每个缩进的代码行都是循环的一部分,且将针对列表中的每个值都执行一次。因此,可对列表中的每个值执行任意次数的操作。
magicians = ['alice', 'david', 'carolina']
for magician in magicians:
print(magician)
注意:
# 遍历的时候下面没有缩进的代码行-->会报错
magicians = ['alice', 'david', 'carolina']
for magician in magicians:
magicians = ['alice', 'david', 'carolina']
for magician in magicians:
print(magician)
print(magician.title() + ", that was a great trick!")
##输出结果为如下展示:
alice
Alice, that was a great trick!
david
David, that was a great trick!
carolina
Carolina, that was a great trick!
遍历完毕的时候,如果下面打印的内容没有缩。那么只会执行一次,且值为列表末尾的值
magicians = ['alice', 'david', 'carolina']
for magician in magicians:
print(magician)
print(magician.title() + ", that was a great trick!")
#输出结果为如下展示:
alice
david
carolina
Carolina, that was a great trick!
#输出1 2 3 4
for value in range(1,5):
print(value)
#输出1 2 3 4 5
for value in range(1,6):
print(value)
range(startNumber,endNumber,stepLength)
startNumber:开始的数字;
endNumber:结束的最大数字,且要比startNumber大;
stepLength:一次累加多少;
even_numbers = list(range(2,11,2))
print(even_numbers)
#输出结果
[2, 4, 6, 8, 10]
>>> digits = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
>>> min(digits)
0
>>> max(digits)
9
>>> sum(digits)
45
前面介绍的生成列表 squares 的方式包含三四行代码,而列表解析让你只需编写一行代码就能生成这样的列表。 列表解析 将 for 循环和创建新元素的代码合并成一行,并自动
附加新元素。面向初学者的书籍并非都会介绍列表解析,这里之所以介绍列表解析,是因为等你开始阅读他人编写的代码时,很可能会遇到它们。
请注意,这里的 for 语句末尾没有冒号。
squares = [value**2 for value in range(1,11)]
print(squares)
#输出结果:
[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
切片:列表的一部分;
[startstep]
start:开始截取的位置,截取的内容包含该位置。
end:结束截取的位置,截取的内容不包含该结束位置。
step:截取的步长,默认值为1。step为正的时候,代表从左到右截取。step为负的时候,从右到左反向截取
例如:
[:]:提取从开头到结尾的整个字符串的全部内容;
[start:]:从start下标字符串开始截取,直到字符串的末尾(包含末尾字符);
[:end]:从字符串的开始字符截取,直到下标end结束(不包含这个end下标);
[start:end]:从start下标开始截取,直到下标end结束(不包含这个end下标);
[startstep]:从start下标字符串开始截取,直到下标end结束(不包含这个end下标),步长为step;
[::2]:每隔一个输出内容;
[::-1]:将内容反序输出;
[-2:-8:-1]:将从下标-2开始(包含自己),直到下标-8(不包含自己)结束内容反序输出;
备注:反序输出的时候start一定要在end的右边
从下标X开始,到下标Y结束,但是不包含下标Y的值
# 从下标0开始,输出到下标3的值结束,但是不包含下标3的值
players = ['charles', 'martina', 'michael', 'florence', 'eli']
print(players[0:3])
#输出结果:
['charles', 'martina', 'michael']
players = ['charles', 'martina', 'michael', 'florence', 'eli']
print(players[:4])
#输出结果:
['charles', 'martina', 'michael', 'florence']
①开始的下标是正数
players = ['charles', 'martina', 'michael', 'florence', 'eli']
print(players[2:])
#输出结果:
['michael', 'florence', 'eli']
②开始的下标是负数
# 输出倒数三个值
players = ['charles', 'martina', 'michael', 'florence', 'eli']
print(players[-3:])
#输出结果:
['michael', 'florence', 'eli']
如果下标都是负数,那么最后一位的下标是从-1开始计算的
#从下标-8的地方(倒数第八个)开始,直到下标-2结束(不包含下标-2的那个值)
s="欢迎大家来到我的博客学习python课程"
result=s[-8:-2]#下标-8的值是p;下标-2的值是"课",但是不包含"课"
result=s[-2:-8:-1]#下标-2的值是"课";下标-8的值p,但是不包含p;反序输出
print(result)
# 输出
python
课nohty
输出前三个队员的姓名
players = ['charles', 'martina', 'michael', 'florence', 'eli']
print("Here are the first three players on my team:")
for player in players[:3]:
print(player.title())
friend_foods = my_foods
my_foods = ['pizza', 'falafel', 'carrot cake']
friend_foods = my_foods
my_foods.append('cannoli')
friend_foods.append('ice cream')
print(my_foods)
print(friend_foods)
# 输出结果:
['pizza', 'falafel', 'carrot cake', 'cannoli', 'ice cream']
['pizza', 'falafel', 'carrot cake', 'cannoli', 'ice cream']
friend_foods = my_foods[:]
my_foods = ['pizza', 'falafel', 'carrot cake']
friend_foods = my_foods[:]
my_foods.append('cannoli')
friend_foods.append('ice cream')
print(my_foods)
print(friend_foods)
# 输出结果:
['pizza', 'falafel', 'carrot cake', 'cannoli']
['pizza', 'falafel', 'carrot cake', 'ice cream']
总结:
1.friend_foods = my_foods
是将地址给了另外一个列表,他们都共同指向了一个相同的地址;
2.friend_foods = my_foods[:]
是将my_foods的元素都复制了一份到friend_foods 中;然后他们互相之间互不影响;