算法训练营第六十天打卡|84.柱状图中最大的矩形

目录

  • Leetcode84.柱状图中最大的矩形

Leetcode84.柱状图中最大的矩形

文章链接:代码随想录
文章链接:84.柱状图中最大的矩形

思路:暴力双指针,超时

class Solution {
public:
    int largestRectangleArea(vector<int>& heights) {
        int result = 0;

        for (int i = 0; i < heights.size(); i++){
            int l = i;
            int r = i;
            for (; l >= 0; l--){
                if (heights[l] < heights[i]) break;
            }

            for (; r < heights.size(); r++){
                if (heights[r] < heights[i]) break;
            }
            int w = r - l - 1;
            int h = heights[i];
            result = max(result, w * h);
        }
        return result;
    }
};

优化1(自己优化),依然超时,本质上还是没优化,时间复杂度一样

class Solution {
public:
    int largestRectangleArea(vector<int>& heights) {
        int result = 0;
        vector<int> nexl(heights.size(), -1);
        vector<int> nexr(heights.size(), heights.size());

        for (int i = 0; i < heights.size(); i++){
            for (int j = i - 1; j >= 0; j--){
                if (heights[j] < heights[i]){
                    nexl[i] = j;
                    break;
                }
            }
        }

        for (int i = heights.size() - 1; i >= 0; i--){
            for (int j = i + 1; j < heights.size(); j++){
                if (heights[j] < heights[i]){
                    nexr[i] = j;
                    break;
                }
            }
        }
        
        for (int i = 0; i < heights.size(); i++){
            int w = nexr[i] - nexl[i] - 1;
            int h = heights[i];
            result = max(result, w * h);
        }

        return result;
    }
};

优化了双指针,在优化过程中用上了之前记录的nexl、nexr中的信息,降低了时间复杂度

class Solution {
public:
    int largestRectangleArea(vector<int>& heights) {
        int result = 0;
        vector<int> nexl(heights.size(), -1);
        vector<int> nexr(heights.size(), heights.size());

        for (int i = 0; i < heights.size(); i++){
            int j = i - 1;
            while (j >= 0 && heights[j] >= heights[i]) j = nexl[j];
            nexl[i] = j;
        } 

        for (int i = heights.size() - 1; i >= 0; i--){
            int j = i + 1;
            while (j < heights.size() && heights[j] >= heights[i]) j = nexr[j];
            nexr[i] = j;
        }
        
        for (int i = 0; i < heights.size(); i++){
            int w = nexr[i] - nexl[i] - 1;
            int h = heights[i];
            result = max(result, w * h);
        }

        return result;
    }
};

单调栈,和接雨水正好相反,是找元素两边第一个比本身小的,数组前后需要各插入一个0,避免递增或递减序列无法正确计算

class Solution {
public:
    int largestRectangleArea(vector<int>& heights) {
        int result = 0;
        heights.insert(heights.begin(), 0);
        heights.push_back(0);
        //heights.insert(heights.end(), 0);
        stack<int> st;
        st.push(0);

        for (int i = 1; i < heights.size(); i++){
            if (heights[i] > heights[st.top()]) st.push(i);
            else if (heights[i] == heights[st.top()]) {
                st.pop();
                st.push(i);
            }
            else{
                while(!st.empty() && heights[i] < heights[st.top()]){
                    int mid = st.top();
                    st.pop();
                    if (!st.empty()){
                        int w = i - st.top() - 1;
                        int h = heights[mid];
                        result = max(result, h * w);
                    }
                    
                }
                st.push(i);
            }
        }
        return result;
    }
};

第六十天打卡,撒花完结;
未来的路还很长,不管结果与否,既然选定了目标,就要坚持坚持坚持,起码不会辜负自己,加油!!!

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