【C/PTA —— 15.结构体2(课外实践)】

C/PTA —— 15.结构体2(课外实践)

  • 7-1 一帮一
  • 7-2 考试座位号
  • 7-3 新键表输出
  • 7-4 可怕的素质
  • 7-5 找出同龄者
  • 7-6 排队
  • 7-7 军训

7-1 一帮一

【C/PTA —— 15.结构体2(课外实践)】_第1张图片

#include
#include

struct student
{
    int a;
    char name[20];
};

struct student1
{
    int b;
    char name1[20];
};

int main()
{
    struct student  s1[50];
    struct student1 s2[50];
    struct student1 s3[50];

    int i, n, j = 0, t = 0, c, d;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
    {
        scanf("%d %s", &s1[i].a, s1[i].name);
    }

    for (i = 0; i < n; i++)
    {
        if (s1[i].a == 1)
        {
            s2[j].b = i;
            strcpy(s2[j].name1, s1[i].name);
            j++;
        }
        if (s1[i].a == 0)
        {
            s3[t].b = i;
            strcpy(s3[t].name1, s1[i].name);
            t++;
        }
    }

    c = n / 2 - 1, d = n / 2 - 1;
    j = 0, t = 0;
    for (i = 0; i < n / 2; i++)
    {
        if (s3[j].b < s2[t].b)
        {
            printf("%s %s\n", s3[j].name1, s2[c].name1);
            j++;
            c--;
        }
        else
        {
            printf("%s %s\n", s2[t].name1, s3[d].name1);
            t++;
            d--;
        }
    }
    return 0;
}

7-2 考试座位号

【C/PTA —— 15.结构体2(课外实践)】_第2张图片

#include
struct student
{
	char num[17];
	int s;
	int k;
};

int main()
{
	int n = 0;
	scanf("%d", &n);
	struct student stu[1000]={0};
	for (int i = 0; i < n; i++)
	{
		scanf("%s %d %d", stu[i].num, &stu[i].s, &stu[i].k);
	}
	int m = 0,ret;     
	scanf("%d", &m);
	for (int i = 0; i < m; i++)
	{
		scanf("%d", &ret);
        int j=0;
		for (j = 0; j < n; j++)
		{
			if (ret == stu[j].s)
			{
				printf("%s %d\n", stu[j].num, stu[j].k);
			}
		}
		
	}
	return 0;
}

7-3 新键表输出

【C/PTA —— 15.结构体2(课外实践)】_第3张图片

#include 
#include 

// 定义链表节点结构体
typedef struct ListNode {
    int val;
    struct ListNode* next;
} ListNode;

// 定义头节点指针
ListNode* createList() {
    ListNode* head = NULL;
    int num;
    while (1) {
        scanf("%d", &num);
        if (num == -1) {
            break;
        }
        ListNode* newNode = (ListNode*)malloc(sizeof(ListNode));
        newNode->val = num;
        newNode->next = NULL;
        if (head == NULL) {
            head = newNode;
        } else {
            ListNode* cur = head;
            while (cur->next != NULL) {
                cur = cur->next;
            }
            cur->next = newNode;
        }
    }
    return head;
}

// 遍历链表,将奇数值节点插入新链表
ListNode* createNewList(ListNode* head) {
    ListNode* newHead = NULL;
    ListNode* cur = head;
    while (cur != NULL) {
        if (cur->val % 2 != 0) {
            ListNode* newNode = (ListNode*)malloc(sizeof(ListNode));
            newNode->val = cur->val;
            newNode->next = NULL;
            if (newHead == NULL) {
                newHead = newNode;
            } else {
                ListNode* temp = newHead;
                while (temp->next != NULL) {
                    temp = temp->next;
                }
                temp->next = newNode;
            }
        }
        cur = cur->next;
    }
    return newHead;
}

// 打印链表
void printList(ListNode* head) {
    ListNode* cur = head;
    printf("%d", cur->val);
    cur = cur->next;
    while (cur != NULL) {
        printf(" %d", cur->val);
        cur = cur->next;
    }
    printf("\n");
}

int main() {
    // 创建链表
    ListNode* head = createList();
    // 创建新链表
    ListNode* newHead = createNewList(head);
    // 打印新链表
    printList(newHead);
    return 0;
}

7-4 可怕的素质

【C/PTA —— 15.结构体2(课外实践)】_第4张图片

#include 
#include
typedef struct student student;
struct student{
    int ret;
    struct student *next;
};
student *insert(int n);
void prin(student*,int n);
int main(){
    int n;
    student *stu1;
    scanf("%d", &n);
    stu1=insert(n);
    prin(stu1, n);
    return 0;
}
void prin(student*stu1,int n){
    student *p = stu1->next;
    while(p!=NULL){
        if(p->next!=NULL)printf("%d ", p->ret);
        else
            printf("%d", p->ret);
        p = p->next;
    }
}
student *insert(int n){
    student *head;
    head = (struct student*) malloc(sizeof(student));
    head->next = NULL;
    student *p = head, *q;
    int pos = 0;
    for (int i = 1; i <= n;i++){
        scanf("%d", &pos);
        q = (struct student *)malloc(sizeof(student));
        q->ret = i;
        q->next = NULL;
        if(i==1){
            head->next = q;
            }
        
        else if(pos==0){
            q->next = head->next;
            head->next = q;
        }
        else if(pos!=0){
            p = head->next;
            while(p->ret!=pos){
                p = p->next;
            }
            q->next = p->next;
            p->next = q;
        }
    }
    return head;
}

