题意:给n个单位内存(编号从1开始),有几种操作:Reset把所有的内存清空,然后输出“Reset Now”。New x申请一块长度为x的内存块(如多解,左边优先),然后输出“New at A”。Free x把包含第x块单位内存的内存块清除,然后输出“Free from A to B”。Get x返回第x块内存块的起始内存单位编号,然后输出 “Get at A”。
大部分操作和POJ 3667 HOTEL一样.对于get操作,我把之前new操作得到的内存块的起点都放到了set,然后get的时候,暴力跑.
/*代码风格更新后*/ #include <iostream> #include <cstdio> #include <cstring> #include <set> using namespace std; #define LL(x) (x<<1) #define RR(x) (x<<1|1) #define MID(a,b) (a+((b-a)>>1)) const int N=50005; struct node { int lft,rht; int lmx,rmx,mx,flag; int len(){return rht-lft+1;} int mid(){return MID(lft,rht);} void init(){lmx=rmx=mx=len();} void fun(int valu) { flag=valu; if(valu>0) lmx=rmx=mx=0; else lmx=rmx=mx=len(); } }; int n,m,st[N],ed[N]; set<int> adj; set<int>::iterator it; struct Segtree { node tree[N*4]; void down(int ind) { if(tree[ind].flag) { tree[LL(ind)].fun(tree[ind].flag); tree[RR(ind)].fun(tree[ind].flag); tree[ind].flag=0; } } void up(node &a,node &b,node &c) { a.lmx=b.lmx; a.rmx=c.rmx; a.mx=max(b.rmx+c.lmx,max(b.mx,c.mx)); if(b.len()==b.lmx) a.lmx+=c.lmx; if(c.len()==c.rmx) a.rmx+=b.rmx; } void build(int lft,int rht,int ind) { tree[ind].lft=lft; tree[ind].rht=rht; tree[ind].flag=0; tree[ind].init(); if(lft==rht) tree[ind].flag=-1; else { int mid=tree[ind].mid(); build(lft,mid,LL(ind)); build(mid+1,rht,RR(ind)); } } void updata(int st,int ed,int ind,int valu) { int lft=tree[ind].lft,rht=tree[ind].rht; if(st<=lft&&rht<=ed) tree[ind].fun(valu); else { down(ind); int mid=tree[ind].mid(); if(st<=mid) updata(st,ed,LL(ind),valu); if(ed> mid) updata(st,ed,RR(ind),valu); up(tree[ind],tree[LL(ind)],tree[RR(ind)]); } } int getID(int pos,int ind) { if(tree[ind].flag) return tree[ind].flag; else {//这里可以不用判断延迟操作,因而也不用合并区间 int mid=tree[ind].mid(); if(pos<=mid) return getID(pos,LL(ind)); else return getID(pos,RR(ind)); } } int query(int valu,int ind) { if(tree[ind].lft==tree[ind].rht) return tree[ind].lft; else { int pos; down(ind); if(tree[LL(ind)].mx>=valu) pos=query(valu,LL(ind)); else if(tree[LL(ind)].rmx+tree[RR(ind)].lmx>=valu) pos=tree[LL(ind)].rht-tree[LL(ind)].rmx+1; else pos=query(valu,RR(ind)); up(tree[ind],tree[LL(ind)],tree[RR(ind)]); return pos; } } }seg; int main() { while(scanf("%d%d",&n,&m)!=EOF) { adj.clear(); seg.build(1,n,1); int a; char cmd[10]; for(int i=1;i<=m;i++) { scanf("%s",cmd); if(strcmp(cmd,"Reset")==0) { adj.clear(); seg.updata(1,n,1,-1); puts("Reset Now"); } else { scanf("%d",&a); if(strcmp(cmd,"New")==0) { if(seg.tree[1].mx<a) puts("Reject New"); else { st[i]=seg.query(a,1); seg.updata(st[i],ed[i]=st[i]+a-1,1,i); adj.insert(st[i]); printf("New at %d\n",st[i]); } } else if(strcmp(cmd,"Free")==0) { int id=seg.getID(a,1); if(id==-1) puts("Reject Free"); else { adj.erase(st[id]); seg.updata(st[id],ed[id],1,-1); printf("Free from %d to %d\n",st[id],ed[id]); } } else { if(a>(int)adj.size()) puts("Reject Get"); else { a--; it=adj.begin(); while(a--) it++; printf("Get at %d\n",*it); } } } } puts(""); } return 0; }
