2024/2/5

第四章  堆与拷贝构造函数

 一 、程序阅读题

1、给出下面程序输出结果。

#include

class example

{int a;

public:

example(int b=5){a=b++;}

void print(){a=a+1;cout <

void print()const

{cout<

};

void main()

{example x;

const example y(2);

x.print();       

y.print();       

}

答：6 2

2、运行程序，写出程序执行的结果。

#include

class Location

{   public:

int X,Y;

void init(int initX,int initY);

int GetX();

int GetY();

};

void Location::init (int initX,int initY)

{X=initX;

Y=initY;

}

int Location::GetX()

{return X;

}

int Location::GetY()

{return Y;

}

void display(Location& rL)

{cout<

}

void main()

{

Location A［5］={{5,5},{3,3},{1,1},{2,2},{4,4}};

Location *rA=A;

A［3］.init(7,3);

rA->init(7,8);

for (int i=0;i<5;i++)

display(*(rA++));

}

答：

7  8

3  3

1  1

7  3

4  4

3. 给出下面程序输出结果。

#include

int a[8］={1,2,3,4,5,6,7};

void fun(int *pa,int n);

void main()

{int m=8;

fun(a,m);

cout<

}

void fun(int *pa,int n)

{for (int i=0;i

*(pa+7)+=*(pa+i);

}

答：28

4. 给出下面程序输出结果。

#include

class A

{

int *a;

public:

A(int x=0):a(new int(x)){}

~A() {delete a;}

int getA() {return *a;}

void setA(int x) {*a=x;}

};

void main()

{

A x1,x2(3);

A *p=&x2;

(*p).setA(x2.getA()+5);

x1.setA(10+x1.getA());

cout<

}

答：10 8

5. 阅读下面的程序，写出运行结果：

#include < iostream.>

using namespace std;

class Samp

{

public:

    void Set_i_j(int a, int b){i=a,j=b;}

    ~Samp()

    {

        cout <<"Destroying.." << i <

    }

    int GetMulti () { return i * j; }

protected:

int i;

int j;

};

int main ()

{

Samp * p;

p = new Samp[l0];

if(!p)

{

cout << "Allocation error \ n";

return;

}

for(int j =0; j

    p[j]. Set_i_j (j, j);

for(int k=0; k

    cout <<"Multi[" <

delete [ ] p;

return 0;

}

答：

Multi[0] is:0

Multi[1] is:1

Multi[2] is:4

Multi[3] is:9

Multi[4] is:16

Multi[5] is:25

Multi[6] is:36

Multi[7] is:49

Multi[8] is:64

Multi[9] is:81

Destroying..9

Destroying..8

Destroying..7

Destroying..6

Destroying..5

Destroying..4

Destroying..3

Destroying..2

Destroying..1

Destroying..0 

6. 写出下面程序的运行结果，请用增加拷贝构造函数的方法避免存在的问题。

#include < iostream>

using namespace std;

class Vector

{

public:

    Vector (int s = 100);

    int& Elem(int ndx);

    void Display();

    void Set ();

    ~Vector ();

protected:

int size;

int* buffer;

}

Vector::Vector (int s)

{

buffer = new int [size = s];

for(int i = O; i

    buffer [i] = i* i;

}

int& Vector:: Elem(int ndx)

{

    if(ndx< 0 || ndx> = size)

    {

        cout << "error in index" <

        exit (1);

    }

    return buffer [ndx];

}

void Vector::Display ()

{

    for(int j =0; j< size; j ++)

    cout << buffer[j] <

}

void Vector:: Set ()

{

    for(int j =0; j

        buffer[j] = j + 1;

}

Vector:: ~ Vector()

{

    delete [] buffer;

}

int main()

{

    Vector a(10);

    Vector b(a);

    a. Set ();

    b. Display ();

return 0;

}

答：

1

1

4

9

16

25

36

49

64

81

7.读下面的程序与运行结果，添上一个拷贝构造函数来完善整个程序。

    

#include < iostream>

using namespace std;

class CAT

{

public:

    CAT();

    CAT(const CAT&);

    ~CAT();

    int GetAge() const (return * itsAge;)

    void SetAge(int age) { * itsAge = age; }

protected:

int * itsAge;

};

CAT::CAT ()

{

itsAge = new int;

*itsAge = 5;

}

CAT::~CAT ()

{

    delete itsAge;

    itsAge = 0;

}

void main()

{

    CAT frisky;

    cout << "frisky's age:" << frisky. GetAge() <

    cout <<"Setting frisky to 6... \ n";

    frisky. SetAge ( 6 );

    cout << "Creating boots from frisky \ n";

    CAT boots(frisky);

    cout <<"frisky's age:" << frisky. GetAge() <

    cout << "boots'age:" << boons. GetAge () <

    cout << "setting frisk,, to 7 .... n";

    frisky. SetAge (7);

    cout <<"frisky"s age:" << frisky. GetAge() <

    cout <<"boots' age:" << boots. GetAge() <

}

答：

   frisky's age:5

    Setting frisky to 6...

    Creating boots from frisky

    frisky's age:6

    boots' age:6

    Setting frisky to 7...

    frisky's age:7

    boots' age:6

添加

CAT::CAT(const CAT& other) {
    itsAge = new int;

    *itsAge = *other.itsAge;

}

CAT::~CAT() {
    delete itsAge;

    itsAge = 0;

}