poj 1006 Biorhythms

Time Limit: 1000MS		Memory Limit: 10000K
Total Submissions: 67911		Accepted: 19964

本题虽然非常简单，但是陷阱却很难发现

下面给几组例子：（据说只要能过这几组例子就能A过）

 

0 4 5 0                368
2 2 2 2                21252
123 128 133 1     99
123 128 133 100 21252
0 1 2 1               16996
1 0 2 1               8119
1 2 0 1               13133
1 2 3 0               16998
117 58 2 27        21227
尤其最后一组例子，很容易被忽略

代码：

 

  
    

   
     
   
      1 
   
     #include
   
     <
   
     stdio.h
   
     >
   
     

   
      2 
   
      
   
     int
   
      main()

   
      3 
   
     {

   
      4 
   
      
   
     int
   
      p,e,i,j,d,count
   
     =
   
     0
   
     ,s;

   
      5 
   
      
   
     while
   
     (scanf(
   
     "
   
     %d%d%d%d
   
     "
   
     ,
   
     &
   
     p,
   
     &
   
     e,
   
     &
   
     i,
   
     &
   
     d)
   
     !=
   
     EOF)

   
      6 
   
      {

   
      7 
   
      count
   
     ++
   
     ;

   
      8 
   
      
   
     if
   
     (p
   
     ==-
   
     1
   
     &&
   
     e
   
     ==-
   
     1
   
     &&
   
     i
   
     ==-
   
     1
   
     &&
   
     d
   
     ==-
   
     1
   
     )

   
      9 
   
      
   
     break
   
     ;

   
     10 
   
      s
   
     =
   
     21252
   
     +
   
     d;

   
     11 
   
      
   
     for
   
     (j
   
     =
   
     1
   
     ;j
   
     <=
   
     s;j
   
     ++
   
     )

   
     12 
   
      {

   
     13 
   
      
   
     if
   
     ((j
   
     -
   
     p)
   
     %
   
     23
   
     ==
   
     0
   
      
   
     &&
   
      (j
   
     -
   
     e)
   
     %
   
     28
   
     ==
   
     0
   
      
   
     &&
   
      (j
   
     -
   
     i)
   
     %
   
     33
   
     ==
   
     0
   
     )

   
     14 
   
      {

   
     15 
   
      
   
     if
   
     ((j
   
     -
   
     d)
   
     <=
   
     0
   
     )

   
     16 
   
      
   
     continue
   
     ;

   
     17 
   
      
   
     else
   
     

   
     18 
   
      
   
     break
   
     ;

   
     19 
   
      }

   
     20 
   
      }

   
     21 
   
      
   
     if
   
     (j
   
     >
   
     s)

   
     22 
   
      printf(
   
     "
   
     Case %d: the next triple peak occurs in 21252 days.\n
   
     "
   
     ,count);

   
     23 
   
      
   
     else
   
     

   
     24 
   
      printf(
   
     "
   
     Case %d: the next triple peak occurs in %d days.\n
   
     "
   
     ,count,j
   
     -
   
     d);

   
     25 
   
      }

   
     26 
   
      
   
     return
   
      
   
     0
   
     ;

   
     27 
   
     }

   
     28