HDU 1033 Edge

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分析：一道简单的模拟题、就是题目英文有点长、各种蛋疼、让你V和A分别逆时针旋转和顺时针旋转、然后输出转过之后的坐标就OK了、

 

#include<stdio.h>

#include<string.h>

#include<stdio.h>

#include<iostream>

using namespace std;

char st[205];

int flag,x,y;

void move(int &x,int &y,int &flag,char dict){

    if(flag==0){

        if(dict=='A'){

            x=x+10;

            y=y;

            flag=1;

        }

        else{

            x=x-10;

            y=y;

            flag=3;

        }

    }

    else if(flag==1){

        if(dict=='A'){

            x=x;

            y=y-10;

            flag=2;

        }

        else{

            x=x;

            y=y+10;

            flag=0;

        }

    }

    else if(flag==2){

        if(dict=='A'){

            x=x-10;

            y=y;

            flag=3;

        }

        else{

            x=x+10;

            y=y;

            flag=1;

        }

    }

    else{

        if(dict=='A'){

            x=x;

            y=y+10;

            flag=0;

        }

        else{

            x=x;

            y=y-10;

            flag=2;

        }

    }

}

int main(){

    while(scanf("%s",&st)!=EOF){

        printf("300 420 moveto\n310 420 lineto\n");

        int len=strlen(st);

        flag=1;

        int i;

        x=310;y=420;

        for(i=0;i<len;i++){

            move(x,y,flag,st[i]);

            printf("%d %d lineto\n",x,y);

        }

        printf("stroke\nshowpage\n");

    }

    return 0;

}