本文由CSDN点云侠原创,CloudCompare——拟合空间球,爬虫自重。如果你不是在点云侠的博客中看到该文章,那么此处便是不要脸的爬虫与GPT生成的文章。
源码里用到了四点定球,具体计算原理如下:
已知空间内不共面的四个点,设其坐标为 A ( x 1 , y 1 , z 1 ) A(x_1,y_1,z_1) A(x1,y1,z1)、 B ( x 2 , y 2 , z 2 ) B(x_2,y_2,z_2) B(x2,y2,z2)、 C ( x 3 , y 3 , z 3 ) 、 D ( x 4 , y 4 , z 4 ) C(x_3,y_3,z_3)、D(x_4,y_4,z_4) C(x3,y3,z3)、D(x4,y4,z4),设半径为 r r r,球心 O O O坐标为 ( x , y , z ) (x,y,z) (x,y,z)。利用四点到球心距离相等的性质得到如下四个方程。
( x − x 1 ) 2 + ( y − y 1 ) 2 + ( z − z 1 ) 2 = r 2 ; ( x − x 2 ) 2 + ( y − y 2 ) 2 + ( z − z 2 ) 2 = r 2 ; ( x − x 3 ) 2 + ( y − y 3 ) 2 + ( z − z 3 ) 2 = r 2 ; ( x − x 4 ) 2 + ( y − y 4 ) 2 + ( z − z 4 ) 2 = r 2 ; (x-x_1)^2 + (y-y_1)^2 +(z-z_1)^2 =r^2;\\ (x-x_2)^2 + (y-y_2)^2 +(z-z_2)^2 =r^2;\\ (x-x_3)^2 + (y-y_3)^2 +(z-z_3)^2 =r^2;\\ (x-x_4)^2 + (y-y_4)^2 +(z-z_4)^2 =r^2; (x−x1)2+(y−y1)2+(z−z1)2=r2;(x−x2)2+(y−y2)2+(z−z2)2=r2;(x−x3)2+(y−y3)2+(z−z3)2=r2;(x−x4)2+(y−y4)2+(z−z4)2=r2;
展开得:
x 2 + y 2 + z 2 − 2 ( x 1 x + y 1 y + z 1 z ) + x 1 2 + y 1 2 + z 1 2 = r 2 ① x 2 + y 2 + z 2 − 2 ( x 2 x + y 2 y + z 2 z ) + x 2 2 + y 2 2 + z 2 2 = r 2 ② x 2 + y 2 + z 2 − 2 ( x 3 x + y 3 y + z 3 z ) + x 3 2 + y 3 2 + z 3 2 = r 2 ③ x 2 + y 2 + z 2 − 2 ( x 4 x + y 4 y + z 4 z ) + x 4 2 + y 4 2 + z 4 2 = r 2 ④ x^2 + y^2 + z^2- 2(x_1x+y_1y+z_1z)+x_1^2+y_1^2 + z_1^2 = r^2 ①\\ x^2 + y^2 + z^2- 2(x_2x+y_2y+z_2z)+x_2^2+y_2^2 + z_2^2 = r^2②\\ x^2 + y^2 + z^2- 2(x_3x+y_3y+z_3z)+x_3^2+y_3^2 + z_3^2 = r^2③\\ x^2 + y^2 + z^2- 2(x_4x+y_4y+z_4z)+x_4^2+y_4^2 + z_4^2 = r^2④ x2+y2+z2−2(x1x+y1y+z1z)+x12+y12+z12=r2①x2+y2+z2−2(x2x+y2y+z2z)+x22+y22+z22=r2②x2+y2+z2−2(x3x+y3y+z3z)+x32+y32+z32=r2③x2+y2+z2−2(x4x+y4y+z4z)+x42+y42+z42=r2④
分别作①-②、③ - ④、② - ③得:
( x 1 − x 2 ) x + ( y 1 − y 2 ) y + ( z 1 − z 2 ) z = 1 / 2 ( x 1 2 − x 2 2 + y 1 2 − y 2 2 + z 1 2 − z 2 2 ) ( x 3 − x 4 ) x + ( y 3 − y 4 ) y + ( z 3 − z 4 ) z = 1 / 2 ( x 3 2 − x 4 2 + y 3 2 − y 4 2 + z 3 2 − z 4 2 ) ( x 2 − x 3 ) x + ( y 2 − y 3 ) y + ( z 2 − z 3 ) z = 1 / 2 ( x 2 2 − x 3 2 + y 2 2 − y 3 2 + z 2 2 − z 3 2 ) (x_1-x_2)x+(y_1-y_2)y+(z_1-z_2)z=1/2(x_1^2 -x_2^2 + y_1^2 -y_2^2 + z_1^2 -z_2^2 )\\ (x_3-x_4)x+(y_3-y_4)y+(z_3-z_4)z=1/2(x_3^2 -x_4^2 + y_3^2 -y_4^2 + z_3^2 -z_4^2 )\\ (x_2-x_3)x+(y_2-y_3)y+(z_2-z_3)z=1/2(x_2^2 -x_3^2 + y_2^2 -y_3^2 + z_2^2 -z_3^2 )\\ (x1−x2)x+(y1−y2)y+(z1−z2)z=1/2(x12−x22+y12−y22+z12−z22)(x3−x4)x+(y3−y4)y+(z3−z4)z=1/2(x32−x42+y32−y42+z32−z42)(x2−x3)x+(y2−y3)y+(z2−z3)z=1/2(x22−x32+y22−y32+z22−z32)
其对应的系数行列式可设为:
D = ∣ a b c a 1 b 1 c 1 a 2 b 2 c 2 ∣ D=\left| \begin{matrix} a & b & c\\ a_1 & b_1 & c_1 \\ a_2 & b_2 & c_2 \end{matrix} \right| D= aa1a2bb1b2cc1c2
则: a = ( x 1 − x 2 ) , b = ( y 1 − y 2 ) , c = ( z 1 − z 2 ) , a 1 = ( x 3 − x 4 ) , b 1 = ( y 3 − y 4 ) , c 1 = ( z 3 − z 4 ) , a 2 = ( x 2 − x 3 ) , b 2 = ( y 2 − y 3 ) , c 2 = ( z 2 − z 3 ) a=(x_1-x_2),b=(y_1-y_2),c=(z_1-z_2),\\a_1=(x_3-x_4),b_1=(y_3-y_4),c_1=(z_3-z_4),\\ a_2=(x_2-x_3),b_2=(y_2-y_3),c_2=(z_2-z_3) a=(x1−x2),b=(y1−y2),c=(z1−z2),a1=(x3−x4),b1=(y3−y4),c1=(z3−z4),a2=(x2−x3),b2=(y2−y3),c2=(z2−z3)
