Sudoku
出处: http://acm.hnu.cn:8080/online/?action=problem&type=show&id=11203&courseid=0
Sudoku |
Time Limit: 1000ms, Special Time Limit:2500ms, Memory Limit:32768KB |
Total submit users: 10, Accepted users: 10 |
Problem 11203 : Special judge |
Problem description |
A Sudoku puzzle, once solved, is a 9x9 grid of digits organized as a 3x3 grid of smaller 3x3 units. Each of the nine rows must contain every positive digits exactly once, as do each column and also each 3x3 unit. The puzzle is to start from a partially filled 9x9 grid and to fill in the remaining cells using only logic. The puzzle maker usually makes sure that the solution will be unique and that it can be reached using deduction only, without guessing. This number placing game is gaining popularity in the west, and every second newspaper publishes weekly instances of the puzzle. Somewhere at the head of one such newspaper, someone decided that buying individual instances from a puzzle maker would be too expansive, and instead decided to steal puzzles from other newspapers and also to print randomly generated Sudoku-like grids. One week later, his assistant gets stuck with the job of printing the solution to the Sudoku puzzles his boss previously published. Unfortunately, his boss doesn’t have those solutions, the randomly generated problems don’t have any solution, and he doesn’t even remember which is which. In despair, the assistant calls for your help. |
Input |
The first line of the input will contain the number of test cases. Each test case will consist of a 9 by 9 grid of characters, where each character will either be ‘?’ or a digit between 1 and 9 inclusively. |
Output |
For each test case, you must print back the grid to the standard input, replacing each question mark with an appropriate digit to solve the Sudoku. If a test case does not allow any solution, output ”impossible” instead of a completed grid. If a test case do allow a solution, you can assume that the solution will be unique, and that theoretically it could be reached without guessing. Test cases are separated by “---” both in the input and in the output. |
Sample Input |
3 ??4??9??8 ?3??5??1? 7??4??2?? 3??8??1?? ?5?????9? ??6??1??2 ??8??3??1 ?2??4??5? 6??1??7?? --- ??4??9??8 ?3??5??1? 7??4??2?? 3??8??1?? ?5?????9? ??6??1??2 ??8??3??1 62??4??5? 6??1??7?? --- 3?1????76 7??9????? 2?5?3???? ?????64?1 ???2?1??? 1?25????? ????8?9?3 ?????9??4 51????7?8 |
Sample Output |
264319578 839257416 715486239 372894165 451632897 986571342 548763921 127948653 693125784 --- impossible --- 391452876 764918532 285637149 953876421 678241395 142593687 426785913 837169254 519324768 |
1
#include
<
iostream
>
2
3 using namespace std;
4
5 bool x[ 9 ][ 10 ];
6 bool y[ 9 ][ 10 ];
7 bool z[ 9 ][ 10 ];
8 int result[ 9 ][ 9 ];
9 int num = 0 ;
10
11
12 int GetID( int x, int y )
13 {
14 if ( x < 3 && y < 3 )
15 return 0 ;
16 else if ( x < 3 && y >= 3 && y < 6 )
17 return 1 ;
18 else if ( x < 3 && y >= 6 && y < 9 )
19 return 2 ;
20 else if ( x >= 3 && x < 6 && y < 3 )
21 return 3 ;
22 else if ( x >= 3 && x < 6 && y >= 3 && y < 6 )
23 return 4 ;
24 else if ( x >= 3 && x < 6 && y >= 6 && y < 9 )
25 return 5 ;
26 else if ( x >= 6 && x < 9 && y < 3 )
27 return 6 ;
28 else if ( x >= 6 && x < 9 && y >= 3 && y < 6 )
29 return 7 ;
30 else if ( x >= 6 && x < 9 && y >= 6 && y < 9 )
31 return 8 ;
32 }
33
34
35 void Print()
36 {
37 for ( int i = 0 ; i < 9 ; ++ i )
38 {
39 for ( int j = 0 ; j < 9 ; ++ j )
40 printf( " %d " ,result[i][j] );
41
42 if ( i < 8 ) printf( " \n " );
43 }
44 }
45
46
47 bool GetXY( int & xx, int & yy )
48 {
49 for ( int i = 0 ; i < 9 ; i ++ )
50 {
51 for ( int j = 0 ; j < 9 ; j ++ )
52 if ( result[i][j] == 0 )
53 {
54 xx = i;
55 yy = j;
56
57 return true ;
58 }
59 }
60
61 return false ;
62 }
63
64
65 void Try( int xx, int yy )
66 {
67 for ( int i = 1 ; i <= 9 ; ++ i )
