大数运算,用了模
#include
<
stdio.h
>
#include
<
stdlib.h
>
#include
<
string.h
>
const
int
OneNode
=
1000000
;
//
??????????????OneNode
const
int
NodeLen
=
6
;
//
????????NodeLen??????OneNode????????????,????????????????????????!!!
const
int
NumMax
=
1005
;
//
????????????????????????NumMax*6
struct BigNum

{
unsigned num[NumMax] ;//???? ?? ????????
unsigned numlen ;

void set(unsigned sm=0)
{ num[0] = sm ; numlen = 1; }//sm<OneNode
void set(char *string , int strlen)

{
numlen = (strlen-1) / NodeLen + 1 ;
memset (num , 0 , sizeof(unsigned)*numlen );
int temp , i ;
for( i=strlen-1 ; i>=0 ; i-- )

{
temp = i / NodeLen ;
num[temp] = num[temp]*10 + string[strlen-1-i]-'0' ;
}
}
void print()

{
printf("%d",num[numlen-1]);
int i = numlen-1;
while( i )

{
i--;
printf("%06d",num[i]);
}
printf("\n");
}
}
;

int
Cmp(BigNum
&
a,BigNum
&
b)
//
a>b --> 1 , > --> -1 ,== --> 0

{
if( a.numlen>b.numlen )
return 1;
if( a.numlen<b.numlen )
return -1;
int len = a.numlen ;
while(len)

{
len --;
if(a.num[len]>b.num[len])return 1;
if(a.num[len]<b.num[len])return -1;
}
return 0;
}

void
Cpy(BigNum
&
a , BigNum
&
b)
//
b-->a

{
a.numlen=b.numlen;
memcpy(a.num,b.num,sizeof(unsigned)*b.numlen);
}

void
Div(BigNum
&
a,
int
b,
int
&
l)
//
a/=b -> ????l

{
int carry=0;
int i;
for(i=a.numlen-1;i>=0;i--)

{
a.num[i]+=carry*OneNode;
carry=a.num[i]%b;
a.num[i]/=b;
}
if(a.numlen>1&&!a.num[a.numlen-1])a.numlen--;
l=carry;
}


int
dig[
9
]
=
{1,2,3,4,5,6,7,8,9}
;

BigNum a, b, c;

char
input[
1005
];

int
ans[
1005
];

int
main()

{

int i;
int p;
int l;
int flag;
while (1)

{
scanf("%s", &input);
if (input[0]=='-')

{
break;
}
a.set(input, strlen(input));
c.set("10", 2);
if (Cmp(a, c)<0)

{
printf("1");
a.print();
}
else

{
p = -1;
flag = 0;
while (Cmp(a, c)>=0)

{
for (i=8; i>0; i--)

{
Cpy(b, a);
Div(b, dig[i], l);
if (l==0)

{
flag = 1;
ans[++p] = dig[i];
Cpy(a, b);
break;
}
}
if (!flag)

{
p = -1;
break;
}
else

{
flag = 0;
}
}
if (Cmp(a, c)<0)

{
for (i=8; i>=0; i--)

{
Cpy(b, a);
Div(b, dig[i], l);
if (l==0)

{
ans[++p] = dig[i];
break;
}
}
}
if (p!=-1)

{
for (i=p; i>=0; i--)

{
printf("%d", ans[i]);
}
printf("\n");
}
else

{
printf("There is no such number.\n");
}
}
}
return 0;
}

版






















































































































































































































