ZZU省赛 第一题 奇怪排序

一开始拿到这道题时，有点纠结排序后的字符串不知道怎么转回来，最后经别人提醒我把字符和数绑定成一个数组就可以了

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 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #include<string.h>
 4 #include<math.h>
 5 
 6 int i;
 7 typedef struct
 8 {
 9    char s[10];
10    int n;
11 }numble;
12 numble num[51];
13       
14 char word[51][10], sort[51];
15 void reverse(int x)
16 {
17      int t=0;
18      char c[10];
19      while( x != 0)
20      {
21         c[t] = x%10 + '0';
22         x = x/10;    
23         t++;    
24      } 
25      c[t] = '\0';   
26      strcpy(word[i++],c);       
27 }
28 
29 int cmp_string(const void *_a,const void *_b)
30 { 
31     char* a = (char*) _a;
32     char* b = (char*) _b;
33     if(strlen(a) != strlen(b)) 
34       return strlen(a) - strlen(b);
35     else 
36       return strcmp(a,b);
37 }
38   
39 int cmp(const void *a,const void *b)
40 {
41     return  (*(numble *)a).n > (*(numble *)b).n ? 1 : -1;
42 }
43   
44 int main()
45 {
46     int j, k, A, B, ncases;
47     int len,n,sum,m; 
48     
49     scanf("%d",&ncases);
50     while( ncases-- )
51     {
52        scanf("%d%d",&A,&B);
53        i = 0; 
54        for(j=A; j<=B; j++)
55        {   
56            reverse(j);    
57        }     
58        n = B-A+1; 
59        qsort(word,n,sizeof(word[0]),cmp_string);
60        for(j=0; j<n; j++)
61        {
62                m = 0; 
63            strcpy(num[j].s,word[j]);    
64           for(k=0; k<strlen(word[j]); k++)
65           {
66               m = m*10 + word[j][k]-'0';
67           }                
68           num[j].n = m;
69        }
70        qsort(num,n,sizeof(numble),cmp);       
71        for(k=0; k<n; k++) 
72        { 
73          len = strlen(num[k].s);
74          sum = 0; 
75          for(j=len-1; j>=0; j--) 
76          { 
77            sum = sum*10 + num[k].s[j]-'0'; 
78          } 
79          printf("%d",sum); 
80          if(k != n)
81            printf(" ");  
82        }
83        printf("\n");   
84     } 
85       return 0;
86 }