hdu 2114 Calculate S(n) 简单数学题

Calculate S(n)

Time Limit: 10000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4983    Accepted Submission(s): 1889

Problem Description

Calculate S(n).

S(n)=1 ³+2 ³ +3 ³ +......+n ³ .

 

Input

Each line will contain one integer N(1 < n < 1000000000). Process to end of file.

 

Output

For each case, output the last four dights of S(N) in one line.

 

Sample Input

   
   
   
   

    
    
    
    1
2
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    0001
0009
   
   
   
   

 

Author

天邪

 

连续的求平方的公式是           1*1+2*2+3*3+4*4----      n*(n+1)*(2n+1)/6

连续的求立方的公式是         1*1*1+2*2*2+3*3*3+4*4*4   n*n*(n+1)*(n+1)/4

直接套用公式mod就可以了

post code：

#include<stdio.h>
int main()
{
   __int64 num;
   int num1;
   while(scanf("%I64d",&num)!=EOF )
   {
     num=num%1000000;
     num= ( (num*num)%1000000*( (num+1)*(num+1) )%1000000 )%1000000/4;                           
     num1=(int) (num%10000);                                                      
     printf("%04d\n",num1);
   }
   
    
}