Jewel——2010 天津赛区 J 题

        一大清早起来 A 掉一道划分树+树状数组+离散化的题+近200行代码的题,勉强算是弥补了今晚不能做 CF 的遗憾了吧,该死的,怎么会这个时候交我回家呢?!!

        题很裸,一看就知道是划分树求区间第 k 值 + 树状数组

        给出题目连接,懒得写 html 了:http://livearchive.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=393&page=show_problem&problem=3035

        注意不要上 hdu 上看题,上面样例给出的数据不全,但是可以在上面测题

        具体怎么做的懒得讲了,直接上代码。

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <vector>
#include <string>
#include <queue>
#include <ctime>
#include <cstdlib>
#include <stack>
#include <map>
#include <set>
#include <list>

#define INT_INF 0x3fffffff
#define LL_INF 0x3fffffffffffffff
#define EPS 1e-12
#define MOD 1000000007
#define PI 3.14159265358979323846
#define N 100010
#define E 100010

using namespace std;

typedef long long LL;
typedef unsigned long long ULL;
typedef unsigned int Uint;
typedef double DB;

struct data
{
    int st,en;
} T[4*N];
int sorted[N];
int val[40][N];
int to_L[40][N];

int sum[N];

struct node
{
    char name[20];
    int st,en,k;
} op[2*N];

vector<int>y;
map<int,int> ihash;
map<int,int> back;

void make_disc()
{
    sort(y.begin(),y.end());
    y.erase(unique(y.begin(),y.end()),y.end());
    for(int i=0; i<(int)y.size(); i++)
    {
        ihash[y[i]]=i+1;
        back[i+1]=y[i];
    }
}

int get_sum(int *a,int pos)
{
    int temp=0;
    while(pos>0)
    {
        temp+=a[pos];
        pos-=pos&(-pos);
    }
    return temp;
}

int get_k(int *a,int k,int L,int R)
{
    while(L<R)
    {
        int mid=(L+R)>>1;
        if(get_sum(a,mid)>=k) R=mid;
        else L=mid+1;
    }
    return L;
}

void update(int *a,int pos,int k)
{
    while(pos<N)
    {
        a[pos]+=k;
        pos+=pos&(-pos);
    }
}

void build(int v,int st,int en,int deep)
{
    T[v].st=st;
    T[v].en=en;
    if(st==en) return;
    int mid=(st+en)>>1;
    int mid_num=sorted[mid];
    int same=mid-st+1;
    for(int i=st; i<=en; i++)
        if(val[deep][i]<mid_num) same--;
    int L=st , R=mid+1;
    for(int i=st; i<=en; i++)
    {
        if(i==st) to_L[deep][i]=0;
        else to_L[deep][i]=to_L[deep][i-1];
        if(val[deep][i]<mid_num || val[deep][i]==mid_num && same>0)
        {
            val[deep+1][L++]=val[deep][i];
            to_L[deep][i]++;
            if(val[deep][i]==mid_num) same--;
        }
        else val[deep+1][R++]=val[deep][i];
    }
    build(v<<1,st,mid,deep+1);
    build(v<<1|1,mid+1,en,deep+1);
}

int query(int v,int st,int en,int k,int deep)
{
    if(st==en) return val[deep][st];
    int s1 , s2 , b1 , b2;
    if(st==T[v].st) s1=0;
    else s1=to_L[deep][st-1];
    s2=to_L[deep][en]-s1;
    b1=(st-1-T[v].st+1)-s1;
    b2=(en-st+1)-s2;
    int mid=(T[v].st+T[v].en)>>1;
    if(k<=s2) return query(v<<1,T[v].st+s1,T[v].st+s1+s2-1,k,deep+1);
    else return query(v<<1|1,mid+1+b1,mid+1+b1+b2-1,k-s2,deep+1);
}
int main()
{
    int n,ca=0;
    while(scanf("%d",&n)!=EOF)
    {
        y.clear();
        back.clear();
        ihash.clear();
        int tot=0;
        for(int i=1; i<=n; i++)
        {
            scanf("%s",op[i].name);
            if(strcmp(op[i].name,"Insert")==0)
            {
                tot++;
                scanf("%d",&val[0][tot]);
                sorted[tot]=val[0][tot];
                op[i].k=sorted[tot];
                y.push_back(val[0][tot]);
            }
            if(strcmp(op[i].name,"Query_1")==0)
                scanf("%d%d%d",&op[i].st,&op[i].en,&op[i].k);
            if(strcmp(op[i].name,"Query_2")==0)
            {
                scanf("%d",&op[i].k);
                y.push_back(op[i].k);
            }
            if(strcmp(op[i].name,"Query_3")==0)
                scanf("%d",&op[i].k);
        }
        make_disc();
        for(int i=1; i<=tot; i++)
        {
            int tmp=val[0][i];
            val[0][i]=sorted[i]=ihash[tmp];
        }
        sort(sorted+1,sorted+1+tot);
        build(1,1,tot,0);
        memset(sum,0,sizeof(sum));
        LL ans1=0 , ans2=0 , ans3=0;
        for(int i=1; i<=n; i++)
        {
            if(strcmp(op[i].name,"Insert")==0)
                update(sum,ihash[op[i].k],1);
            if(strcmp(op[i].name,"Query_1")==0)
                ans1+=(LL)back[query(1,op[i].st,op[i].en,op[i].k,0)];
            if(strcmp(op[i].name,"Query_2")==0)
                ans2+=(LL)get_sum(sum,ihash[op[i].k]);
            if(strcmp(op[i].name,"Query_3")==0)
                ans3+=(LL)back[get_k(sum,op[i].k,1,N-1)];
        }
        printf("Case %d:\n",++ca);
        printf("%I64d\n%I64d\n%I64d\n",ans1,ans2,ans3);
    }
    return 0;
}



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