POJ 1142 Smith Numbers

 

Smith Numbers
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 7141   Accepted: 2505

Description

While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University,noticed that the telephone number of his brother-in-law H. Smith had the following peculiar property: The sum of the digits of that number was equal to the sum of the digits of the prime factors of that number. Got it? Smith's telephone number was 493-7775. This number can be written as the product of its prime factors in the following way: 
4937775= 3*5*5*65837
The sum of all digits of the telephone number is 4+9+3+7+7+7+5= 42,and the sum of the digits of its prime factors is equally 3+5+5+6+5+8+3+7=42. Wilansky was so amazed by his discovery that he named this kind of numbers after his brother-in-law: Smith numbers. 
As this observation is also true for every prime number, Wilansky decided later that a (simple and unsophisticated) prime number is not worth being a Smith number, so he excluded them from the definition. 
Wilansky published an article about Smith numbers in the Two Year College Mathematics Journal and was able to present a whole collection of different Smith numbers: For example, 9985 is a Smith number and so is 6036. However,Wilansky was not able to find a Smith number that was larger than the telephone number of his brother-in-law. It is your task to find Smith numbers that are larger than 4937775!

Input

The input file consists of a sequence of positive integers, one integer per line. Each integer will have at most 8 digits. The input is terminated by a line containing the number 0.

Output

For every number n > 0 in the input, you are to compute the smallest Smith number which is larger than n,and print it on a line by itself. You can assume that such a number exists.

Sample Input

4937774
0

Sample Output

4937775

Source

Mid-Central European Regional Contest 2000

 

/* http://acm.pku.edu.cn/JudgeOnline/problem?id=1142 map 哈希 + 求质因数,注意质数不是合法结果 */ #include #include using namespace std; int input; map::iterator itr; int getDigitSum(int a) { int res = 0; while(a != 0) { res += a % 10; a /= 10; } return res; } bool check(int inNum) { map countm; int curN, input = inNum; for(curN = 2; curN * curN <= input; curN++) { //cout<first; int cn = itr->second; //cout<>input && input != 0) { while(true) { input++; //cout<

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