flask之文件上传
1、创建表单提交页面，如：upload.html
<html>
<head>
<title>File Uploadtitle>
head>
<body>
<form action="http://localhost:8888/uploadfile" method="POST" enctype="multipart/form-data">
<input type="file" name="file001" />
<input type="submit" value="提交" />
form>
body>
html>
2、url地址关联表单提交页面
@app.route('/upload')
def uploadFile():
return render_template('upload.html')
3、提交表单后定义执行保存的函数
@app.route('/uploadfile',methods=['GET','POST'])
def save():
if request.method == 'POST':
f = request.files['file001'] #提取文件
f.save(os.path.join(app.config['UPLOAD_FOLDER'], secure_filename(f.filename)))
4、完整演示代码
from flask import Flask, render_template, request
from werkzeug.utils import secure_filename
import os
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = 'upload/' #app.config['UPLOAD_FOLDER'] 定义上传文件夹的路径
@app.route('/upload')
def uploadFile():
return render_template('upload.html')
@app.route('/uploadfile',methods=['GET','POST'])
def save():
if request.method == 'POST':
f = request.files['file001'] #提取文件
f.save(os.path.join(app.config['UPLOAD_FOLDER'], secure_filename(f.filename))) #保存文件，目标文件的名称可以是硬编码的，也可以从 request.files[file] 对象的 filename 属性中获取。但是，建议使用 secure_filename() 函数获取它的安全版本。
return 'file uploaded successfully'
else:
return render_template('upload.html')
if __name__ == '__main__':
app.run(debug=True)