C++ 对象的内存布局（下）
C++ 对象的内存布局(下)<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />
陈皓
重复继承
下面我们再来看看，发生重复继承的情况。所谓重复继承，也就是某个基类被间接地重复继承了多次。
下图是一个继承图，我们重载了父类的f()函数。
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其类继承的源代码如下所示。其中，每个类都有两个变量，一个是整形（4字节），一个是字符（1字节），而且还有自己的虚函数，自己overwrite父类的虚函数。如子类D中，f()覆盖了超类的函数， f1() 和f2() 覆盖了其父类的虚函数，Df()为自己的虚函数。
class B
{
public:
int ib;
char cb;
public:
B():ib(0),cb('B') {}
virtual void f() { cout << "B::f()" << endl;}
virtual void Bf() { cout << "B::Bf()" << endl;}
};
class B1 : public B
{
public:
int ib1;
char cb1;
public:
B1():ib1(11),cb1('1') {}
virtual void f() { cout << "B1::f()" << endl;}
virtual void f1() { cout << "B1::f1()" << endl;}
virtual void Bf1() { cout << "B1::Bf1()" << endl;}
};
class B2: public B
{
public:
int ib2;
char cb2;
public:
B2():ib2(12),cb2('2') {}
virtual void f() { cout << "B2::f()" << endl;}
virtual void f2() { cout << "B2::f2()" << endl;}
virtual void Bf2() { cout << "B2::Bf2()" << endl;}
};
class D : public B1, public B2
{
public:
int id;
char cd;
public:
D():id(100),cd('D') {}
virtual void f() { cout << "D::f()" << endl;}
virtual void f1() { cout << "D::f1()" << endl;}
virtual void f2() { cout << "D::f2()" << endl;}
virtual void Df() { cout << "D::Df()" << endl;}
};
我们用来存取子类内存布局的代码如下所示：（在VC++ 2003和G++ 3.4.4下）
typedef void(*Fun)(void);
int** pVtab = NULL;
Fun pFun = NULL;
D d;
pVtab = (int**)&d;
cout << "[0] D::B1::_vptr->" << endl;
pFun = (Fun)pVtab[0][0];
cout << " [0] "; pFun();
pFun = (Fun)pVtab[0][1];
cout << " [1] "; pFun();
pFun = (Fun)pVtab[0][2];
cout << " [2] "; pFun();
pFun = (Fun)pVtab[0][3];
cout << " [3] "; pFun();
pFun = (Fun)pVtab[0][4];
cout << " [4] "; pFun();
pFun = (Fun)pVtab[0][5];
cout << " [5] 0x" << pFun << endl;
cout << "[1] B::ib = " << (int)pVtab[1] << endl;
cout << "[2] B::cb = " << (char)pVtab[2] << endl;
cout << "[3] B1::ib1 = " << (int)pVtab[3] << endl;
cout << "[4] B1::cb1 = " << (char)pVtab[4] << endl;
cout << "[5] D::B2::_vptr->" << endl;
pFun = (Fun)pVtab[5][0];
cout << " [0] "; pFun();
pFun = (Fun)pVtab[5][1];
cout << " [1] "; pFun();
pFun = (Fun)pVtab[5][2];
cout << " [2] "; pFun();
pFun = (Fun)pVtab[5][3];
cout << " [3] "; pFun();
pFun = (Fun)pVtab[5][4];
cout << " [4] 0x" << pFun << endl;
cout << "[6] B::ib = " << (int)pVtab[6] << endl;
cout << "[7] B::cb = " << (char)pVtab[7] << endl;
cout << "[8] B2::ib2 = " << (int)pVtab[8] << endl;
cout << "[9] B2::cb2 = " << (char)pVtab[9] << endl;
