Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times.
Example 1:
Input:
s = "aaabb", k = 3
Output:
3
The longest substring is "aaa", as 'a' is repeated 3 times.
Example 2:
Input:
s = "ababbc", k = 2
Output:
5
The longest substring is "ababb", as 'a' is repeated 2 times and 'b' is repeated 3 times.
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/longest-substring-with-at-least-k-repeating-characters
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分治算法,每次统计所有字符,找到不够数的字母,把字符串分成两边,再对两边计算。
class Solution {
public int longestSubstring(String s, int k) {
char[] counts = new char[26];
for (int i = 0; i < s.length(); i++) {
counts[s.charAt(i) - 'a'] ++;
}
int target = -1;
for (int i = 0; i < s.length(); i++) {
if (counts[s.charAt(i) - 'a'] < k) {
target = i;
break;
}
}
if (target == -1) {
return s.length();
}
return Math.max(longestSubstring(s.substring(0, target), k), longestSubstring(s.substring(target + 1), k));
}
}