数据库和xml协同工作（2）

1。用xml控件来显示数据库信息：

后台：

DataSetds = new DAL.JPDataAccess( " Select*fromArticle " ).IDs;

XmlDataDocumentxdd = new XmlDataDocument(ds);

Xml1.Document = xdd;
Xml1.TransformSource = (MapPath( " TransformArticle.xsl " ));

TransformArticle.xsl：

<? xmlversion="1.0"encoding="utf-8" ?>

< xsl:stylesheet version ="1.0"
xmlns:xsl ="http://www.w3.org/1999/XSL/Transform" >

< xsl:template match ="Table" >
< p >
< table width ="100%" border ="1" cellpadding ="10" >
< tr >
< td bgColor ="yellow" >
< strong >
< xsl:value-of select ="articleTitle" />
</ strong >
</ td >
</ tr >
< tr >
< td bgColor ="#eeeeee" >
< xsl:value-of select ="content" />
</ td >
</ tr >
</ table >
</ p >
</ xsl:template >

</ xsl:stylesheet >

2。不用xml控件，同时把数据库转换来的表以xml+xsl输出：

DataSetds = new DAL.JPDataAccess( " select*fromArticle " ).IDs;

// 写入输出流
XmlDataDocumentxdd = new XmlDataDocument(ds);
// XslTransformxtf=newXslTransform();
XslCompiledTransformxtf = new XslCompiledTransform();
xtf.Load(MapPath( " TransformArticle.xsl " ));
xtf.Transform(xdd, new XsltArgumentList(),Response.OutputStream);

// 写入文件
StreamWritersw = new StreamWriter(MapPath( " transformed.txt " ));
xtf.Transform(xdd, new XsltArgumentList(),sw);
sw.Close();