Pythonchallenge一起来闯关

http://www.pythonchallenge.com/是一个在线的python过关游戏,一共有33关.玩这个游戏对熟悉python用法及相关库的使用都很有好处.

目前做到了第九关.python版本3.4. 操作系统版本32位win7,64位win7.

0.http://www.pythonchallenge.com/pc/def/0.html

计算2的38次方

1.http://www.pythonchallenge.com/pc/def/274877906944.html

提示已经很清楚了,简单的字符转换.可以使用str模块中的maketrans()和translate()方法.https://docs.python.org/3/library/stdtypes.html#str.translate

2.http://www.pythonchallenge.com/pc/def/ocr.html

页面源码里有注释：

<!--
	find rare characters in the mess below:
	-->

用到了re模块,这里有很好的关于re模块的使用说明,我觉得比官方文档要好读一些http://www.cnblogs.com/huxi/archive/2010/07/04/1771073.html

import urllib.request as ur

import re



url = "http://www.pythonchallenge.com/pc/def/ocr.html"



def main():

    global url



    response = ur.urlopen(url)

    body = response.read()



    text = re.search("<!--\n%(.|\s)+",body.decode())

    dic={}

    #print(text.group(0))

    for x in text.group(0):

        if x not in dic:

            dic[x] = 1

        else:

            dic[x] += 1 



    print(dic)

    for i in dic:

        if (dic[i]== 1 and 'a' <= i <='z'):

            print(i)



if __name__ == '__main__':

    main()

3.http://www.pythonchallenge.com/pc/def/equality.html

提示:One small letter, surrounded by EXACTLY three big bodyguards on each of its sides.

import urllib.request as ur

import re



url = "http://www.pythonchallenge.com/pc/def/equality.html"



def main():

    response = ur.urlopen(url)

    body = response.read()



    pattern="[^A-Z][A-Z][A-Z][A-Z]([a-z])[A-Z][A-Z][A-Z][^A-Z]"



    result = re.findall(pattern,body.decode())

    print(result)



if __name__ == '__main__':

    main()

4.http://www.pythonchallenge.com/pc/def/linkedlist.php

  查看页面源代码,可以看到提示有follow the chain,又有一个href,点击之后页面显示“next nothing is ....”猜想是不断地访问下一个url直到答案出现.

使用re模块时,注意match()与search()的区别：

Python offers two different primitive operations based on regular expressions:  re.match() checks for a match only at the beginning of the string, while  re.search() checks for a match anywhere in the string (this is what Perl does by default).

 

import urllib.request as ur

import re



url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=8022"



def main():

    global url

    global body

    while 1:    

        print(url)

        response = ur.urlopen(url)

        #print(type(response))



        body = response.read()

        #print(type(body))

        #print(body)

        #print(body.decode())



        pattern="and the next nothing is ([0-9]+)"

        #match从string的开头查找

        #search从string的anywhere开始找

        result = re.search(pattern,body.decode())

        #print(result)

        #m=re.match(r'and the next nothing is ([0-9]+)', body)

        #print(m)

        if result:

            num = result.group(1)

            print(result.group(0))

            print(num)

            url = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=%s" % num

        else:

            #print(type(result),result)

            break

    print(body)



if __name__ == '__main__':

    main()

5.http://www.pythonchallenge.com/pc/def/peak.html

  查看页面源代码有提示.peak hell sounds familiar.去翻翻标准库,看到一个模块叫pickle的.

  pickle模块用来实现python对象的序列化,反序列化.

import urllib.request as ur

import pickle





url = "http://www.pythonchallenge.com/pc/def/banner.p"



def main():

    global url



    httpresponse = ur.urlopen(url)

    dataBytes = httpresponse.read()



    obj = pickle.loads(dataBytes)

    #print(type(obj),obj)

    for ele in obj:

        #print(ele)

        s=""

        for i in ele:

            #print(i)

            #print(i[0]*i[1])

            s += i[0]*i[1]

        print(s)

        

if __name__ == '__main__':

    main()

6.http://www.pythonchallenge.com/pc/def/channel.html

    查看页面源代码,注释里有zip字样,去标准库里查查看有没有zip相关。

    输入url http://www.pythonchallenge.com/pc/def/channel.zip发现有一个channe.zip文件可以下载

    解压后读一下readme.txt。是类似于04的一直读文件下去,直到出现提示,collect comments。去翻标准库,发现一个zipfile.getinfo()的方法,原来打包的每个文件还可以有注释的,

    还真是第一次知道.

