【非原创】C语言金典实例程序91-100(个人收集)

【程序91】
题目:时间函数举例1
1.程序分析:
2.程序源代码:
#include "stdio.h"
#include "conio.h"
#include "time.h"
void main()
{
  time_t lt; /*define a longint time varible*/
  lt=time(NULL);/*system time and date*/
  printf(ctime(&lt)); /*english format output*/
  printf(asctime(localtime(&lt)));/*tranfer to tm*/
  printf(asctime(gmtime(&lt))); /*tranfer to Greenwich time*/
  getch();
}
==============================================================
【程序92】
题目:时间函数举例2
1.程序分析:           
2.程序源代码:
/*calculate time*/
#include "time.h"
#include "stdio.h"
#include "conio.h"
main()
{
  time_t start,end;
  int i;
  start=time(NULL);
  for(i=0;i<30000;i++)
    printf("\1\1\1\1\1\1\1\1\1\1\n");
  end=time(NULL);
  printf("\1: The different is %6.3f\n",difftime(end,start));
  getch();
}
==============================================================
【程序93】
题目:时间函数举例3
1.程序分析:
2.程序源代码:
/*calculate time*/
#include "time.h"
#include "stdio.h"
#include "conio.h"
main()
{
  clock_t start,end;
  int i;
  double var;
  start=clock();
  for(i=0;i<10000;i++)
    printf("\1\1\1\1\1\1\1\1\1\1\n");
  end=clock();
  printf("\1: The different is %6.3f\n",(double)(end-start));
  getch();
}
==============================================================
【程序94】
题目:时间函数举例4,一个猜数游戏,判断一个人反应快慢。(版主初学时编的)
1.程序分析:
2.程序源代码:
#include "time.h"
#include "stdlib.h"
#include "stdio.h"
#include "conio.h"
main()
{
  char c;
  clock_t start,end;
  time_t a,b;
  double var;
  int i,guess;
  srand(time(NULL));
  printf("do you want to play it.('y' or 'n') \n");
loop:
  while((c=getchar())=='y')
  {
    i=rand()%100;
    printf("\nplease input number you guess:\n");
    start=clock();
    a=time(NULL);
    scanf("%d",&guess);
    while(guess!=i)
    {
      if(guess>i)
      {
        printf("please input a little smaller.\n");
        scanf("%d",&guess);
      }
      else
      {
        printf("please input a little bigger.\n");
        scanf("%d",&guess);
      }
    }
    end=clock();
    b=time(NULL);
    printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2);
    printf("\1: it took you %6.3f seconds\n\n",difftime(b,a));
    if(var<15)
      printf("\1\1 You are very clever! \1\1\n\n");
      else if(var<25)
        printf("\1\1 you are normal! \1\1\n\n");
      else
        printf("\1\1 you are stupid! \1\1\n\n");
    printf("\1\1 Congradulations \1\1\n\n");
    printf("The number you guess is %d",i);
  }
  printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n");
  if((c=getch())=='y')
    goto loop;
}
==============================================================
【程序95】
题目:家庭财务管理小程序
1.程序分析:
2.程序源代码:
/*money management system*/
#include "stdio.h"
#include "dos.h"
#include "conio.h"
main()
{
  FILE *fp;
  struct date d;
  float sum,chm=0.0;
  int len,i,j=0;
  int c;
  char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];
pp:
  clrscr();
  sum=0.0;
  gotoxy(1,1);printf("|---------------------------------------------------------------------------|");
  gotoxy(1,2);printf("| money management system(C1.0) 2000.03 |");
  gotoxy(1,3);printf("|---------------------------------------------------------------------------|");
  gotoxy(1,4);printf("| -- money records -- | -- today cost list -- |");
  gotoxy(1,5);printf("| ------------------------ |-------------------------------------|");
  gotoxy(1,6);printf("| date: -------------- | |");
  gotoxy(1,7);printf("| | | | |");
  gotoxy(1,8);printf("| -------------- | |");
  gotoxy(1,9);printf("| thgs: ------------------ | |");
  gotoxy(1,10);printf("| | | | |");
  gotoxy(1,11);printf("| ------------------ | |");
  gotoxy(1,12);printf("| cost: ---------- | |");
  gotoxy(1,13);printf("| | | | |");