常数项行列式为:
L = ∣ P Q R ∣ L=\left| \begin{matrix} P\\ Q \\ R \end{matrix} \right| L= PQR
则:
P = 1 2 ( x 1 2 − x 2 2 + y 1 2 − y 2 2 + z 1 2 − z 2 2 ) P=\frac{1}{2}(x_1^2 -x_2^2 + y_1^2 -y_2^2 + z_1^2 - z_2^2 ) P=21(x12−x22+y12−y22+z12−z22)
Q = 1 2 ( x 3 2 − x 4 2 + y 3 2 − y 4 2 + z 3 2 − z 4 2 ) Q=\frac{1}{2}(x_3^2 -x_4^2 + y_3^2 -y_4^2 + z_3^2 - z_4^2 ) Q=21(x32−x42+y32−y42+z32−z42)
R = 1 2 ( x 2 2 − x 3 2 + y 2 2 − y 3 2 + z 2 2 − z 3 2 ) R=\frac{1}{2}(x_2^2 -x_3^2 + y_2^2 -y_3^2 + z_2^2 - z_3^2 ) R=21(x22−x32+y22−y32+z22−z32)
现设:
D x = ∣ P b c Q b 1 c 1 R b 2 c 2 ∣ Dx=\left| \begin{matrix} P & b & c\\ Q & b_1 & c_1 \\ R & b_2 & c_2 \end{matrix} \right| Dx= PQRbb1b2cc1c2
D y = ∣ a P c a 1 Q c 1 a 2 R c 2 ∣ Dy=\left| \begin{matrix} a & P & c\\ a_1 & Q & c_1 \\ a_2 &R & c_2 \end{matrix} \right| Dy= aa1a2PQRcc1c2
D z = ∣ a b P a 1 b 1 Q a 2 b 2 R ∣ Dz=\left| \begin{matrix} a & b & P\\ a_1 & b_1 & Q \\ a_2 &b_2 & R \end{matrix} \right| Dz= aa1a2bb1b2PQR
由线性代数中的克拉默法则可知:
x = D x D x=\frac{Dx}{D} x=DDx
y = D y D y=\frac{Dy}{D} y=DDy
z = D z D z=\frac{Dz}{D} z=DDz
通过菜单栏的'Tools > Fit > Sphere'
找到该功能。
选择一个或多个点云,然后启动此工具。CloudCompare将在每个点云上拟合球体基元。在控制台中,将输出以下信息:
center
(也可以在球体实体属性中找到球体边界框的中心)radius
(也可以在sphere实体属性中找到)RMS
(在默认球体实体名称中调用)注意:理论上球体拟合算法可以处理高达50%的异常值。球形点云
拟合结果
控制台输出
GeometricalAnalysisTools::ErrorCode GeometricalAnalysisTools::DetectSphereRobust(
GenericIndexedCloudPersist* cloud,
double outliersRatio,
CCVector3& center,
PointCoordinateType& radius,
double& rms,
GenericProgressCallback* progressCb/*=nullptr*/,
double confidence/*=0.99*/,
unsigned seed/*=0*/)
{
if (!cloud)
{
assert(false);
return InvalidInput;
}
unsigned n = cloud->size();
if (n < 4)
return NotEnoughPoints;
assert(confidence < 1.0);
confidence = std::min(confidence, 1.0 - FLT_EPSILON);
//we'll need an array (sorted) to compute the medians
std::vector<PointCoordinateType> values;
try
{
values.resize(n);
}
catch (const std::bad_alloc&)
{
//not enough memory
return NotEnoughMemory;
}
//number of samples
unsigned m = 1;
const unsigned p = 4;
if (n > p)
{
m = static_cast<unsigned>(log(1.0 - confidence) / log(1.0 - pow(1.0 - outliersRatio, static_cast<double>(p))));
}
//for progress notification
NormalizedProgress nProgress(progressCb, m);
if (progressCb)
{
if (progressCb->textCanBeEdited())
{
char buffer[64];
sprintf(buffer, "Least Median of Squares samples: %u", m);
progressCb->setInfo(buffer);
progressCb->setMethodTitle("Detect sphere");
}
progressCb->update(0);
progressCb->start();
}
//now we are going to randomly extract a subset of 4 points and test the resulting sphere each time
if (seed == 0)
{
std::random_device randomGenerator; // non-deterministic generator
