马踏棋盘 (对应于小甲鱼视频的代码)

#include

#include

#define X 8

#define Y 8

int chess[X][Y];

int c = 1;

//找到基于(x,y)位置的下一个可走位置

int nextxy(int *x, int *y, int count)

{

switch (count)

{

case 0:

if (*x + 2 <= X - 1 && *y - 1 >= 0 && chess[*x + 2][*y - 1] == 0)

{

*x += 2;

*y -= 1;

return 1;

}

break;

case 1:

if (*x + 2 <= X - 1 && *y + 1 <= Y - 1 && chess[*x + 2][*y + 1] == 0)

{

*x += 2;

*y += 1;

return 1;

}

break;

case 2:

if (*x - 2 >= 0 && *y - 1 >= 0 && chess[*x - 2][*y - 1] == 0)

{

*x -= 2;

*y -= 1;

return 1;

}

break;

case 3:

if (*x - 2 >= 0 && *y + 1 <= Y - 1 && chess[*x - 2][*y + 1] == 0)

{

*x -= 2;

*y += 1;

return 1;

}

break;

case 4:

if (*x + 1 <= X - 1 && *y - 2 >= 0 && chess[*x + 1][*y - 2] == 0)

{

*x += 1;

*y -= 2;

return 1;

}

break;

case 5:

if (*x + 1 <= X - 1 && *y + 2 <= Y - 1 && chess[*x + 1][*y + 2] == 0)

{

*x += 1;

*y += 2;

return 1;

}

break;

case 6:

if (*x - 1 >= 0 && *y - 2 >= 0 && chess[*x - 1][*y - 2] == 0)

{

*x -= 1;

*y -= 2;

return 1;

}

break;

case 7:

if (*x - 1 >= 0 && *y + 2 <= Y - 1 && chess[*x - 1][*y + 2] == 0)

{

*x -= 1;

*y += 2;

return 1;

}

break;

default:

break;

}

return 0;

}

void print()

{

int i, j;

for (i = 0; i < X; i++)

{

for (j = 0; j < Y; j++)

{

printf("%2d\t", chess[i][j]);

}

printf("\n");

}

printf("\n");

}

//深度优先遍历棋盘 (x,y)为起始位置坐标,tag为标记变量,每走一步,tag加一

int Travalchesboard(int x, int y, int tag)

{

int x1 = x, y1 = y, flag = 0, count = 0;

chess[x][y] = tag;

if (tag == X * Y)

{

//打印棋盘

print();

return 1;

}

flag = nextxy(&x1, &y1, count);              //打印马的下一个坐标(x1,y1),如果找到flag=1,否则=0;

while (flag == 0 && count < 7)

{

count++;

flag = nextxy(&x1, &y1, count);

}

while (flag)

{

if (Travalchesboard(x1, y1, tag + 1))    //这里这个递推需要好好理解一下,在不满足条件出去一个函数后,tag会减一,从而实现不对则往回返

{

return 1;

}

x1 = x;

y1 = y;

count++;

flag = nextxy(&x1, &y1, count); //出现意外,继续找下一步可走坐标

}

if (flag == 0)

{

chess[x][y] = 0;

}

return 0;

}

int main()

{

int i, j;

clock_t start, finish;

start = clock();

for (i = 0; i < X; i++)

{

for (j = 0; j < Y; j++)

{

chess[i][j] = 0;

}

}

if (!Travalchesboard(2, 0, 1))

{

printf("sorry,fault!! \n");

}

finish = clock();

printf("\n time: \n", (double)(finish - start) / CLOCKS_PER_SEC);

return 0;

}

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