Google JS Test是一个运行于V8 JavaScript引擎下的Javascript单元测试框架，其在Google内部负责对Chrome的快速JS执行速度进行测试，现在Google以开源工程开放大家使用。Google JS Test主要特性：

  • 超快的启动速度和执行时间，不需要在浏览器里运行
  • 清爽而具有可读性的输出内容
  • 也有一个可选的基于浏览器的测试器，可在JS修改的时候刷新
  • 其样式和语义跟Google Test for C++类似
  • 内置的Mocking框架只需要最简单的样板代码（比如no $tearDown or $verifyAll 请求），其样式和语义基于Google C++ Mocking Framework
  • 匹配系统允许表达式测试，并可直观的阅读输出的错误提示，内置了很多匹配器，用户也可自行添加

JS测试工具 Google JS Test_第1张图片

01 function UserInfoTest() {
02   // Each test function gets its own instance of UserInfoTest, so tests can
03   // use instance variables to store state that doesn't affect other tests.
04   // There's no need to write a tearDown method, unless you modify global
05   // state.
06   //
07   // Create an instance of the class under test here, giving it a mock
08   // function that we also keep a reference to below.
09   this.getInfoFromDb_ = createMockFunction();
10   this.userInfo_ = new UserInfo(this.getInfoFromDb_);
11 }
12 registerTestSuite(UserInfoTest);
13  
14 UserInfoTest.prototype.formatsUSPhoneNumber = function() {
15   // Expect a call to the database function with the argument 0xdeadbeef. When
16   // the call is received, return the supplied string.
17   expectCall(this.getInfoFromDb_)(0xdeadbeef)
18     .willOnce(returnWith('phone_number: "650 253 0000"'));
19  
20   // Make sure that our class returns correctly formatted output.
21   expectEq('(650) 253-0000',this.userInfo_.getPhoneForId(0xdeadbeef));
22 };
23  
24 UserInfoTest.prototype.returnsLastNameFirst = function() {
25   expectCall(this.getInfoFromDb_)(0xdeadbeef)
26     .willOnce(returnWith('given_name: "John" family_name: "Doe"'));
27  
28   // Make sure that our class puts the last name first.
29   expectEq('Doe, John', this.userInfo_.getNameForId(0xdeadbeef));
30 };
项目地址：  http://code.google.com/p/google-js-test/