C++ Templates中的例子编译不过的原因

 此例子来源于《C++Templates The Complete Guide》，
使用了两种编译器(gcc 3.4.4, Dev-C++ 4.9.9.2)，都出现如下错误：

C++ Templates中的functor源代码。编译其中的一个cpp文件（compose6.cpp）即可。
下载地址：
[url]http://www.josuttis.com/tmplbook/examples.zip[/url]

编译错误：
dell@dell - PC / cygdrive / g / cyghome / src / cpptemplates / functors $ make g ++ .exe  compose6.cpp - o test.exe
In file included from forwardparam.hpp: 15 ,
                 from functionptr.hpp: 11 ,
                 from funcptr.hpp: 11 ,
                 from compose6.cpp: 12 :
typet.hpp: 73 : error: expected primary - expression before ' > ' token
typet.hpp: In instantiation of `IsFunctionT < double > ' :
typet.hpp: 105 :   instantiated from `CompoundT < double > '
typet.hpp: 290 :   instantiated from `TypeT < double > '
forwardparam.hpp: 29 :   instantiated from `ForwardParamT < double > '
functionptr.hpp: 39 :   instantiated from `FunctionPtr < double , double , double , voi
d > '
compose6.cpp: 29 :   instantiated from here
typet.hpp: 73 : error: enumerator value for `Yes ' not integer constant
make: *** [test.exe] Error 1

  
  
  
  

   
   
   
   
   
   
   
    
  
  
  
  
  
  
  
  

   
   
   
   解决方法：去掉IsFunctionT<T>::
  
  
  
  
  
  
  
  

   
   
   
    
    
 
     
 
      
 
       
 
         //enum { Yes = sizeof(IsFunctionT<T>::test<T>(0)) == 1 };   
       
 
       

           //error: expected primary-expression before '>' token 
        
 
             enum { Yes = sizeof(test<T>(0)) == 1 };