mysql 复杂 语句_Mysql复杂查询语句汇总(仅供学习)

1、mysql查询今天、昨天、上周

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

#查询本季度数据

select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

#查询上季度数据

select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

#查询本年数据

select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());

#查询上年数据

select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查询距离当前现在6个月的数据

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查询上个月的数据

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select *

from user

where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *

from [ user ]

where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())

and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *

from [ user ]

where pudate between 上月最后一天

and 下月第一天

where date(regdate) = curdate();

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )

FROM `t_score`

WHERE 1

LIMIT 0 , 30

2 搜索选修课程是税收基础的学生信息

SELECTs.*

FROMc

JOINscONc.id=sc.cid

JOINsONs.id=sc.sid

WHEREc.cn='税收基础'

3 查询选修课程大于2门课的学生信息

SELECTm.*

FROM(

SELECTs.*,count(*)ASaaa

FROMs

JOINscONs.id=sc.sid

)m

或者

SELECTs.*,count(*)

FROMs

JOINscONs.id=sc.sid

HAVINGcount(*)>3

4 查询学员朱欣磊选修的课程信息

SELECTs.*

FROMs

JOINscONs.id=sc.sid

WHEREs.sn='朱欣磊'

5 查询没有选择数学课的学生信息

SELECT*

FROMs

WHEREidNOT

IN(

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

WHEREc.cn='数学'

)

先查找的选修了数学的学生,然后排除的

6 查询没门课选修的人数

SELECTcn,count(*)

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

GROUPBY cn

7 查询每个学员选修了几门课程

SELECTsn,count(*)

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

GROUPBYsn

8 查询选修课程不及格的学生信息及课程信息

SELECT*

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

WHEREsc.g<60

9查询各门课的平均成绩,输出课程名及平均成绩,最高,最低

SELECTc.cn,avg(g),max(g),min(g)

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

GROUPBYcn

10 查询至少有两人选修的课程

SELECTcn

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

GROUPBYcn

HAVINGcount(*)>2

11查询税收基础成绩不低于平均成绩的学生信息及其成绩

SELECTsn,sc.g

FROMs

JOINscONs.id=sc.sid

JOINcONc.id=sc.cid

GROUPBYcn

HAVINGsc.g>avg(sc.g)

这样写是不正确的,这里

SELECT *

FROM s

JOIN sc ON s.id=sc.sid

JOIN c ON c.id=sc.cid

where c.cn = '税收基础' and g > (select avg(g) from sc where cid = 1)

12 查询年龄是21岁的平均成绩最高的学生信息

select max(abc.aaa) from (select sa,avg(g) as aaa from s join sc on World's shortest URL shortener = sc.sid join c on c.id = sc.cid group by World's shortest URL shortener) as abc where Automated Buildings Company = 21

13 查询选修过课的学生的总人数

select *,count(*) from sc group by sc.sid

这是不行的,这种写法以为是以学生来分类的,所以取出的是每个学生选修了几门课

select count(*) from (select *,count(*) from sc group by sc.sid)

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