二维指针内存的申请和释放(simple，naive ?)

simple，naive ?

int _tmain(int argc, _TCHAR* argv[])
{
	//二维指针
	int **p = NULL;

	//行、列
	int x,y;
	
	cout << "行数：" ; 
	cin >> x;

	cout << "列数：" ; 
	cin >> y;
	
	//申请行空间
	p = new(std::nothrow) int*[x];  
	if( NULL == p)
	{
		cout << "memery allocate failed" << endl;
		return false;
	}

	//申请列空间
	for(int i = 0; i < x; i++)
	{
		p[i] = new(std::nothrow) int[y];
		if(NULL == p[i])
		{
			cout << "memery allocate failed" << endl;
			return false;
		}
	}

	//读入值
	int tmp = 1;
	for(int i=0;i<x;i++)
	{
		for(int j=0; j<y; j++)
		{
			p[i][j] = tmp;
			tmp++;
		}
	}

	//输出
	for(int i=0;i<x;i++)
	{
		for(int j=0; j<y; j++)
		{
			cout << p[i][j] << "\t";
		}
		cout << endl;
	}
        
     if(p)
	{
		//删除申请的内存
		for(int i = 0; i < x; i++)
		{
			delete []p[i];
		}
		delete [] p;
	}

	system("pause");
	return 0;
}

输出：

行数：3
列数：4
1       2       3       4
5       6       7       8
9       10      11      12