   

import urllib.request as ur

import zipfile

import pathlib

import re



url = "http://www.pythonchallenge.com/pc/def/channel.zip"





def main():

    # global url



    #下载zip文件并解压

    # httpresponse = ur.urlopen(url)

    # dataBytes = httpresponse.read()

    # with open("channel.zip", "wb") as local_file:

    #     if local_file.write(dataBytes):

    #         z = zipfile.ZipFile("channel.zip")

    #         z.extractall("./channel")



    # # p = pathlib.Path("./channel")

    # # for files in  p.iterdir():

    # #     #print(files,type(files))

    # #     #str = open(files).read()

    # #     str = files.open().read()

    # #     print(str)

    # #     break;



    #读取解压的文档获取提示



    z = zipfile.ZipFile("channel.zip")

    z.extractall("./channel")



    orderedFilePath=[]

    filepath = "./channel/90052.txt"

    filename = "90052.txt"

    while 1:

        orderedFilePath.append(filename)

        f = open(filepath)

        content = f.read()

        result = re.match("Next nothing is (\d+)",content)

        if result:

            num = result.group(1)

            #print(num)

            filepath = "./channel/%s.txt" % num

            filename = "%s.txt" % num

        else:

            #print(content)

            break



    print(orderedFilePath)

    for file in orderedFilePath:

        c = z.getinfo(file).comment.decode()

        print(c,end="")



if __name__ == '__main__':

    main()

7.http://www.pythonchallenge.com/pc/def/oxygen.html

这一关要用到图形库PIL.首先PIL官方版不支持py3,其次官方版不支持64位python.一番google之后,下载http://pillow.readthedocs.org/en/latest/installation.htmlpillow代替PIL

这题没什么思路,google以后知道是要读那些灰色块的像素值,再将其转码为对应的字符.

import urllib.request as ur

from PIL import Image



def ReadUrl(url):

    httpresponse = ur.urlopen(url)

    dataBytes = httpresponse.read()



    return dataBytes



def main():

    url = "http://www.pythonchallenge.com/pc/def/oxygen.png"

    databytes = ReadUrl(url)

    f = open("oxygen.png","wb")

    f.write(databytes)

    im = Image.open("oxygen.png")

    #print(im.size)

    (width,height) = im.size



    for i in range(0,width,1):    

        pos = (i,height/2)

        #pixel(49,49,49,255)前三位代表的是rgb的值.

        pixel = im.getpixel(pos)

        #ascii码转字符

        char = chr(pixel[0])

        print(char,end="")



    print(''.join(map(chr, [105, 110, 116, 101, 103, 114, 105, 116, 121])))



if __name__ == '__main__':

    main()

8.http://www.pythonchallenge.com/pc/def/integrity.html

页面源码里有一个链接,href="../return/good.html",点击之后发现要用户名和密码,恰好当前页面源码里有注释

<!--
	un: 'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'
	pw: 'BZh91AY&SY\x94$|\x0e\x00\x00\x00\x81\x00\x03$ \x00!\x9ah3M\x13<]\xc9\x14\xe1BBP\x91\xf08'
	-->

un,pw这不是username，password的缩写吗.最开始认为是和加密解密有关的,看了hashlib模块没有头绪,上网一搜原来是和压缩解压缩有关,BZh91AY&SY这是代表一种bzip2的压缩算法的.应该使用bz2模块..bz后缀的压缩文件还真没见过......

