MySQL必学!!!(练习题50道精选)

必学练习题(45道)

  • 一、 数据表介绍
  • 二、搭建环境
    • 学生表 Student
    • 科目表 Course
    • 教师表 Teacher
    • 成绩表 SC
  • 三、练习题

一、 数据表介绍

数据表介绍
–1.学生表

Student(SId,Sname,Sage,Ssex)
--SId 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别

–2.课程表

Course(CId,Cname,TId)
--CId 课程编号,Cname 课程名称,TId 教师编号

–3.教师表

Teacher(TId,Tname)
--TId 教师编号,Tname 教师姓名

–4.成绩表

--SId 学生编号,CId 课程编号,score 分数

二、搭建环境

学生表 Student

create table Student(SId varchar(10),Sname varchar(10),Sage datetime,Ssex varchar(10));
insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
insert into Student values('02' , '钱电' , '1990-12-21' , '男');
insert into Student values('03' , '孙风' , '1990-12-20' , '男');
insert into Student values('04' , '李云' , '1990-12-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吴兰' , '1992-01-01' , '女');
insert into Student values('07' , '郑竹' , '1989-01-01' , '女');
insert into Student values('09' , '张三' , '2017-12-20' , '女');
insert into Student values('10' , '李四' , '2017-12-25' , '女');
insert into Student values('11' , '李四' , '2012-06-06' , '女');
insert into Student values('12' , '赵六' , '2013-06-13' , '女');
insert into Student values('13' , '孙七' , '2014-06-01' , '女');

科目表 Course

create table Course(CId varchar(10),Cname nvarchar(10),TId varchar(10));
insert into Course values('01' , '语文' , '02');
insert into Course values('02' , '数学' , '01');
insert into Course values('03' , '英语' , '03');

教师表 Teacher

create table Teacher(TId varchar(10),Tname varchar(10));
insert into Teacher values('01' , '张三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五');

成绩表 SC

create table SC(SId varchar(10),CId varchar(10),score decimal(18,1));
insert into SC values('01' , '01' , 80);
insert into SC values('01' , '02' , 90);
insert into SC values('01' , '03' , 99);
insert into SC values('02' , '01' , 70);
insert into SC values('02' , '02' , 60);
insert into SC values('02' , '03' , 80);
insert into SC values('03' , '01' , 80);
insert into SC values('03' , '02' , 80);
insert into SC values('03' , '03' , 80);
insert into SC values('04' , '01' , 50);
insert into SC values('04' , '02' , 30);
insert into SC values('04' , '03' , 20);
insert into SC values('05' , '01' , 76);
insert into SC values('05' , '02' , 87);
insert into SC values('06' , '01' , 31);
insert into SC values('06' , '03' , 34);
insert into SC values('07' , '02' , 89);
insert into SC values('07' , '03' , 98);

三、练习题

  1. 查询" 01 “课程比” 02 "课程成绩高的学生的信息及课程分数
select * from  (
    ->     select t1.SId, class1, class2
    ->     from
    ->         (SELECT SId, score as class1 FROM SC WHERE SC.CId = '01') AS t1, 
    ->         (SELECT SId, score as class2 FROM SC WHERE SC.CId = '02') AS t2
    ->     where t1.SId = t2.SId and t1.class1 > t2.class2
    -> ) r
    -> LEFT JOIN Student
    -> ON Student.SId = r.SId;

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1.1 查询同时存在" 01 “课程和” 02 "课程的情况

select * from      
(select * from SC where SC.CId = '01') as t1,     
(select * from SC where SC.CId = '02') as t2
 where t1.SId = t2.SId;

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1.2 查询存在" 01 “课程但可能不存在” 02 "课程的情况(不存在时显示为 null )

select * from
    -> (select * from SC where SC.CId = '01') as t1
    -> left join
    -> (select * from SC where SC.CId = '02') as t2
    -> on t1.SId = t2.SId;

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1.3 查询不存在" 01 “课程但存在” 02 "课程的情况

> select * from SC
    -> where SC.SId not in (
    ->     select SId from SC
    ->     where SC.CId = '01'
    -> )
    -> AND SC.CId= '02';

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  1. 查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩
> select Student.SId, Student.Sname, r.ss from Student right join(
    ->       select SId, AVG(score) AS ss from SC
    ->       GROUP BY SId
    ->       HAVING AVG(score)> 60
    -> )r on Student.SId = r.SId;