seed = randomGenerator();
}
std::mt19937 gen(seed); // to seed mersenne twister.
std::uniform_int_distribution<unsigned> dist(0, n - 1);
unsigned sampleCount = 0;
unsigned attempts = 0;
double minError = -1.0;
std::vector<unsigned> indexes;
indexes.resize(p);
while (sampleCount < m && attempts < 2*m)
{
//get 4 random (different) indexes
for (unsigned j = 0; j < p; ++j)
{
bool isOK = false;
while (!isOK)
{
indexes[j] = dist(gen);
isOK = true;
for (unsigned k = 0; k < j && isOK; ++k)
if (indexes[j] == indexes[k])
isOK = false;
}
}
assert(p == 4);
const CCVector3* A = cloud->getPoint(indexes[0]);
const CCVector3* B = cloud->getPoint(indexes[1]);
const CCVector3* C = cloud->getPoint(indexes[2]);
const CCVector3* D = cloud->getPoint(indexes[3]);
++attempts;
CCVector3 thisCenter;
PointCoordinateType thisRadius;
if (ComputeSphereFrom4(*A, *B, *C, *D, thisCenter, thisRadius) != NoError)
continue;
//compute residuals
for (unsigned i = 0; i < n; ++i)
{
PointCoordinateType error = (*cloud->getPoint(i) - thisCenter).norm() - thisRadius;
values[i] = error*error;
}
const unsigned int medianIndex = n / 2;
std::nth_element(values.begin(), values.begin() + medianIndex, values.end());
//the error is the median of the squared residuals
double error = static_cast<double>(values[medianIndex]);
//we keep track of the solution with the least error
if (error < minError || minError < 0.0)
{
minError = error;
center = thisCenter;
radius = thisRadius;
}
++sampleCount;
if (progressCb && !nProgress.oneStep())
{
//progress canceled by the user
return ProcessCancelledByUser;
}
}
//too many failures?!
if (sampleCount < m)
{
return ProcessFailed;
}
//last step: robust estimation
ReferenceCloud candidates(cloud);
if (n > p)
{
//e robust standard deviation estimate (see Zhang's report)
double sigma = 1.4826 * (1.0 + 5.0 /(n-p)) * sqrt(minError);
//compute the least-squares best-fitting sphere with the points
//having residuals below 2.5 sigma
double maxResidual = 2.5 * sigma;
if (candidates.reserve(n))
{
//compute residuals and select the points
for (unsigned i = 0; i < n; ++i)
{
PointCoordinateType error = (*cloud->getPoint(i) - center).norm() - radius;
if (error < maxResidual)
candidates.addPointIndex(i);
}
candidates.resize(candidates.size());
//eventually estimate the robust sphere parameters with least squares (iterative)
if (RefineSphereLS(&candidates, center, radius))
{
//replace input cloud by this subset!
cloud = &candidates;
n = cloud->size();
}
}
else
{
//not enough memory!
//we'll keep the rough estimate...
}
}
//update residuals
{
double residuals = 0;
for (unsigned i = 0; i < n; ++i)
{
const CCVector3* P = cloud->getPoint(i);
double e = (*P - center).norm() - radius;
residuals += e*e;
}
rms = sqrt(residuals/n);
}
return NoError;
}
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