hdu 2368 Alfredo's Pizza Restaurant

Alfredo's Pizza Restaurant

                                                                          Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Other）

Problem Description

Traditionally after the Local Contest, judges and contestants go to their favourite restaurant, Alfredos Pizza Restaurant. The contestants are really hungry after trying hard for five hours. To get their pizza as quickly as possible, they just decided to order one big pizza for all instead of several small ones. They wonder whether it is possible to put the big rectangular pizza on the surface of the round table such that it does not overhang the border of the table. Write a program that helps them!

 

Input

The input file contains several test cases. Each test case starts with an integer number r, the radius of the surface of the round table the contestants are sitting at. Input is terminated by r=0. Otherwise, 1 ≤ r ≤ 1000. Then follow 2 integer numbers w and l specifying the width and the length of the pizza, 1 ≤ w ≤ l ≤ 1000. 

 

Output

Output for each test case whether the ordered pizza will fit on the table or not. Adhere to the format shown in the sample output. A pizza which just touches the border of the table without intersecting it is considered fitting on the table, see example 3 for clarification. 

 

Sample Input

   
   
   
   

    
    
    
    38 40 60
35 20 70
50 60 80
0
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    Pizza 1 fits on the table.
Pizza 2 does not fit on the table.
Pizza 3 fits on the table.
   
   
   
   
   
   
   
   

    
    
    
    题目意思：给出桌子的半径和Pizza的长和宽，问Pizza能否放在这个桌子上而不会越过桌子边缘。将Pizza看做一个矩形，只要比较矩形的对角线和桌子的直径大小即可。注意数据类型。
   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   

    
    
    
    
#include<stdio.h>
#include<math.h>
int main() { float w,l,d,r; int i=1; while(scanf("%f",&r)!=EOF) { if(r==0) break;
        scanf("%f%f",&w,&l);
        d=sqrt(w*w+l*l);  //对角线长
 if(d<=r*2)
            printf("Pizza %d fits on the table.\n",i++); else
            printf("Pizza %d does not fit on the table.\n",i++); } return 0; }