  gotoxy(1,14);printf("| ---------- | |");
  gotoxy(1,15);printf("| | |");
  gotoxy(1,16);printf("| | |");
  gotoxy(1,17);printf("| | |");
  gotoxy(1,18);printf("| | |");
  gotoxy(1,19);printf("| | |");
  gotoxy(1,20);printf("| | |");
  gotoxy(1,21);printf("| | |");
  gotoxy(1,22);printf("| | |");
  gotoxy(1,23);printf("|---------------------------------------------------------------------------|");
  i=0;
  getdate(&d);
  sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day);
  for(;;)
  {
    gotoxy(3,24);printf(" Tab __browse cost list Esc __quit");
    gotoxy(13,10);printf(" ");
    gotoxy(13,13);printf(" ");
    gotoxy(13,7);printf("%s",chtime);
    j=18;
    ch[0]=getch();
    if(ch[0]==27)
      break;
    strcpy(chshop,"");
    strcpy(chmoney,"");
    if(ch[0]==9)
    {
mm:
      i=0;
      fp=fopen("home.dat","r+");
      gotoxy(3,24);printf(" ");
      gotoxy(6,4);printf(" list records ");
      gotoxy(1,5);printf("|-------------------------------------|");
      gotoxy(41,4);printf(" ");
      gotoxy(41,5);printf(" |");
      while(fscanf(fp,"%10s%14s%f\n",chtime,chshop,&chm)!=EOF)
      {
        if(i==36)
        {
          getch();
          i=0;
        }
        if((i%36)<17)
        {
          gotoxy(4,6+i);
          printf(" ");
          gotoxy(4,6+i);
        }
        else
          if((i%36)>16)
          {
            gotoxy(41,4+i-17);
            printf(" ");
            gotoxy(42,4+i-17);
          }
        i++;
        sum=sum+chm;
        printf("%10s %-14s %6.1f\n",chtime,chshop,chm);
      }
      gotoxy(1,23);printf("|---------------------------------------------------------------------------|");
      gotoxy(1,24);printf("| |");
      gotoxy(1,25);printf("|---------------------------------------------------------------------------|");
      gotoxy(10,24);printf("total is %8.1f$",sum);
      fclose(fp);
      gotoxy(49,24);printf("press any key to.....");getch();goto pp;
    }
    else
    {
      while(ch[0]!='\r')
      {
        if(j<10)
        {
          strncat(chtime,ch,1);
          j++;
        }
        if(ch[0]==8)
        {
          len=strlen(chtime)-1;
          if(j>15)
          {len=len+1; j=11;}
          strcpy(ch1,"");
          j=j-2;
          strncat(ch1,chtime,len);
          strcpy(chtime,"");
          strncat(chtime,ch1,len-1);
          gotoxy(13,7);printf(" ");
        }
        gotoxy(13,7);printf("%s",chtime);ch[0]=getch();
        if(ch[0]==9)
          goto mm;
        if(ch[0]==27)
          exit(1);
      }
      gotoxy(3,24);printf(" ");
      gotoxy(13,10);
      j=0;
      ch[0]=getch();
      while(ch[0]!='\r')
      {
        if (j<14)
        {
          strncat(chshop,ch,1);
          j++;
        }
        if(ch[0]==8)
        {
          len=strlen(chshop)-1;
          strcpy(ch1,"");
          j=j-2;
          strncat(ch1,chshop,len);
          strcpy(chshop,"");
          strncat(chshop,ch1,len-1);
          gotoxy(13,10);printf(" ");
        }
        gotoxy(13,10);printf("%s",chshop);ch[0]=getch();
      }
      gotoxy(13,13);
      j=0;
      ch[0]=getch();
      while(ch[0]!='\r')
      {
        if (j<6)
        {
          strncat(chmoney,ch,1);
          j++;
        }
        if(ch[0]==8)
        {
          len=strlen(chmoney)-1;
          strcpy(ch1,"");
          j=j-2;
          strncat(ch1,chmoney,len);
          strcpy(chmoney,"");
          strncat(chmoney,ch1,len-1);
          gotoxy(13,13);printf(" ");
        }
        gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();
      }
      if((strlen(chshop)==0)||(strlen(chmoney)==0))
        continue;
      if((fp=fopen("home.dat","a+"))!=NULL);
        fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney);
      fputc('\n',fp);
      fclose(fp);
      i++;
      gotoxy(41,5+i);
      printf("%10s %-14s %-6s",chtime,chshop,chmoney);
    }
  }
  getch();
}
==============================================================
【程序96】
题目:计算字符串中子串出现的次数
1.程序分析:
2.程序源代码:
#include "string.h"
#include "stdio.h"
#include "conio.h"
main()
{
  char str1[20],str2[20],*p1,*p2;
  int sum=0;
  printf("please input two strings\n");
  scanf("%s%s",str1,str2);
  p1=str1;p2=str2;
  while(*p1!='\0')
  {
    if(*p1==*p2)
    {
      while(*p1==*p2&&*p2!='\0')
      {
        p1++;
        p2++;
      }
    }
    else
      p1++;
    if(*p2=='\0')
      sum++;
    p2=str2;
  }
  printf("%d",sum);
  getch();
}
==============================================================
【程序97】
题目:从键盘输入一些字符,逐个把它们送到磁盘上去,直到输入一个#为止。
1.程序分析:     
2.程序源代码:
#include "stdio.h"
main()
{
  FILE *fp;
  char ch,filename[10];
  scanf("%s",filename);
  if((fp=fopen(filename,"w"))==NULL)
  {
    printf("cannot open file\n");
    exit(0);
  }
  ch=getchar();
  ch=getchar();
  while(ch!='#')
  {
    fputc(ch,fp);
    putchar(ch);
    ch=getchar();
  }
  fclose(fp);
}
==============================================================
【程序98】
题目:从键盘输入一个字符串,将小写字母全部转换成大写字母,然后输出到一个磁盘文件“test”中保存。
   输入的字符串以!结束。
1.程序分析:
2.程序源代码:
#include "stdio.h"
#include "conio.h"
main()
{
  FILE *fp;
  char str[100],filename[10];
  int i=0;
  if((fp=fopen("test","w"))==NULL)
  {
    printf("cannot open the file\n");
    exit(0);
  }
  printf("please input a string:\n");
  gets(str);
  while(str[i]!='!')
  {
    if(str[i]>='a'&&str[i]<='z')
      str[i]=str[i]-32;
    fputc(str[i],fp);
    i++;
  }
  fclose(fp);
  fp=fopen("test","r");
  fgets(str,strlen(str)+1,fp);
  printf("%s\n",str);
  fclose(fp);
  getch();
}
==============================================================
【程序99】
题目:有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息合并(按字母顺序排列),
   输出到一个新文件C中。
1.程序分析:
2.程序源代码:
#include "stdio.h"
#include "conio.h"
main()
{
  FILE *fp;
  int i,j,n,ni;
  char c[160],t,ch;
  if((fp=fopen("A","r"))==NULL)
  {
    printf("file A cannot be opened\n");
    exit(0);
  }
  printf("\n A contents are :\n");
  for(i=0;(ch=fgetc(fp))!=EOF;i++)
  {
    c[i]=ch;
    putchar(c[i]);
  }
  fclose(fp);
  ni=i;
  if((fp=fopen("B","r"))==NULL)
  {
    printf("file B cannot be opened\n");
    exit(0);
  }
  printf("\n B contents are :\n");
  for(i=0;(ch=fgetc(fp))!=EOF;i++)
  {
    c[i]=ch;
    putchar(c[i]);
  }
  fclose(fp);
  n=i;
  for(i=0;i<n;i++)
    for(j=i+1;j<n;j++)
      if(c[i]>c[j])
      {t=c[i];c[i]=c[j];c[j]=t;}
  printf("\n C file is:\n");
  fp=fopen("C","w");
  for(i=0;i<n;i++)
  {
    putc(c[i],fp);
    putchar(c[i]);
  }
  fclose(fp);
  getch();
}
==============================================================
【程序100】
题目:有五个学生,每个学生有3门课的成绩,从键盘输入以上数据(包括学生号,姓名,三门课成绩),计算出
   平均成绩,况原有的数据和计算出的平均分数存放在磁盘文件"stud"中。
1.程序分析:
2.程序源代码:
#include "stdio.h"
#include "conio.h"
struct student
{
  char num[6];
  char name[8];
  int score[3];
  float avr;
}stu[5];
main()
{
  int i,j,sum;
  FILE *fp;
  /*input*/
  for(i=0;i<5;i++)
  {
    printf("\n please input No. %d score:\n",i);
    printf("stuNo:");
    scanf("%s",stu[i].num);
    printf("name:");
    scanf("%s",stu[i].name);
    sum=0;
    for(j=0;j<3;j++)
    {
      printf("score %d.",j+1);
      scanf("%d",&stu[i].score[j]);
      sum+=stu[i].score[j];
    }
    stu[i].avr=sum/3.0;
  }
  fp=fopen("stud","w");
  for(i=0;i<5;i++)
    if(fwrite(&stu[i],sizeof(struct student),1,fp)!=1)
      printf("file write error\n");
  fclose(fp);
  getch();
}

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