7-5 找出同龄者

【C/PTA —— 15.结构体2(课外实践)】_第5张图片

#include
typedef struct student
{
	char name[10];
	int age;
}student;
int main()
{
	int n = 0;
	student stu[100];
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		scanf("%s %d", stu[i].name, &stu[i].age);
	}
	int m = 0;
	scanf("%d", &m);
	int j = 0;
	for (int i = 0; i < n; i++)
	{
		if (stu[i].age != m)
		{
			printf("%s", stu[i].name);
			j = i;
			break;
		}
			
	}
	for (int i = j + 1; i < n; i++)
	{
		if (stu[i].age != m)
		{
			printf(" %s", stu[i].name);
		}
	}
	return 0;
}

7-6 排队

【C/PTA —— 15.结构体2(课外实践)】_第6张图片

#include
#include
typedef struct student student;
//还是双链表好用
struct student{
    student *prior;
    student *next;
    int ri, bi, fi,ret;
    double height;
    student *arret;
};
student* create(int n){
    student *head, *p, *q;
    head = (student*)malloc(sizeof(student));
    head->prior = NULL;
    head->next = NULL;
    head->arret = NULL;
    for (int i = 1; i <= n;i++){
        q = (student*)malloc(sizeof(student));
        scanf("%lf", &q->height);
        q->ret = i;
        if(i==1){
            head->next = q;
            head->arret = q;
            q->arret = NULL;
            q->prior = head;
            q->next = NULL;
            
        }else {
            p->next = q;
            p->arret = q;
            q->arret = NULL;
            q->prior = p;
            q->next = NULL;
        }
        p = q;
    }
    return head;
}
void swap(student *p1,student *p2){
    student *p1f, *p1b, *p2f, *p2b;
    p1f = p1->prior;
    p1b = p1->next;
    p2f = p2->prior;
    p2b = p2->next;
 
    p1f->next = p1b;
    p1b->prior = p1f;
    p1b->next = p2f;
    p2f->prior = p1b;
    p2f->next = p2b;
    if(p2b!=NULL)
        p2b->prior = p2f;
}
int main(){
    int n;
    scanf("%d", &n);
    student *stu1;
    stu1=create(n);
    student *p = stu1->next;
    for (int i = 1; i < n;i++){
        p = stu1->next;
        for (int j = 1; j < n - i + 1;j++){
            if(p->height<p->next->height){
                swap(p,p->next);
            }
            else p = p->next;
        }
    }
    p = stu1->next;
    for (int i = 1; i <= n;i++){
        if(i==1){
            p->fi = 0;
            p->bi = p->next->ret;
        }else if(i==n){
            p->bi = 0;
            p->fi = p->prior->ret;
        }else {
            p->fi = p->prior->ret;
            p->bi = p->next->ret;
        }
        p->ri = i;
        p = p->next;
    }
    p = stu1->arret;
    for (int i = 1; i <= n;i++){
        printf("%d %d %d\n", p->ri, p->fi, p->bi);
        p = p->arret;
    }
        return 0;
}

7-7 军训

【C/PTA —— 15.结构体2(课外实践)】_第7张图片

#include
#include
typedef struct queue queue;
struct queue{
    int rank;
    queue *prior;
    queue *next;
    int size;
};
void print(queue *queue1){
    queue *p = queue1->next;
    while(p!=NULL){
        if(p->next!=NULL)printf("%d ", p->rank);
        else
            printf("%d\n", p->rank);
        p = p->next;
    }
}
queue *delete_LB(queue *queue1){
    queue *k = queue1;
    queue1->prior->next = queue1->next;
    if(queue1->next!=NULL)queue1->next->prior = queue1->prior;
    queue1 = queue1->prior;
    free(k);
    return queue1;
}
queue *create(int n){
    queue *head;
    queue *p, *q;
    head = (queue*)malloc(sizeof(queue));
    head->prior = NULL;
    head->next = NULL;
    for (int i = 1; i <= n;i++){
        q = (queue *)malloc(sizeof(queue));
        q->rank = i;
        if(i==1){
            head->next = q;
            q->prior = head;
            q->next = NULL;
        }else {
            p->next = q;
            q->prior = p;
            q->next = NULL;
        }
        p = q;
    }
    return head;
}
int main(){
    int n;
    scanf("%d", &n);
    queue document[105];
    queue *a;
    for (int i = 1; i <= n;i++){
        int count;
        scanf("%d", &count);
        a = create(count);
        a->size = count;
        queue *p;
        while(a->size>3){
            p = a->next;
            for (int j = 1; j <= count; j++)
            {
                if (j % 2 == 0)//这里无需判断是否size>3,因为无论是否满足,都必须在进行的一轮内将所有2的报数删除;
                {
                    p=delete_LB(p);
                    a->size--;
                }
                p = p->next;
            }
            count = a->size;
            p = a->next;
            if(a->size>3)//这里加上size>3的判断才能保证n=40的情况下37不会被删除,否则还会进行一次j=3时的删除操作;特殊情况(即处理完上一轮2的报数后size恰好为3,但是此时没有加入判断的话循环会继续运行,会多删除1项)
            {
                for (int j = 1; j <= count; j++)
                {
                    if (j % 3 == 0) 
                    {
                        p = delete_LB(p);
                        a->size--;
                    }
                    p = p->next;
            }
            }
        count = a->size;
        }
        document[i] = *a;
    }
    for (int i = 1; i <= n;i++){
        print(&document[i]);
    }
    return 0;
}

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