hdu 1228 A + B

A + B

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10243 Accepted Submission(s): 5867

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

   
   
   
   

    
    
    
    one + two =
three four + five six =
zero seven + eight nine =
zero + zero =
   
   
   
   

Sample Output

   
   
   
   

    
    
    
    3
90
96
   
   
   
   

Source

浙大计算机研究生复试上机考试-2005年

Recommend

JGShining

直接模拟就不说了。

#include <stdio.h>
#include<string.h>

int main()
{
    char num[10][10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    char s[10];
    int sum=0,i,a;

    while(~scanf("%s",s))
    {
        if(s[0]=='+')
        {
            a=sum;
            sum=0;
            continue;
        }
        if(s[0]=='=')
        {
            if(sum==0&&a==0)
                break;
            printf("%d\n",sum+a);
            sum=0;
            continue;
        }
        for(i=0;i<10;i++)
        {
            if(strcmp(num[i],s)==0)
            {
                sum*=10;
                sum+=i;
                break;
            }
        }
    }
    return 0;
}