//哈夫曼树构造原则: 权值小的在前,相等的单节点在前; #include "stdafx.h" #include <stdio.h> #include <stdlib.h> #include <string.h> typedef struct{ unsigned int weight; unsigned int parent,lchild,rchild; }HTNode,*HuffmanTree; typedef char **HuffmanCode; void Select(HuffmanTree &HT, int n, int &s1, int &s2) { //在HT[1..n]中选择parent为0且weight最小的两个结点, // 其序号分别为s1和s2。 int i; s1=-1;s2=-1; for(i=1; i<=n; i++) if(HT[i].parent == 0) { if(s1 == -1) s1 = i; else if(HT[i].weight < HT[s1].weight) { s2 = s1; s1 = i; } else if(s2 == -1 || HT[i].weight < HT[s2].weight) s2 = i; } } void HuffmanCoding(HuffmanTree &HT,HuffmanCode &HC,int *w,int n) { // 并求出n个字符的哈夫曼编码HC int i, m, s1, s2, start; char *cd; unsigned int c, f; if (n<=1) return; m = 2 * n - 1; HT = (HuffmanTree)malloc((m+1) * sizeof(HTNode)); // 0号单元未用 for (i=1; i<=n; i++) { //初始化 HT[i].weight=w[i-1]; HT[i].parent=0; HT[i].lchild=0; HT[i].rchild=0; } for (i=n+1; i<=m; i++) { //初始化 HT[i].weight=0; HT[i].parent=0; HT[i].lchild=0; HT[i].rchild=0; } for (i=n+1; i<=m; i++) { // 建哈夫曼树 // 在HT[1..i-1]中选择parent为0且weight最小的两个结点, // 其序号分别为s1和s2。 Select(HT, i-1, s1, s2); HT[s1].parent = i; HT[s2].parent = i; HT[i].lchild = s1; HT[i].rchild = s2; HT[i].weight = HT[s1].weight + HT[s2].weight; } //--- 从叶子到根逆向求每个字符的哈夫曼编码 --- cd = (char *)malloc(n*sizeof(char)); // 分配求编码的工作空间 cd[n-1] = '\0'; // 编码结束符。 for (i=1; i<=n; ++i) { // 逐个字符求哈夫曼编码 start = n-1; // 编码结束符位置 for (c=i, f=HT[i].parent; f!=0; c=f, f=HT[f].parent) // 从叶子到根逆向求编码 if (HT[f].lchild==c) cd[--start] = '0'; else cd[--start] = '1'; HC[i] = (char *)malloc((n-start)*sizeof(char)); // 为第i个字符编码分配空间 strcpy(HC[i], &cd[start]); // 从cd复制编码(串)到HC } free(cd); //释放工作空间 } //HuffmanCoding int _tmain(int argc, _TCHAR* argv[]) { int i,n; int *w; HuffmanTree HT; HuffmanCode HC; printf("Node Number:"); scanf("%d",&n); //权值个数 w=(int *)malloc(n*sizeof(int)); printf("Input weights:"); for ( i=0;i<n;i++) //录入权值 scanf("%d",&w[i]); HC=(char **)malloc((n+1)*sizeof(char*)); //0空间未用 HT=(HuffmanTree)malloc((2*n+1+1)*sizeof(HTNode));//0空间未用 HuffmanCoding(HT, HC, w, n); printf("\n"); for (i = 1; i<n+1; i++){ printf("%s\n", HC[i]); //输出哈夫曼编码 free(HC[i]); //释放空间 } free(HC); free(HT); system("pause"); return 0; }
其中的select()函数亦可如下求解:
int min(HuffmanTree t,int i) { // 函数void select()调用 int j,flag; unsigned int k=UINT_MAX; // 取k为不小于可能的值 for(j=1; j<=i; j++) if(t[j].weight<k&&t[j].parent==0) k=t[j].weight,flag=j; t[flag].parent=1; return flag; } void select(HuffmanTree t,int i,int &s1,int &s2) { // s1为最小的两个值中序号小的那个 s1=min(t,i); s2=min(t,i); /* if(s1>s2) { j=s1; s1=s2; s2=j; }*/ }