Oracle行列转换小结
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http://www.2cto.com/database/201108/100792.html
目录结构如下：
行转列
列转行
[一]、行转列
1.1、初始测试数据
表结构：TEST_TB_GRADE
Sql代码
create table TEST_TB_GRADE
(
ID NUMBER(10) not null,
USER_NAME VARCHAR2(20 CHAR),
COURSE VARCHAR2(20 CHAR),
SCORE FLOAT
)
初始数据如下图：
1.2、 如果需要实现如下的查询效果图：
这就是最常见的行转列，主要原理是利用decode函数、聚集函数(sum)，结合group by分组实现的，具体的sql如下：
Sql代码
select t.user_name,
sum(decode(t.course, '语文', score,null)) as CHINESE,
sum(decode(t.course, '数学', score,null)) as MATH,
sum(decode(t.course, '英语', score,null)) as ENGLISH
from test_tb_grade t
group by t.user_name
order by t.user_name
1.3、延伸
如果要实现对各门功课的不同分数段进行统计，效果图如下：
具体的实现sql如下：
Sql代码
select t2.SCORE_GP,
sum(decode(t2.course, '语文', COUNTNUM,null)) as CHINESE,
sum(decode(t2.course, '数学', COUNTNUM,null)) as MATH,
sum(decode(t2.course, '英语', COUNTNUM,null)) as ENGLISH
from (
select t.course,
case when t.score <60 then '00-60'
when t.score >=60 and t.score <80 then '60-80'
when t.score >=80 then '80-100' end as SCORE_GP,
count(t.score) as COUNTNUM
FROM test_tb_grade t
group by t.course,
case when t.score <60 then '00-60'
when t.score >=60 and t.score <80 then '60-80'
when t.score >=80 then '80-100' end
order by t.course ) t2
group by t2.SCORE_GP
order by t2.SCORE_GP
[二]、列转行
1.1、初始测试数据
表结构：TEST_TB_GRADE2
Sql代码
create table TEST_TB_GRADE2
(
ID NUMBER(10) not null,
USER_NAME VARCHAR2(20 CHAR),
CN_SCORE FLOAT,
MATH_SCORE FLOAT,
EN_SCORE FLOAT
)
初始数据如下图：
1.2、 如果需要实现如下的查询效果图：
这就是最常见的列转行，主要原理是利用SQL里面的union，具体的sql语句如下：
Sql代码
select user_name, '语文' COURSE , CN_SCORE as SCORE from test_tb_grade2
union select user_name, '数学' COURSE, MATH_SCORE as SCORE from test_tb_grade2
union select user_name, '英语' COURSE, EN_SCORE as SCORE from test_tb_grade2
order by user_name,COURSE
也可以利用【 insert all into ... select 】来实现，首先需要先建一个表TEST_TB_GRADE3：
Sql代码
create table TEST_TB_GRADE3
(
USER_NAME VARCHAR2(20 CHAR),
COURSE VARCHAR2(20 CHAR),
SCORE FLOAT
)
再执行下面的sql：
Sql代码
insert all
into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '语文', CN_SCORE)
into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '数学', MATH_SCORE)
into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '英语', EN_SCORE)
select user_name, CN_SCORE, MATH_SCORE, EN_SCORE from test_tb_grade2;
commit;
别忘记commit操作，然后再查询TEST_TB_GRADE3，发现表中的数据就是列转成行了。