cout << "[10] D::id = " << (int)pVtab[10] << endl;
cout << "[11] D::cd = " << (char)pVtab[11] << endl;
程序运行结果如下：
| GCC 3.4.4 |
VC++ 2003 |
| [0] D::B1::_vptr-> [0] D::f() [1] B::Bf() [2] D::f1() [3] B1::Bf1() [4] D::f2() [5] 0x1 [1] B::ib = 0 [2] B::cb = B [3] B1::ib1 = 11 [4] B1::cb1 = 1 [5] D::B2::_vptr-> [0] D::f() [1] B::Bf() [2] D::f2() [3] B2::Bf2() [4] 0x0 [6] B::ib = 0 [7] B::cb = B [8] B2::ib2 = 12 [9] B2::cb2 = 2 [10] D::id = 100 [11] D::cd = D |
[0] D::B1::_vptr-> [0] D::f() [1] B::Bf() [2] D::f1() [3] B1::Bf1() [4] D::Df() [5] 0x00000000 [1] B::ib = 0 [2] B::cb = B [3] B1::ib1 = 11 [4] B1::cb1 = 1 [5] D::B2::_vptr-> [0] D::f() [1] B::Bf() [2] D::f2() [3] B2::Bf2() [4] 0x00000000 [6] B::ib = 0 [7] B::cb = B [8] B2::ib2 = 12 [9] B2::cb2 = 2 [10] D::id = 100 [11] D::cd = D |
下面是对于子类实例中的虚函数表的图：
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我们可以看见，最顶端的父类B其成员变量存在于B1和B2中，并被D给继承下去了。而在D中，其有B1和B2的实例，于是B的成员在D的实例中存在两份，一份是B1继承而来的，另一份是B2继承而来的。所以，如果我们使用以下语句，则会产生二义性编译错误：
D d;
d.ib = 0;//二义性错误
d.B1::ib = 1; //正确
d.B2::ib = 2; //正确
注意，上面例程中的最后两条语句存取的是两个变量。虽然我们消除了二义性的编译错误，但B类在D中还是有两个实例，这种继承造成了数据的重复，我们叫这种继承为重复继承。重复的基类数据成员可能并不是我们想要的。所以，C++引入了虚基类的概念。
钻石型多重虚拟继承
虚拟继承的出现就是为了解决重复继承中多个间接父类的问题的。钻石型的结构是其最经典的结构。也是我们在这里要讨论的结构：
上述的“重复继承”只需要把B1和B2继承B的语法中加上virtual 关键，就成了虚拟继承，其继承图如下所示：
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上图和前面的“重复继承”中的类的内部数据和接口都是完全一样的，只是我们采用了虚拟继承：其省略后的源码如下所示：
class B {……};
class B1 : virtual public B{……};
class B2: virtual public B{……};
class D : public B1, public B2{ …… };
在查看D之前，我们先看一看单一虚拟继承的情况。下面是一段在VC++2003下的测试程序：（因为VC++和GCC的内存而局上有一些细节上的不同，所以这里只给出VC++的程序，GCC下的程序大家可以根据我给出的程序自己仿照着写一个去试一试）：
int** pVtab = NULL;
Fun pFun = NULL;
B1 bb1;
pVtab = (int**)&bb1;
cout << "[0] B1::_vptr->" << endl;
pFun = (Fun)pVtab[0][0];
cout << " [0] ";
pFun(); //B1::f1();
cout << " [1] ";
pFun = (Fun)pVtab[0][1];
pFun(); //B1::bf1();
cout << " [2] ";
cout << pVtab[0][2] << endl;
cout << "[1] = 0x";
cout << (int*)*((int*)(&bb1)+1) <<endl; //B1::ib1
cout << "[2] B1::ib1 = ";
cout << (int)*((int*)(&bb1)+2) <<endl; //B1::ib1
cout << "[3] B1::cb1 = ";
cout << (char)*((int*)(&bb1)+3) << endl; //B1::cb1
cout << "[4] = 0x";
cout << (int*)*((int*)(&bb1)+4) << endl; //NULL
cout << "[5] B::_vptr->" << endl;
pFun = (Fun)pVtab[5][0];
cout << " [0] ";
pFun(); //B1::f();
pFun = (Fun)pVtab[5][1];
cout << " [1] ";
pFun(); //B::Bf();
cout << " [2] ";
cout << "0x" << (Fun)pVtab[5][2] << endl;
cout << color: ol