开始时把un,pw作为str处理发现不对,要作为bytes处理

import bz2



un=b'BZh91AY&SYA\xaf\x82\r\x00\x00\x01\x01\x80\x02\xc0\x02\x00 \x00!\x9ah3M\x07<]\xc9\x14\xe1BA\x06\xbe\x084'

pw=b'BZh91AY&SY\x94$|\x0e\x00\x00\x00\x81\x00\x03$ \x00!\x9ah3M\x13<]\xc9\x14\xe1BBP\x91\xf08'



def main():

       #username = bz2.decompress(un.decode("utf-8"))

        username=bz2.decompress(un)

        password=bz2.decompress(pw)

        print(username,password)



if __name__ == '__main__':

    main()

9.http://www.pythonchallenge.com/pc/return/good.html

提示1.要将这些点连起来,2.first+second=?

考虑获取点的坐标,重新画图。

import urllib.request as ur

from PIL import Image



def SaveImg(url,imgname):

    httpresponse = ur.urlopen(url)

    dataBytes = httpresponse.read()

    f = open(imgname,"wb")

    f.write(databytes)

    f.close()



first = [146,399,163,403,170,393,169,391,166,386,170,381,170,371,170,355,169,346,167,335,170,329,170,320,170,

310,171,301,173,290,178,289,182,287,188,286,190,286,192,291,194,296,195,305,194,307,191,312,190,316,

190,321,192,331,193,338,196,341,197,346,199,352,198,360,197,366,197,373,196,380,197,383,196,387,192,

389,191,392,190,396,189,400,194,401,201,402,208,403,213,402,216,401,219,397,219,393,216,390,215,385,

215,379,213,373,213,365,212,360,210,353,210,347,212,338,213,329,214,319,215,311,215,306,216,296,218,

290,221,283,225,282,233,284,238,287,243,290,250,291,255,294,261,293,265,291,271,291,273,289,278,287,

279,285,281,280,284,278,284,276,287,277,289,283,291,286,294,291,296,295,299,300,301,304,304,320,305,

327,306,332,307,341,306,349,303,354,301,364,301,371,297,375,292,384,291,386,302,393,324,391,333,387,

328,375,329,367,329,353,330,341,331,328,336,319,338,310,341,304,341,285,341,278,343,269,344,262,346,

259,346,251,349,259,349,264,349,273,349,280,349,288,349,295,349,298,354,293,356,286,354,279,352,268,

352,257,351,249,350,234,351,211,352,197,354,185,353,171,351,154,348,147,342,137,339,132,330,122,327,

120,314,116,304,117,293,118,284,118,281,122,275,128,265,129,257,131,244,133,239,134,228,136,221,137,

214,138,209,135,201,132,192,130,184,131,175,129,170,131,159,134,157,134,160,130,170,125,176,114,176,

102,173,103,172,108,171,111,163,115,156,116,149,117,142,116,136,115,129,115,124,115,120,115,115,117,

113,120,109,122,102,122,100,121,95,121,89,115,87,110,82,109,84,118,89,123,93,129,100,130,108,132,110,

133,110,136,107,138,105,140,95,138,86,141,79,149,77,155,81,162,90,165,97,167,99,171,109,171,107,161,

111,156,113,170,115,185,118,208,117,223,121,239,128,251,133,259,136,266,139,276,143,290,148,310,151,

332,155,348,156,353,153,366,149,379,147,394,146,399]



second = [156,141,165,135,169,131,176,130,187,134,191,140,191,146,186,150,179,155,175,157,168,157,163,157,159,

157,158,164,159,175,159,181,157,191,154,197,153,205,153,210,152,212,147,215,146,218,143,220,132,220,

125,217,119,209,116,196,115,185,114,172,114,167,112,161,109,165,107,170,99,171,97,167,89,164,81,162,

77,155,81,148,87,140,96,138,105,141,110,136,111,126,113,129,118,117,128,114,137,115,146,114,155,115,

158,121,157,128,156,134,157,136,156,136]



def main():

    coordinates = first + second

    im = Image.open("good.jpg")

    w,h = im.size

    mode = im.mode

    bands = im.getbands()

    print(type(mode),mode)

    print(type(bands),bands)



    #两两为一个像素点位置

    postions = []

    for x in range(0,len(coordinates),2):

        postion = (coordinates[x],coordinates[x+1])

        postions.append(postion)



    im2 = Image.new(mode,(w,h))

    for pos in postions:

        im2.putpixel(pos,(255,255,255))

    im2.save('09answer.jpg')



if __name__ == '__main__':

    main()