Time Limit: 5000MS Memory Limit: 65536K
Total Submissions: 3409 Accepted: 1514
Description
Consider equations having the following form:
a1x13+ a2x23+ a3x33+ a4x43+ a5x53=0
The coefficients are given integers from the interval [-50,50].
It is consider a solution a system (x1, x2, x3, x4, x5) that verifies the equation, xi∈[-50,50], xi != 0, any i∈{1,2,3,4,5}.
Determine how many solutions satisfy the given equation.
Input
The only line of input contains the 5 coefficients a1, a2, a3, a4, a5, separated by blanks.
Output
The output will contain on the first line the number of the solutions for the given equation.
Sample Input
37 29 41 43 47
Sample Output
654
Source
Romania OI 2002
//
POJ1840.cpp : Defines the entry point for the console application.
//
#include
<
iostream
>
using
namespace
std;
struct
Node
{
Node():count(
0
), num(
0
), next(NULL){}
int
num;
int
count;
Node
*
next;
};
int
main(
int
argc,
char
*
argv[])
{
int
a[
5
];
cin
>>
a[
0
]
>>
a[
1
]
>>
a[
2
]
>>
a[
3
]
>>
a[
4
];
const
int
SIZE
=
33119
;
Node hash[SIZE];
//
create lookup table
int
X[
51
];
for
(
int
i
=
0
; i
<=
50
;
++
i) X[i]
=
i
*
i
*
i;
//
init hash table
for
(
int
i
=
-
50
; i
<=
50
;
++
i)
for
(
int
j
=
-
50
; j
<=
50
;
++
j)
if
(i
!=
0
&&
j
!=
0
)
{
int
num
=
a[
0
]
*
(i
<
0
?
-
X[
-
i]:X[i])
+
a[
1
]
*
(j
<
0
?
-
X[
-
j]:X[j]);
int
key
=
num
%
SIZE;
if
(key
<
0
) key
+=
SIZE;
Node
*
pt
=
&
hash[key];
bool
found
=
false
;
while
(pt
->
next
!=
NULL)
{
pt
=
pt
->
next;
if
(pt
->
num
==
num)
{
++
(pt
->
count);
found
=
true
;
break
;
}
}
if
(found
==
false
)
{
Node
*
pc
=
new
Node;
pc
->
count
=
1
;
pc
->
num
=
num;
pt
->
next
=
pc;
};
};
//
search hash table and find match
int
cnt
=
0
;
for
(
int
i
=
-
50
; i
<=
50
;
++
i)
for
(
int
j
=
-
50
; j
<=
50
;
++
j)
for
(
int
k
=
-
50
; k
<=
50
;
++
k)
if
(i
!=
0
&&
j
!=
0
&&
k
!=
0
)
{
int
num
=
-
(a[
2
]
*
(i
<
0
?
-
X[
-
i]:X[i])
+
a[
3
]
*
(j
<
0
?
-
X[
-
j]:X[j])
+
a[
4
]
*
(k
<
0
?
-
X[
-
k]:X[k]));
int
key
=
num
%
SIZE;
if
(key
<
0
) key
+=
SIZE;
Node
*
pt
=
&
hash[key];
while
(pt
->
next
!=
NULL)
{
pt
=
pt
->
next;
if
(pt
->
num
==
num)
{
cnt
+=
pt
->
count;
break
;
}
}
};
cout
<<
cnt
<<
endl;
return
0
;
}