嵌入式C语言函数指针数组

#include <stdio.h>
typedef int (*fun_t)(int , int);

/*构造一个枚举值对应的操作符标示(ID)*/
enum{


    OPER_ADD = 0,
    OPER_SUB,
    OPER_MUL,
    OPER_DIV,
    OPER_NUM            //操作符个数
};
int add(int a,int b)
{
    return (a + b);
}

int sub(int a,int b)
{
    return (a - b);
}

int mul(int a,int b)
{
    return (a * b);
}

int div(int a,int b)
{
    return (int)(a / b);
}

static const fun_t oper_table[OPER_NUM] = {
    add,
    sub,
    mul,
    div
};

int main(int argc ,char **argv)
{
    int a , b , result;
    a = 100;
    b = 20;

    /* use table operation : Add */
    result = oper_table[OPER_ADD](a,b);
    printf("Table operation : %d + %d = %d\n" , a , b , result);

    /* use table operation : Sub */
    result = oper_table[OPER_SUB](a,b);
    printf("Table operation : %d + %d = %d\n" , a , b , result);

    /* use table operation : Multiply */
    result = oper_table[OPER_MUL](a,b);
    printf("Table operation : %d + %d = %d\n" , a , b , result);

    /* use table operation : Divide */
    result = oper_table[OPER_DIV](a,b);
    printf("Table operation : %d + %d = %d\n" , a , b , result);

    return 0;
}