Artificial Intelligence

读取题目要求格式的字符串是个问题。

 1 /* UVa 537 - Artificial Intelligence? */
 2 # include <stdio.h>
 3 # include <ctype.h>
 4 # include <stdlib.h>
 5 
 6 typedef struct {
 7         double val;
 8         int vis;
 9 }phy;
10 
11 phy U, I, P, x;
12 int T;
13 char tmp[50];
14 
15 void getval(void);
16 
17 int main()
18 {
19     int i, c, t, j;
20         
21     scanf("%d", &T);
22     getchar();
23     for (i = 1; i <= T; ++i)
24     {
25         U.vis = I.vis = P.vis = 0;
26         printf("Problem #%d\n", i);
27         
28         getval();
29         
30         if (!U.vis) printf("U=%.2lfV\n", (P.val)/(I.val));
31         else if (!I.vis) printf("I=%.2lfA\n", (P.val)/(U.val));
32         else printf("P=%.2lfW\n", (U.val)*(I.val));
33         
34         printf("\n");
35     }    
36     return 0;
37 }
38 
39 void getval(void)
40 {
41      int j, c, t;
42      phy x;
43      
44      while ((c = getchar()) != EOF)
45      {
46          if (c == '\n') return ;
47          if (c == '=')
48          {
49              j = 0;
50              while (isdigit(c = getchar()) || c == '.')
51                    tmp[j++] = c;
52              tmp[j] = '\0';
53              
54              x.val = atof(tmp);
55              if (c == 'm') x.val /= 1000;
56              else if (c == 'k') x.val *= 1000;
57              else if (c == 'M') x.val *= 1000000;
58      
59              x.vis = 1;
60              if (t == 'U') U = x;
61              else if (t == 'I') I = x;
62              else P = x;
63          }
64          t = c;
65      }
66 }

一次 AC，加油！