mybatis批量插入oracle大量数据记录性能问题解决

1.使用"直接路径插入"(下面sql语句中的"/*+append_values */"),并且使用关键字"union all":

< insert id= "addUidCodeBatch"  parameterType= "java.util.List" >
    insert into /*+append_values */
        T_UID_CODE(C_UID_CODE,
                 C_SERAIL_LEN,
                 C_BATCH_CODE,
                 C_TYPE,
                 C_CREATE_TIME,
                 C_SUPER_CODE,
                 c_security_code,
                 C_SERIAL_CODE
                 )
       "list" item= "item" index = "index" separator= "union all" >
          select #{item.uidCode},
                 #{item.kCode},
                 #{item.batchCode},
                 #{item.type},
                 sysdate,
                 #{item.superCode},
                 #{item.securityCode},
                 #{item.serialCode}
          from dual

    insert >

2.dao层实现: 之前是一次性commit,这样做会随着插入数目的增大,执行速度陡然变慢,所以应该分批次进行插入:

public void save(List uidCodeList) throws Exception {
    SqlSession batchSqlSession = null ;
    try {
        batchSqlSession = sqlSessionFactory.openSession(ExecutorType.BATCH, false );//获取批量方式的sqlsession
        int batchCount = 1000;//每批 commit 的个数
        int batchLastIndex = batchCount - 1;//每批最后一个的下标
        for ( int index = 0; index < uidCodeList. size ()-1;){
            if(batchLastIndex > uidCodeList. size ()-1){
                batchLastIndex = uidCodeList. size () - 1;
                batchSqlSession. insert (NAMESPACE+ ".addUidCodeBatch" , uidCodeList.subList( index , batchLastIndex));
                batchSqlSession. commit ();
                System. out .println( "index:" + index + "     batchLastIndex:" +batchLastIndex);
                break;//数据插入完毕,退出循环

            } else {
                batchSqlSession. insert (NAMESPACE+ ".addUidCodeBatch" , uidCodeList.subList( index , batchLastIndex));                                   batchSqlSession. commit ();
                System. out .println( "index:" + index + "     batchLastIndex:" +batchLastIndex);
                index = batchLastIndex + 1;//设置下一批下标
                batchLastIndex = index + (batchCount - 1);
            }
        }
    }finally{
        batchSqlSession. close ();
    }
}