第二次作业
1 package aaa; 2 import java.util.Scanner; 3 4 public class A { 5 6 public static void main(String[]args) 7 { 8 int[] arr1={-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,
-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,
2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,
6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,
461,940,6604,-3631,3802,-2037,-4354,-1213,767}; 9 int sum=0; 10 Scanner se = new Scanner(System.in) ; 11 System.out.println("请输入start:"); 12 int start = se.nextInt() ; 13 System.out.println("请输入end:"); 14 int end =se.nextInt(); 15 System.out.println("start为：" +start); 16 System.out.println("end为：" +end); 17 for(int i=start;i<=end;i++)18 19 20 sum+=arr1[i]; 21 System.out.println(sum); 22 } 23 24 }
这上面是一维数组1至100任意相加的代码，运用了面向过程的方法。需要输入一维数的开始范围与结束范围，由程序最后自动相加得到结果。
1 package aaa; 2 3 import java.util.Scanner; 4 5 public class B { 6 7 public static void main(String[]args){ 8 int[][] a={{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767},{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}}; 9 int sum=0; 10 Scanner se = new Scanner(System.in); 11 System.out.println("输入start-y："); 12 int start1 = se.nextInt(); 13 System.out.println("输入end-y:"); 14 int end1 =se.nextInt(); 15 System.out.println("start-y：" +start1); 16 System.out.println("end-y：" +end1); 17 18 System.out.println("输入start-x："); 19 int start2 = se.nextInt(); 20 System.out.println("输入end-x:"); 21 int end2 =se.nextInt(); 22 System.out.println("start-x：" +start2); 23 System.out.println("end-x：" +end2); 24 for(int i=start1;i<=end1;i++) 25 { 26 for(int j=start2;j<=end2;j++) 27 { 28 sum+=a[i][j]; 29 } 30 } 31 System.out.println(sum); 32 } 33 34 }
这上面是二维数组，同样运用了面向过程的方法。
1 package aaa; 2 3 import java.util.Scanner; 4 5 public class C { 6 7 8 public static void main(String[]args) 9 { 10 int sum=0; 11 int[][][] a = new int[][][] 12 { 13 {{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767}}, 14 {{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}}, 15 {{302,-7944,-6551,6648,-884,-6332,1188,-248,3902,-2171,-3782,-3510,6203,-636,-4605,4497,3187,-6278,1198,-7963,7647,-3022,-8267,7995,-1998,-4171,730,-8117,-1706,7601,-2454,-6161,-1810,243,-2841,-5377,2985,2328,177,5622,3596,3057,2830,-1151,6566,2254,6972,-3060,4063,367,84,3156,3880,-1530,5272,1385,-565,-1736,1267,-3863,-229,2072,2423,-7449,9555,2844,-1278,-3613,-919,4153,-4232,4032,-5732,199,4792,2498,-3344,-4193,2650,-579,3416,-3575,1822,-6936,-2661,-1873,414,2314,6844,7613,-7844,6680,5974,2208,-3597,6302,4396,-141,-1864,1939}} 16 }; 17 Scanner se = new Scanner(System.in) ; 18 System.out.println("请输入start-x:"); 19 int start1 = se.nextInt() ; 20 System.out.println("请输入end-x:"); 21 int end1 =se.nextInt(); 22 System.out.println("start-x为：" +start1); 23 System.out.println("end-x为：" +end1); 24 25 System.out.println("请输入start-y:"); 26 int start2 = se.nextInt() ; 27 System.out.println("请输入end-y:"); 28 int end2 =se.nextInt(); 29 System.out.println("start-y为：" +start2); 30 System.out.println("end-y为：" +end2); 31 32 System.out.println("请输入start-z:"); 33 int start3 = se.nextInt() ; 34 System.out.println("请输入end-z:"); 35 int end3 =se.nextInt(); 36 System.out.println("start-z为：" +start3); 37 System.out.println("end-z为：" +end3); 38 for(int i=start1;i<=end1;i++) 39 { 40 for(int j=start2;j<=end2;j++) 41 { 42 for(int q=start3;q<=end3;q++) 43 { 44 sum+=a[i][j][q]; 45 46 } 47 } 48 49 } 50 System.out.println(sum); 51 } 52 }
此为三维数组。