Boyer–Moore string search algorithm（java）
package com.test.bmsearch;
public class Bm {
public static void main(String[] args) {
System.out.println(indexOf("asdasdas".toCharArray(),"das".toCharArray()));
}
/**
* Returns the index within this string of the first occurrence of the
* specified substring. If it is not a substring, return -1.
*
* @param haystack The string to be scanned
* @param needle The target string to search
* @return The start index of the substring
*/
public static int indexOf(char[] haystack, char[] needle) {
if (needle.length == 0) {
return 0;
}
int charTable[] = makeCharTable(needle);
int offsetTable[] = makeOffsetTable(needle);
for (int i = needle.length - 1, j; i < haystack.length;) {
for (j = needle.length - 1; needle[j] == haystack[i]; --i, --j) {
if (j == 0) {
return i;
}
}
// i += needle.length - j; // For naive method
i += Math.max(offsetTable[needle.length - 1 - j], charTable[haystack[i]]);
}
return -1;
}
/**
* Makes the jump table based on the mismatched character information.
*/
private static int[] makeCharTable(char[] needle) {
final int ALPHABET_SIZE = 256;
int[] table = new int[ALPHABET_SIZE];
for (int i = 0; i < table.length; ++i) {
table[i] = needle.length;
}
for (int i = 0; i < needle.length - 1; ++i) {
table[needle[i]] = needle.length - 1 - i;
}
return table;
}
/**
* Makes the jump table based on the scan offset which mismatch occurs.
*/
private static int[] makeOffsetTable(char[] needle) {
int[] table = new int[needle.length];
int lastPrefixPosition = needle.length;
for (int i = needle.length - 1; i >= 0; --i) {
if (isPrefix(needle, i + 1)) {
lastPrefixPosition = i + 1;
}
table[needle.length - 1 - i] = lastPrefixPosition - i + needle.length - 1;
}
for (int i = 0; i < needle.length - 1; ++i) {
int slen = suffixLength(needle, i);
table[slen] = needle.length - 1 - i + slen;
}
return table;
}
/**
* Is needle[p:end] a prefix of needle?
*/
private static boolean isPrefix(char[] needle, int p) {
for (int i = p, j = 0; i < needle.length; ++i, ++j) {
if (needle[i] != needle[j]) {
return false;
}
}
return true;
}
/**
* Returns the maximum length of the substring ends at p and is a suffix.
*/
private static int suffixLength(char[] needle, int p) {
int len = 0;
for (int i = p, j = needle.length - 1;
i >= 0 && needle[i] == needle[j]; --i, --j) {
len += 1;
}
return len;
}
}