python2和python3在运算符上的区别

今天在巩固python基础的路上，发现了一个在运算符上不同的python版本的区别。

在算数运算符/除法上

python2中，俩个整数相除，并且可以整除的情况下，返回的是整数

C:\Users>python
Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> 4/2
2
>>> a = 4/2
>>> type(a)

python3中，俩个整数相除，并且可以整除的情况下，返回的仍是浮点数

C:\Users>python3
Python 3.6.5 (v3.6.5:f59c0932b4, Mar 28 2018, 17:00:18) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> 4/2
2.0
>>> a = 4/2
>>> type(a)

但是如果是俩个浮点数相除，得到的结果仍是浮点数

C:\Users>python
Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> b = 4.0/2.0
>>> b
2.0
>>> type(b)

C:\Users>python3
Python 3.6.5 (v3.6.5:f59c0932b4, Mar 28 2018, 17:00:18) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> b = 4.0/2.0
>>> b
2.0
>>> type(b)

在比较运算符<>除法上

在python3上，不支持用<>表示不等于，只支持!=这种形式。

C:\Users\40859>python3
Python 3.6.5 (v3.6.5:f59c0932b4, Mar 28 2018, 17:00:18) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> a = 5
>>> b = 6
>>> a<>b
  File "", line 1
    a<>b
      ^
SyntaxError: invalid syntax

C:\Users>python
Python 2.7.3 (default, Apr 10 2012, 23:31:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> a = 5
>>> b = 6
>>> a<>b
True
>>>