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  1. 查询在 SC 表存在成绩的学生信息
> select DISTINCT Student.*
    -> from Student,SC
    -> where Student.SId=SC.SId
    -> ;

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  1. 查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null )
> select Student.sid, Student.sname,r.coursenumber,r.scoresum
    -> from Student,
    -> (select SC.sid, sum(SC.score) as scoresum, count(SC.cid) as coursenumber from SC
    -> group by SC.sid)r
    -> where Student.sid = r.sid;

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4.1查有成绩的学生信息

> select * from Student
    -> where Student.sid in (select SC.sid from SC);

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  1. 查询「李」姓老师的数量
> select count(*)
    -> from Teacher
    -> where tname like '李%';

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  1. 查询学过「张三」老师授课的同学的信息
> select Student.* from Student,Teacher,Course,SC
    -> where
    ->     Student.sid = SC.sid
    ->     and Course.cid=SC.cid
    ->     and Course.tid =Teacher.tid
    ->     and tname = '张三';

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  1. 查询没有学全所有课程的同学的信息
> select * from Student
    -> where Student.sid not in (
    ->   select SC.sid from SC
    ->   group by SC.sid
    ->   having count(SC.cid)= (select count(cid) from Course)
    -> );

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  1. 查询至少有一门课与学号为" 01 "的同学所学相同的同学的信
> select * from Student
    -> where Student.sid in (
    ->     select SC.sid from SC
    ->     where SC.cid in(
    ->         select SC.cid from SC
    ->         where SC.sid = '01'
    ->     )
    -> );

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  1. 查询和" 01 "号的同学学习的课程 完全相同的其他同学的信息
> SELECT a.SId, a.Sname, a.Sage, a.Ssex
    -> FROM Student a, SC b
    -> WHERE a.SId = b.SId AND b.CId IN (
    ->     SELECT CId
    ->     FROM SC
    ->     WHERE SId = '01'
    -> ) AND a.SId <> '01';

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  1. 查询没学过"张三"老师讲授的任一门课程的学生姓名
> select * from Student
    ->      where Student.sid not in(
    ->         select SC.sid from SC,Course,Teacher
    ->         where
    ->             SC.cid = Course.cid
    ->              and Course.tid = Teacher.tid
    ->             and Teacher.tname= "张三");

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  1. 查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
select Student.SId, Student.Sname,b.avg
    -> from Student RIGHT JOIN
    -> (select sid, AVG(score) as avg from SC
    ->     where sid in (
    ->               select sid from SC
    ->               where score<60
    ->               GROUP BY sid
    ->               HAVING count(score)>1)
    ->     GROUP BY sid) b on Student.sid=b.sid;

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  1. 检索" 01 "课程分数小于 60,按分数降序排列的学生信息
> select Student.*, SC.score from Student, SC
    -> where Student.sid = SC.sid
    -> and SC.score < 60
    -> and cid = "01"
    -> ORDER BY SC.score DESC;

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  1. 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
> select *  from SC
    -> left join (
    ->     select sid,avg(score) as avscore from SC
    ->     group by sid
    ->     )r
    -> on SC.sid = r.sid
    -> order by avscore desc;

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  1. 查询各科成绩最高分、最低分和平均分:
    以如下形式显示:课程 ID,课程 name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
    及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
    要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

  2. 按各科成绩进行排序,并显示排名, Score 重复时保留名次空缺

> select
    -> SC.CId ,
    -> max(SC.score)as 最高分,
    -> min(SC.score)as 最低分,
    -> AVG(SC.score)as 平均分,
    -> count(*)as 选修人数,
    -> sum(case when SC.score>=60 then 1 else 0 end )/count(*)as 及格率,
    -> sum(case when SC.score>=70 and SC.score<80 then 1 else 0 end )/count(*)as        中等率,
    -> sum(case when SC.score>=80 and SC.score<90 then 1 else 0 end )/count(*)as        优良率,
    -> sum(case when SC.score>=90 then 1 else 0 end )/count(*)as 优秀率
    -> from SC
    -> GROUP BY SC.CId
    -> ORDER BY count(*)DESC, SC.CId ASC
    -> ;

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  1. 查询学生的总成绩,并进行排名,总分重复时保留名次空缺

  1. 统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0] 及所占百分比

  2. 查询各科成绩前三名的记录

> select * from SC
    -> where (
    -> select count(*) from SC as a
    -> where SC.cid = a.cid and SC.score )< 3
    -> order by cid asc, SC.score desc;

