求一元二次方程的跟

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	double a,b,c,x,dlt,x1,x2;
	cout<<"请输入一元二次方程的各项系数："<<endl;
	cin>>a>>b>>c;
	if(a==0)
	{
		if(b!=0)
		{
		    x=c/b;
			cout<<"方程的解为："<<x<<endl;
		}
		else
			cout<<"无解"<<endl;
	}else{
		dlt=sqrt(b*b-4*a*c);
		if(dlt<0)
			cout<<"无解"<<endl;
		else if(dlt==0)
		{
			x=-b/2*a;
			cout<<"方程的解为："<<x<<endl;
		}
		else
		{
			x1=(-b+dlt)/2*a;
			x2=(-b-dlt)/2*a;
			cout<<"x1="<<x1<<endl;
            cout<<"x2="<<x2<<endl;
		}
	}
		return 0;
}