68 {
69 if ( ! x[xx][i] && ! y[yy][i] && ! z[ GetID(xx,yy) ][i] )
70 {
71 int a, b;
72
73 result[xx][yy] = i;
74
75 x[xx][i] = true ;
76 y[yy][i] = true ;
77 z[ GetID(xx,yy) ][i] = true ;
78
79 if ( ! GetXY( a, b ) )
80 {
81 Print();
82 num = 1 ;
83 return ;
84 }
85
86 Try( a, b );
87 result[xx][yy] = 0 ;
88
89 x[xx][i] = false ;
90 y[yy][i] = false ;
91 z[ GetID(xx,yy) ][i] = false ;
92 }
93 }
94 }
95
96
97
98 int main()
99 {
100 int n;
101 scanf( " %d " , & n);
102 char aaa[ 10 ];
103
104 for ( int mm = 0 ; mm < n; mm ++ )
105 {
106 char graph[ 9 ][ 10 ];
107 num = 0 ;
108
109 memset( x, false , sizeof (x) );
110 memset( y, false , sizeof (y) );
111 memset( z, false , sizeof (z) );
112 memset( result, 0 , sizeof ( result ) );
113
114 for ( int i = 0 ; i < 9 ; ++ i )
115 scanf( " %s " , graph[i] );
116
117 for ( int i = 0 ; i < 9 ; ++ i )
118 {
119 for ( int j = 0 ; j < 9 ; ++ j )
120 if ( graph[i][j] != ' ? ' )
121 {
122 int t = graph[i][j] - ' 0 ' ;
123 result[i][j] = t;
124
125 x[i][t] = true ;
126 y[j][t] = true ;
127 z[ GetID( i, j ) ][t] = true ;
128 }
129 }
130
131 int x, y;
132
133 GetXY( x, y );
134 Try( x, y );
135
136 if ( mm < n - 1 )
137 {
138 printf( " \n---\n " );
139 scanf( " %s " ,aaa);
140 }
141
142 if ( num == 0 )
143 printf( " impossible " );
144 }
145
146 return 0 ;
147 }
148
149
2
3 using namespace std;
4
5 bool x[ 9 ][ 10 ];
6 bool y[ 9 ][ 10 ];
7 bool z[ 9 ][ 10 ];
8 int result[ 9 ][ 9 ];
9 int num = 0 ;
10
11
12 int GetID( int x, int y )
13 {
14 if ( x < 3 && y < 3 )
15 return 0 ;
16 else if ( x < 3 && y >= 3 && y < 6 )
17 return 1 ;
18 else if ( x < 3 && y >= 6 && y < 9 )
19 return 2 ;
20 else if ( x >= 3 && x < 6 && y < 3 )
21 return 3 ;
22 else if ( x >= 3 && x < 6 && y >= 3 && y < 6 )
23 return 4 ;
24 else if ( x >= 3 && x < 6 && y >= 6 && y < 9 )
25 return 5 ;
26 else if ( x >= 6 && x < 9 && y < 3 )
27 return 6 ;
28 else if ( x >= 6 && x < 9 && y >= 3 && y < 6 )
29 return 7 ;
30 else if ( x >= 6 && x < 9 && y >= 6 && y < 9 )
31 return 8 ;
32 }
33
34
35 void Print()
36 {
37 for ( int i = 0 ; i < 9 ; ++ i )
38 {
39 for ( int j = 0 ; j < 9 ; ++ j )
40 printf( " %d " ,result[i][j] );
41
42 if ( i < 8 ) printf( " \n " );
43 }
44 }
45
46
47 bool GetXY( int & xx, int & yy )
48 {
49 for ( int i = 0 ; i < 9 ; i ++ )
50 {
51 for ( int j = 0 ; j < 9 ; j ++ )
52 if ( result[i][j] == 0 )
53 {
54 xx = i;
55 yy = j;
56
57 return true ;
58 }
59 }
60
61 return false ;
62 }
63
64
65 void Try( int xx, int yy )
66 {
67 for ( int i = 1 ; i <= 9 ; ++ i )
68 {
69 if ( ! x[xx][i] && ! y[yy][i] && ! z[ GetID(xx,yy) ][i] )
70 {
71 int a, b;
72
73 result[xx][yy] = i;
74
75 x[xx][i] = true ;
76 y[yy][i] = true ;
77 z[ GetID(xx,yy) ][i] = true ;
78
79 if ( ! GetXY( a, b ) )
80 {
81 Print();
82 num = 1 ;
83 return ;
84 }
85
86 Try( a, b );
87 result[xx][yy] = 0 ;
88
89 x[xx][i] = false ;
90 y[yy][i] = false ;
91 z[ GetID(xx,yy) ][i] = false ;
92 }
93 }
94 }
95
96
97
98 int main()
99 {
100 int n;
101 scanf( " %d " , & n);
102 char aaa[ 10 ];
103
104 for ( int mm = 0 ; mm < n; mm ++ )
105 {
106 char graph[ 9 ][ 10 ];
107 num = 0 ;
108
109 memset( x, false , sizeof (x) );
110 memset( y, false , sizeof (y) );
111 memset( z, false , sizeof (z) );
112 memset( result, 0 , sizeof ( result ) );
113
114 for ( int i = 0 ; i < 9 ; ++ i )
115 scanf( " %s " , graph[i] );
116
117 for ( int i = 0 ; i < 9 ; ++ i )
118 {
119 for ( int j = 0 ; j < 9 ; ++ j )
120 if ( graph[i][j] != ' ? ' )
121 {
122 int t = graph[i][j] - ' 0 ' ;
123 result[i][j] = t;
124
125 x[i][t] = true ;
126 y[j][t] = true ;
127 z[ GetID( i, j ) ][t] = true ;
128 }
129 }
130
131 int x, y;
132
133 GetXY( x, y );
134 Try( x, y );
135
136 if ( mm < n - 1 )
137 {
138 printf( " \n---\n " );
139 scanf( " %s " ,aaa);
140 }
141
142 if ( num == 0 )
143 printf( " impossible " );
144 }
145
146 return 0 ;
147 }
148
149