【MySQL】子查询 综合练习

题目:

#1.查询和Zlotkey相同部门的员工姓名和工资

#2.查询工资比公司平均工资高的员工的员工号,姓名和工资。

#3.选择工资大于所有JOB_ID = 'SA_MAN'的员工的工资的员工的last_name, job_id, salary

#4.查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名

#5.查询在部门的location_id为1700的部门工作的员工的员工号

#6.查询管理者是King的员工姓名和工资

#7.查询工资最低的员工信息: last_name, salary

#8.查询平均工资最低的部门信息

#9.查询平均工资最低的部门信息和该部门的平均工资(相关子查询)

#10.查询平均工资最高的 job 信息

#11.查询平均工资高于公司平均工资的部门有哪些?

#12.查询出公司中所有 manager 的详细信息

#13.各个部门中 最高工资中最低的那个部门的 最低工资是多少?

#14.查询平均工资最高的部门的 manager 的详细信息: last_name, department_id, email, salary

#15. 查询部门的部门号,其中不包括job_id是"ST_CLERK"的部门号

#16. 选择所有没有管理者的员工的last_name

#17.查询员工号、姓名、雇用时间、工资,其中员工的管理者为 'De Haan'

#18.查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资(相关子查询)

#19.查询每个部门下的部门人数大于 5 的部门名称(相关子查询)

#20.查询每个国家下的部门个数大于 2 的国家编号(相关子查询)

综合练习


#1.查询和Zlotkey相同部门的员工姓名和工资
SELECT last_name,salary
FROM employees
WHERE department_id = 
(
	SELECT department_id
	FROM employees
	WHERE last_name = 'Zlotkey'
);

	
#2.查询工资比公司平均工资高的员工的员工号,姓名和工资。
SELECT employee_id,last_name,salary
FROM employees
WHERE salary > 
(
	SELECT AVG(salary)
	FROM employees
);


#3.选择工资大于所有JOB_ID = 'SA_MAN'的员工的工资的员工的last_name, job_id, salary
SELECT last_name,job_id,salary
FROM employees
WHERE salary > ALL
(
	SELECT salary
	FROM employees
	WHERE job_id = 'SA_MAN'
);


#4*.查询 名字包含'%u%' 的 部门, 打印与其同部门的员工id,名字
SELECT employee_id,last_name
FROM employees 
WHERE department_id = ANY
(
	SELECT DISTINCT department_id
	FROM employees 
	WHERE last_name LIKE '%u%'
);


#5*.查询在部门的location_id为1700的部门工作的员工的员工号
SELECT employee_id
FROM employees
WHERE department_id IN 
(
	SELECT department_id
	FROM departments
	WHERE location_id = 1700
);

#6.查询管理者是King的员工姓名和工资
SELECT e.last_name,e.salary,m.last_name
FROM employees e, employees m 
WHERE e.manager_id = m.employee_id
AND m.last_name = 'king';

SELECT last_name,salary,last_name
FROM employees
WHERE last_name IN
(
	SELECT last_name
	FROM employees
	WHERE last_name = 'king'
);

#7*.查询工资最低的员工信息: last_name, salary
SELECT last_name,salary
FROM employees
WHERE salary <= ALL
(
	SELECT salary
	FROM employees
);

SELECT last_name,salary
FROM employees
WHERE salary = 
(
	SELECT MIN(salary)
	FROM employees 
);

#8*.查询平均工资最低的部门信息
# 方式一:
SELECT *
FROM departments d1 , (SELECT AVG(salary) avg_sal,department_id
									FROM employees
									GROUP BY department_id
									ORDER BY avg_sal ASC
									LIMIT 0,1) d2
WHERE d1.department_id = d2.department_id;

# 方式二


# 方式三


# 方式四



#9.查询平均工资最低的部门信息和该部门的平均工资(相关子查询)
SELECT d1.*,d2.department_id,d2.avg_sal
FROM departments d1 , (SELECT AVG(salary) avg_sal,department_id
									FROM employees
									GROUP BY department_id
									ORDER BY avg_sal ASC
									LIMIT 0,1) d2
WHERE d1.department_id = d2.department_id;

#10.查询平均工资最高的 job 信息
SELECT  j.*,e.avg_sal
FROM jobs j,(
						SELECT AVG(salary) avg_sal,job_id
						FROM employees
						GROUP BY job_id
						ORDER BY avg_sal DESC
						LIMIT 0,1
						) e
WHERE j.job_id = e.job_id;

#11.查询平均工资高于公司平均工资的部门有哪些?
SELECT department_id
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING AVG(salary) > (
				SELECT AVG(salary)
				FROM employees
);
						

#12.查询出公司中所有 manager 的详细信息
SELECT DISTINCT m.*
FROM employees e,employees m
WHERE e.manager_id = m.employee_id

#13.各个部门中 最高工资中最低的那个部门的 最低工资是多少?
SELECT e1.department_id,e2.max_sal
FROM employees e1 , (
											SELECT MAX(salary) max_sal,department_id
											FROM employees e2 
											GROUP BY department_id
											ORDER BY max_sal 
											LIMIT 0,1
)e2
WHERE e1.department_id = e2.department_id;

#14.查询平均工资最高的部门的 manager 的详细信息: last_name, department_id, email, salary
SELECT employee_id, last_name,m.department_id,email,salary
FROM employees e , (
											SELECT AVG(salary) avg_sal,department_id
											FROM employees m 
											GROUP BY department_id,employee_id
											ORDER BY avg_sal DESC
											LIMIT 0,1
) m
WHERE e.department_id = m.department_id
LIMIT 0,1;

#15. 查询部门的部门号,其中不包括job_id是"ST_CLERK"的部门号
SELECT department_id
FROM departments
WHERE department_id NOT IN 
(
		SELECT DISTINCT department_id
		FROM employees
		WHERE job_id = 'ST_CLERK'
);

#16. 选择所有没有管理者的员工的last_name
SELECT last_name
FROM employees e1
WHERE NOT EXISTS 
(
	SELECT *
	FROM employees e2 
	WHERE e1.manager_id = e2.employee_id
);

#17.查询员工号、姓名、雇用时间、工资,其中员工的管理者为 'De Haan'
SELECT e.employee_id,e.last_name,e.hire_date,e.salary
FROM employees e JOIN employees m 
WHERE e.manager_id = m.employee_id
AND m.last_name = 'De Haan';

#18.查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资(相关子查询)
SELECT employee_id,last_name,salary
FROM employees e1
WHERE salary > 
(
	SELECT AVG(salary)
	FROM employees e2
	WHERE e1.department_id = e2.department_id
);

#19.查询每个部门下的部门人数大于 5 的部门名称(相关子查询)
SELECT department_name,department_id
FROM departments d
WHERE 5 < 
(
	SELECT COUNT(*)
	FROM employees e
	WHERE d.department_id = e.department_id
);

#20.查询每个国家下的部门个数大于 2 的国家编号(相关子查询)		
SELECT country_id
FROM locations l
WHERE 2 < 
(
	SELECT COUNT(*)
	FROM departments d 
	WHERE l.location_id = d.location_id
);

你可能感兴趣的:(MySQL,#,综合练习,mysql,数据库,sql)