/*代码风格更新前*/ #include <iostream> #include <cstdio> #include <map> #include <cstring> using namespace std; const int N=50005; struct XD { int be,end; XD(){be=0;end=0;}; XD(int a,int b){be=a;end=b;} }; struct node { int left,right,co; int lmax,rmax,mmax; int mid(){return left+(right-left)/2;} int dis(){return right-left+1;} void change(int r) { co=r; if(r!=0) {lmax=rmax=mmax=0;} else {lmax=rmax=mmax=dis();} } }; void unin(node &a,node &b,node &c) { a.lmax=b.lmax; a.rmax=c.rmax; a.mmax=max(b.rmax+c.lmax,max(b.mmax,c.mmax)); if(b.dis()==b.lmax) a.lmax+=c.lmax; if(c.dis()==c.rmax) a.rmax+=b.rmax; } struct Segtree { node tree[N*4]; void build(int left,int right,int r) { tree[r].left=left; tree[r].right=right; tree[r].lmax=tree[r].rmax=tree[r].mmax=tree[r].dis(); tree[r].co=0; if(left<right) { int mid=tree[r].mid(); build(left,mid,r*2); build(mid+1,right,r*2+1); } } void updata(int be,int end,int r,int co) { if(be<=tree[r].left&&tree[r].right<=end) { tree[r].change(co); } else { if(tree[r].co!=-1) { tree[r*2].change(tree[r].co); tree[r*2+1].change(tree[r].co); tree[r].co=-1; } int mid=tree[r].mid(); if(be<=mid) updata(be,end,r*2,co); if(end>mid) updata(be,end,r*2+1,co); unin(tree[r],tree[r*2],tree[r*2+1]); } } int query(int len,int r) { if(tree[r].lmax>=len) return tree[r].left; else { if(tree[r*2].mmax>=len) return query(len,r*2); else if(tree[r*2].rmax+tree[r*2+1].lmax>=len) return tree[r*2].right-tree[r*2].rmax+1; else return query(len,r*2+1); } } int check(int pos,int r) { if(tree[r].co!=-1) return tree[r].co; else { if(tree[r].co!=-1) { tree[r*2].change(tree[r].co); tree[r*2+1].change(tree[r].co); tree[r].co=-1; } int mid=tree[r].mid(); if(pos<=mid) return check(pos,r*2); else return check(pos,r*2+1); } } }seg; int main() { int n,m; map<int,XD> adj; map<int,XD>::iterator it; while(scanf("%d%d",&n,&m)!=EOF) { int a; char cmd[10]; adj.clear(); seg.build(1,n,1); for(int i=0;i<m;i++) { scanf("%s",cmd); if(strcmp(cmd,"Reset")==0) { adj.clear(); seg.updata(1,n,1,0); puts("Reset Now"); } else { scanf("%d",&a); if(strcmp(cmd,"New")==0) { if(seg.tree[1].mmax<a) puts("Reject New"); else { int pos=seg.query(a,1); seg.updata(pos,pos+a-1,1,pos); adj.insert(pair<int,XD>(pos,XD(pos,pos+a-1))); printf("New at %d\n",pos); } } else if(strcmp(cmd,"Get")==0) { if(a>adj.size())puts("Reject Get"); else { int cnt=1; for(it=adj.begin();it!=adj.end();it++) { if(cnt==a) break; cnt++; } printf("Get at %d\n",it->first); } } else { int pos=seg.check(a,1); if(pos==0) puts("Reject Free"); else { int be=adj[pos].be,end=adj[pos].end; adj.erase(pos); seg.updata(be,end,1,0); printf("Free from %d to %d\n",be,end); } } } } puts(""); } return 0; }