[leetcode] 1431. Kids With the Greatest Number of Candies

Description

Given the array candies and the integer extraCandies, where candies[i] represents the number of candies that the ith kid has.

For each kid check if there is a way to distribute extraCandies among the kids such that he or she can have the greatest number of candies among them. Notice that multiple kids can have the greatest number of candies.

Example 1:

Input: candies = [2,3,5,1,3], extraCandies = 3
Output: [true,true,true,false,true] 
Explanation: 
Kid 1 has 2 candies and if he or she receives all extra candies (3) will have 5 candies --- the greatest number of candies among the kids. 
Kid 2 has 3 candies and if he or she receives at least 2 extra candies will have the greatest number of candies among the kids. 
Kid 3 has 5 candies and this is already the greatest number of candies among the kids. 
Kid 4 has 1 candy and even if he or she receives all extra candies will only have 4 candies. 
Kid 5 has 3 candies and if he or she receives at least 2 extra candies will have the greatest number of candies among the kids. 

Example 2:

Input: candies = [4,2,1,1,2], extraCandies = 1
Output: [true,false,false,false,false] 
Explanation: There is only 1 extra candy, therefore only kid 1 will have the greatest number of candies among the kids regardless of who takes the extra candy.

Example 3:

Input: candies = [12,1,12], extraCandies = 10
Output: [true,false,true]

Constraints:

  • 2 <= candies.length <= 100
  • 1 <= candies[i] <= 100
  • 1 <= extraCandies <= 50

分析

题目的意思是:这是一个分糖果的简单题,看明白题目了之后,首先就要找到一个数组里面的最大值,然后遍历candies数组,找到每个位置的值能凑齐最大值所需要到糖果数,如果大于给定的extraCandies,则不符合条件;否则,满足条件。

代码

class Solution:
    def kidsWithCandies(self, candies: List[int], extraCandies: int) -> List[bool]:
        max_val=max(candies)
        res=[]
        for candy in candies:
            remain=max_val-candy
            if(remain<=extraCandies):
                res.append(True)
            else:
                res.append(False)
        return res

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