= 104

注意：本题与主站 35 题相同： https://leetcode-cn.com/problems/search-insert-position/

class Solution {
public:
    int searchInsert(vector<int>& nums, int target) {
        int len=nums.size();
        int left=0,right=len-1;

        while(left<=right){
            int  mid=left+(right-left)/2;
            if(nums[mid]==target){
                return mid;
            }
            else if(nums[mid]<target){
                left=mid+1;
            }
            else{
                right=mid-1;
            }
        }
        return left;
    }
};