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  1. 查询每门课程被选修的学生数
> select cid, count(sid) from SC
    -> group by cid;

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  1. 查询出只选修两门课程的学生学号和姓名
> select Student.sid, Student.sname from Student
    -> where Student.sid in
    -> (select SC.sid from SC
    -> group by SC.sid
    -> having count(SC.cid)=2
    -> );

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  1. 查询男生、女生人数
> select ssex, count(*) from Student
    -> group by ssex;

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  1. 查询名字中含有「风」字的学生信息
> select *
    -> from Student
    -> where Student.Sname like '%风%'
    -> ;

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  1. 查询同名同性学生名单,并统计同名人数
> select sname, count(*) from Student
    -> group by sname
    -> having count(*)>1;

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  1. 查询 1990 年出生的学生名单
> select *
    -> from Student
    -> where YEAR(Student.Sage)=1990;

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25. 查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

  1. 查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩

  2. 查询课程名称为「数学」,且分数低于 60 的学生姓名和分数

> select Student.sname, SC.score from Student, SC, Course
    -> where Student.sid = SC.sid
    -> and Course.cid = SC.cid
    -> and Course.cname = "数学"
    -> and SC.score < 60;

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  1. 查询所有学生的课程及分数情况(存在学生没成绩,没选课的情况)
select Student.sname, cid, score from Student
left join SC
on Student.sid = SC.sid;

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  1. 查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数
> select Student.sname, Course.cname,SC.score from Student,Course,SC
    -> where SC.score>70
    -> and Student.sid = SC.sid
    -> and SC.cid = Course.cid;

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  1. 查询不及格的课程
> select DISTINCT SC.CId
    -> from SC
    -> where SC.score <60;

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  1. 查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名
> select Student.sid,Student.sname
    -> from Student,SC
    -> where cid="01"
    -> and score>=80
    -> and Student.sid = SC.sid;

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  1. 求每门课程的学生人数
> select SC.CId,count(*) as 学生人数
    -> from SC
    -> GROUP BY SC.CId;

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  1. 成绩不重复,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩
l> select Student.*, SC.score, SC.cid from Student, Teacher, Course,SC
    -> where Teacher.tid = Course.tid
    -> and SC.sid = Student.sid
    -> and SC.cid = Course.cid
    -> and Teacher.tname = "张三"
    -> order by score desc
    -> limit 1;

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  1. 成绩有重复的情况下,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩
> select Student.*, SC.score, SC.cid from Student, Teacher, Course,SC
    -> where Teacher.tid = Course.tid
    -> and SC.sid = Student.sid
    -> and SC.cid = Course.cid
    -> and Teacher.tname = "张三"
    -> and SC.score = (
    ->     select Max(SC.score)
    ->     from SC,Student, Teacher, Course
    ->     where Teacher.tid = Course.tid
    ->     and SC.sid = Student.sid
    ->     and SC.cid = Course.cid
    ->     and Teacher.tname = "张三"
    -> );

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  1. 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

  2. 查询每门功成绩最好的前两名

  1. 统计每门课程的学生选修人数(超过 5 人的课程才统计)。
> select SC.cid, count(sid) as cc from SC
    -> group by cid
    -> having cc >5;

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  1. 检索至少选修两门课程的学生学号
> select sid, count(cid) as cc from SC
    -> group by sid
    -> having cc>=2;

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  1. 查询选修了全部课程的学生信息

  1. 查询各学生的年龄,只按年份来算
SELECT s.SId, s.SName
FROM Student s
INNER JOIN SC sc ON s.SId = sc.SId
WHERE sc.Score > 80 AND sc.CId != '01';

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  1. 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一
> select Student.SId as 学生编号,Student.Sname  as  学生姓名,
    -> TIMESTAMPDIFF(YEAR,Student.Sage,CURDATE()) as 学生年龄
    -> from Student
    -> ;

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  1. 查询本周过生日的学生
select *
from Student 
where WEEKOFYEAR(Student.Sage)=WEEKOFYEAR(CURDATE());

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  1. 查询下周过生日的学生
select *
from Student 
where WEEKOFYEAR(Student.Sage)=WEEKOFYEAR(CURDATE())+1;

在这里插入图片描述

  1. 查询本月过生日的学生
l> select *
    -> from Student
    -> where MONTH(Student.Sage)=MONTH(CURDATE());

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  1. 查询下月过生日的学生
> select *
    -> from Student
    -> where MONTH(Student.Sage)=MONTH(CURDATE())+1;

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