CQC与SRSS
/solu
antype,modal
MODOPT,LANB,20,0.1,0, ,OFF
DMPRAT,0.02
solve
finish
/solu
antype,spectr
spopt,sprs,20,yes
svtype,2
sed,,1
freq,0.167,0.182,0.200,0.222,0.250,0.286,0.333,0.400,0.500
freq,0.556,0.625,0.714,0.833,1.000,1.250,1.667,2.500,4.000
freq, 10.000,10000.000
sv,0.02,0.150,0.159,0.168,0.178,0.187,0.196,0.206,0.215,0.224
sv,0.02,0.248,0.277,0.315,0.364,0.433,0.535,0.704,1.034,1.034
sv,0.02, 1.034, 0.353
solve
finish
/solu
antype,modal
expass,on
mxpand,20,,,yes
solve
finish
/solu
antype,spectr
DMPRAT,0.02
cqc,,disp
solve
finish
按理论上说的是当结构的频率比较稀疏的时候考虑用SRSS,当比较密集的时候需要考虑振型相关,所以要用CQC.我求的是一个钢塔,频率很密集,所以希望用CQC计算,我也用你给的命令流计算过,但是结果却和SRSS一样,所以我才怀疑自己CQC有问题,因为SRSS方法的例题比较普遍我见过很多应该不会错的,现在我把命令流都给出来,希望楼上的比较下,确保您给的命令流正确,并希望能指点下为什么不同的方法的出的结果却一样
我用的SRSS法命令流:
/SOLU
NSEL,S,LOC,Z,0
D,ALL,,,,,,ALL
ALLSEL,ALL
ANTYPE,MODAL
MODOPT,subsp,30
SOLVE
FINISH
/SOLU
ANTYPE,SPECTR
SPOPT,SPRS,30,YES
SVTYP,2
SED,1
FREQ,0.20,0.25,0.40,0.50,0.53,0.59,0.71,0.83,1.00
FREQ,1.11,1.25,1.67,2.50,5.00,5.56,8.33,14.29,20.00
FREQ,33.33,100
SV,0.02,0.24,0.24,0.24,0.24,0.34,0.54,0.84,1.04,1.24,
SV,0.02,1.34,1.44,1.44,1.44,1.44,1.312,0.928,0.608,0.48,
SV,0.02,0.48,0.48,
SOLVE
FINISH
/SOLU
ANTYPE,MODAL
EXPASS,ON
MXPAND,30,,,YES,0
SOLVE
FINISH
/SOLU
ANTYPE,SPECTR
SRSS,0,disp
SOLVE
FINISH
我用的CQC法命令流(和您给的一样):
/SOLU
NSEL,S,LOC,Z,0
D,ALL,,,,,,ALL
ALLSEL,ALL
ANTYPE,MODAL
MODOPT,subsp,30
DMPRAT,0.02
SOLVE
FINISH
/SOLU
ANTYPE,SPECTR
SPOPT,SPRS,30,YES
SVTYP,2
SED,1
FREQ,0.20,0.25,0.40,0.50,0.53,0.59,0.71,0.83,1.00
FREQ,1.11,1.25,1.67,2.50,5.00,5.56,8.33,14.29,20.00
FREQ,33.33,100
SV,0.02,0.24,0.24,0.24,0.24,0.34,0.54,0.84,1.04,1.24,
SV,0.02,1.34,1.44,1.44,1.44,1.44,1.312,0.928,0.608,0.48,
SV,0.02,0.48,0.48,
SOLVE
FINISH
/SOLU
ANTYPE,MODAL
EXPASS,ON
MXPAND,30,,,YES,0
SOLVE
FINISH
/SOLU
ANTYPE,SPECTR
DMPRAT,0.02
CQC,0,disp
SOLVE
FINISH
srss方法：
/SOLU
ANTYPE,SPECTR
DMPRAT,0.02
SRSS,0,disp
SOLVE
FINISH
cqc方法：
/SOLU
ANTYPE,SPECTR
DMPRAT,0.02
cqc,0,disp
SOLVE
FINISH
引自：http://www.baisi.net/thread-1163161-1-1.html