在一张图片上,打印8*10的数字矩阵,实现如下:
//格子的尺寸 $grid_font_size = 18; //字体大小 $grid_font_color = "#000"; //字体颜色 $grid_width = 36; //格子的宽度 $grid_height = 24; //格子的高度 $grid_origin_x = 15; //左上角的数字的起始横坐标 $grid_origin_y = 98; //左上角的数字的起始纵坐标 #原图 $image = new Imagick('background.jpg'); #写入密保卡数据 $tmp_grid_origin_x = $grid_origin_x; $tmp_grid_origin_y = $grid_origin_y; foreach ($pData as $k => $v){ foreach ($v as $k_grid_data => $v_grid_data){ $tmp_grid_origin_x += $grid_width; $draw = new ImagickDraw(); $draw->setFillColor($grid_font_color); $draw->setFontSize($grid_font_size); $draw->annotation($tmp_grid_origin_x, $tmp_grid_origin_y, $v_grid_data); $image->drawImage($draw); } $tmp_grid_origin_x = $grid_origin_x; $tmp_grid_origin_y += $grid_height; } $image->writeImage($ks_ImageSrcPath. $pSN. '.jpg'); #释放资源 $image->destroy(); $draw->destroy();
这样做的后果是,在每次循环的时候,都要实例化一个ImagickDraw,并执行drawImage方法,非常占用CPU资源。
可以从以下两点优化:
1. 不必每次都执行new操作,一个就够了;
2. 不必每次都执行drawImage方法,一次就够了。也就是说,annotation方法好像具有“附加”的意味,不用担心后来的覆盖掉之前的;
代码如下:
$draw = new ImagickDraw(); $draw->setFillColor($grid_font_color); $draw->setFontSize($grid_font_size); foreach ($pData as $k => $v){ foreach ($v as $k_grid_data => $v_grid_data){ $tmp_grid_origin_x += $grid_width; $draw->annotation($tmp_grid_origin_x, $tmp_grid_origin_y, $v_grid_data); } $tmp_grid_origin_x = $grid_origin_x; $tmp_grid_origin_y += $grid_height; } $image->drawImage($draw);
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2009-9-1 更新
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换种思路!
把8*10的数字矩阵看做“由80个数字、每10个换一行、每2个有一定间距”的字符串,哈!就可以从“调用80次annotation方法”减少到“调用1次”。
只是,我们不得不重新修改背景图的尺寸、“该字符串”在背景图的起始坐标等。
示例代码如下:
$numX = 0; $str = ''; $tData = explode(",", $pData); foreach ($tData as $d) { if (($numX++)%10 == 0) { $str .= "\n\n"; } $str .= $d . " "; } $draw->setFillColor($grid_font_color); $draw->setFontSize($grid_font_size); $draw->annotation($grid_origin_x, $grid_origin_y, $str); $image->drawImage($draw);